How to tap on a specific point using Xcode UITests

Question

I want to use Xcode UI tests with the Fastlane Snapshot to make screenshots of the Cordova app. Basically, as my entire app is just a web view, all the Xcode UI test helper methods become irrelevant, and I just want to tap on specific points, e.g. tap(x: 10, y: 10) should produce a tap at the point {10px; 10px}.

That's probably very simple, but I can't figure out how to do it.

Thanks.

Dreeda

Answer 1

You can tap a specific point with the XCUICoordinate API. Unfortunately you can't just say "tap 10,10" referencing a pixel coordinate. You will need to create the coordinate with a relative offset to an actual view.

We can use the mentioned web view to interact with the relative coordinate.

let app = XCUIApplication()
let webView = app.webViews.element
let coordinate = webView.coordinateWithNormalizedOffset(CGVector(dx: 10, dy: 10))
coordinate.tap()

---

Side note, but have you tried interacting with the web view directly? I've had a lot of success using app.links["Link title"].tap() or app.staticTexts["A different link title"].tap(). Here's a demo app I put together demonstrating interacting with a web view.

---

Update: As Michal W. pointed out in the comments, you can now tap a coordinate directly, without worrying about normalizing the offset.

let normalized = webView.coordinate(withNormalizedOffset: CGVector(dx: 0, dy: 0))
let coordinate = normalized.withOffset(CGVector(dx: 10, dy: 10))
coordinate.tap()

Notice that I pass 0,0 to the normalized vector and then the actual point, 10,10, to the second call.

Polarization

I'm not sure that is correct as I needed to add 'coordinateWithOffset' to perform x/y tap: let cooridnate = self.coordinateWithNormalizedOffset(CGVector(dx: 0, dy: 0)).coordinateWithOffset(CGVector(dx: position.x, dy: position.y)) cooridnate.tap() forums.developer.apple.com/thread/13373 – Albin

Good idea! Thanks @MichałW. I noted the comment in an update to the answer as it was already accepted. – Polarization

Another small optimization is to use CGVector.zero instead of CGVector(dx: 0, dy: 0). – Inappreciable

Answer 2

@joe To go a little further off of Joe Masilotti's approach I put mine in an extensionand gave prepositional phrases to the global and local params.

func tapCoordinate(at xCoordinate: Double, and yCoordinate: Double) {
    let normalized = app.coordinate(withNormalizedOffset: CGVector(dx: 0, dy: 0))
    let coordinate = normalized.withOffset(CGVector(dx: xCoordinate, dy: yCoordinate))
    coordinate.tap()
}

By giving the global an identifiable name I can easily understand the instance for example:

tapCoordinate(at x: 100, and y: 200)

Tejeda

Worked for me in Swift 3! – Knesset

This doesn't compile in Swift 3 – Serafina

I had to run it as tapCoordinate(at:100, and:200) and it worked perfectly! Unlike the exact example you used which didn't compile in Swift 5 – Sequestered

Answer 3

I found Laser's answer to work fine with Xcode 11, but made a few tweaks to easily integrate it into my testing.

extension XCUIApplication {
    func tapCoordinate(at point: CGPoint) {
        let normalized = coordinate(withNormalizedOffset: .zero)
        let offset = CGVector(dx: point.x, dy: point.y)
        let coordinate = normalized.withOffset(offset)
        coordinate.tap()
    }
}

Now, when I need to tap on a given location, I just provide a CGPoint and call this against my XCUIApplication like so:

let point = CGPoint(x: xCoord, y: yCoord)
app.tapCoordinate(at: point)

Interfaith

Answer 4

<something>.coordinate(withNormalizedOffset: CGVector.zero).withOffset(CGVector(dx:10,dy:60)).tap()

Pass .zero to the normalized vector and then the actual point (10,60)

Buine

This is great for Swift 4 :) – Acord