Fire onmouseover event when element is disabled
Asked Answered
E

7

33

I have some controls that I need to disable when users don't have edit privileges, but are sometimes not wide enough to show the entire text of the selected option element. In which case I've added a tool tip with ASP.NET and the following code

ddl.Attributes.Add("onmouseover", "this.title=this.options[this.selectedIndex].title")

This works when the control is enabled, but doesn't work when it is disabled.

The following alert will not fire when a mouse is over the select element:

<select disabled="disabled" onmouseover="alert('hi');">
    <option>Disabled</option>
</select>

See this fiddle.

Q: Can I fire the onmouseover event for controls that are disabled?

Espinosa answered 7/8, 2013 at 21:14 Comment(1)
Disabled button counter in Fiddle is firing for me Chrome 93 and Firefox 91. Here's with alert (works in Firefox 91 but not Chrome 93): jsfiddle.net/7hqL2f1a/1Subvention
P
56

Disabled elements do not fire events, e.g. users cannot hover or click them to trigger a popover (or tooltip). You can however wrap the disabled element with a DIV and listen to the event fired on that element instead.

Pirbhai answered 7/8, 2013 at 21:16 Comment(5)
could you please demonstrateExtroversion
It appears that if the disabled element takes up 100% of the div, even this won't workSilvio
Do this and use "mouseenter" instead of "mouseover" and it will work.Janitress
Trouble is you lose the HTML 'not-allowed' cursor snf the pointer cursor once the button is enabledBondon
As a comment: The W3C HTML5 spec states, that click events are disabled. Vendors treat other events differently. Firefox, for example, seems to trigger some events like mouseEnter.Milstone
E
10

Update: Please see nathan william's comment for some serious limitations to this approach. I've updated the fiddle to illustrate the problem areas more clearly.


Expanding on what @Diodeus said, you can use jQuery to automatically create the div container for you and wrap it around any disabled elements.

  1. Use the :disabled selector to find all disabled elements.
  2. Then call the .wrap() method with a function callback
  3. You can use this to refer to the current element in the set.
  4. Then use .attr() method to get the onmouseover value from the parent element and apply the same value to the new div.
$(':disabled').wrap(function() {
    return '<div onmouseover="' + $(this).attr('onmouseover') + '" />';
});

Demo in jsFiddle

Espinosa answered 7/8, 2013 at 22:12 Comment(1)
Should be noted that there's still a dead zone over the disabled element itself. If the wrapper has block style, then the effect will be erratic; if it has inline style, then the mouse may never transit any part of it to trigger the effect. A z-index overlay element would behave more consistently, but would require inserting a sibling element with absolute positioning relative to the wrapper.Juggle
C
8

I know this is an old post, but hopefully this answer will clarify how @Diodeus answer can be implemented!

Disabled elements do not fire events, e.g. users cannot hover or click them to trigger a popover (or tooltip). As a workaround, you can however wrap a <DIV> or <span> around the disabled element and listen to the event fired on that element instead.

NOTE! Using onmouseover and onmouseout in the wrapper <DIV> will not work as expected in Chrome (v69). But will however work in IE. Which is why I recommend users to use onmouseenter and onmouseleave instead, which is working great both in IE and in Chrome.

   <select disabled="disabled" onmouseover="alert('hi');">
    <option>Disabled</option>
  </select>

  <div onmouseenter="alert('hi');">
    <select disabled="disabled" onmouseover="alert('hi');">
      <option>Disabled with wrapper</option>
    </select>
  </div>

I've put together a JS fiddle with some examples here: http://jsfiddle.net/Dr4co/tg6134ju/

Cuba answered 26/10, 2018 at 11:55 Comment(1)
Thanks for adding this answer. In the latest version of Chrome, onmouseenter did work as a replacement for onmouseover with disabled children but onmouseleave did not work as a replacement for onmouseout. Due to the onmouseleave issue, I still had to add a ::before pseudo-element to the wrapper positioned on top of the disabled child in order to get onmouseover or onmouseleave to fire.Dillion
O
5

For modern browsers, you can use the pointerenter and pointerleave events instead. These fire even if the HTML Element is disabled.

Outstrip answered 15/5, 2023 at 14:7 Comment(2)
This is right answer for disabled element to fire the event.Quarters
True! But before the year 2018, both Safari and Firefox did not have support for pointerenter and pointerleave. Back then it was better to use mouseenter or mouseleave =)Cuba
T
2

I know this is an old post, but in chrome you can set css property pointer-events to all and it should allow for events. I haven't checked in other browsers.

button[disabled] {
  pointer-events: all;
}

Edit:

Actually I think setting the property to auto is sufficient. As @KyleMit commented, support it's pretty good.

I just used this in project where I needed to disable an button until some validation rules where met, but I also needed to trigger the validation on hover over the button. So adding the pointer-events did the trick. I think it's the easiest way get over the problem stated in the OP.

Tolly answered 30/12, 2016 at 17:34 Comment(2)
This does not work at all for me, whether I use all or auto.Epizoic
I needed to include the !important property, then it worked. Like so: pointer-events: all !importantFasces
V
1

Why can't you add a title on the target element? title looks like the same as tool tip. And title works on disabled elements.

when you set the value of your select, also set title:

element.value=value;
element.title = element.options[element.selectedIndex].text;
Viridis answered 19/1, 2016 at 14:28 Comment(2)
Justin, that's one way to go (which I think I might have ultimately gone with) - the problem is that there are a lot of selects that are conditionally disabled. I needed the mouseover so the title would update appropriately when it wasn't disabled. But seeding it with the correct title to start covers both cases.Espinosa
To Kylemit, then you can add condition for it: if(element.classList.contains("addTitle15")){ // add titleViridis
P
-1

there are two solutions for this

<Tooltip title="Tooltip" placement="bottom">
          <div>
            <IconButton disabled>
              <Done />
            </IconButton>
          </div>
        </Tooltip>

or this one if you dont want miss the view

<Tooltip title="Tooltip" placement="bottom">
  <IconButton component="div" disabled>
    <Done />
  </IconButton>
</Tooltip>

reference

Pavement answered 23/7, 2019 at 21:37 Comment(0)

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