Yes, that will remove all registrations where the observer is self
. It's documented in the NSNotificationCenter Class Reference:
The following example illustrates how to unregister someObserver
for all notifications for which it had previously registered:
[[NSNotificationCenter defaultCenter] removeObserver:someObserver];
Note that in theory (but not, as far as I know, in practice as of iOS 7.0), UIViewController
could have its own registrations that it doesn't want removed in viewWillDisappear:
. It's unlikely to register for any of the notifications in the public API using addObserver:selector:name:object:
, because that would preclude you registering for them in your UIViewController
subclass, but it could certainly register for non-public notifications now or in a future version.
A safe way to deregister is to send removeObserver:name:object:
once for each registration:
- (void)deregisterForKeyboardNotifications {
NSNotificationCenter *center = [NSNotificationCenter defaultCenter];
[center removeObserver:self name:UIKeyboardWillShowNotification object:nil];
[center removeObserver:self name:UIKeyboardWillHideNotification object:nil];
[center removeObserver:self name:UIApplicationWillResignActiveNotification object:nil];
}
- (void)viewWillDisappear:(BOOL)animated {
[super viewWillDisappear:animated];
[self deregisterForKeyboardNotifications];
}
- (void)dealloc {
[self deregisterForKeyboardNotifications];
}
Another way is to use addObserverForName:object:queue:usingBlock:
to register (instead of addObserver:selector:name:object:
). This returns a new observer object reference for each registration. You have to save these away (perhaps in an NSArray
instance variable if you don't want to create individual instance variables). Then you pass each one to removeObserver:
to deregister its notification. Example:
@implementation MyViewController {
NSMutableArray *observers;
}
- (void)registerForKeyboardNotifications {
NSNotificationCenter *center = [NSNotificationCenter defaultCenter];
NSOperationQueue *queue = [NSOperationQueue mainQueue];
__weak MyViewController *me = self;
observers = [NSMutableArray array];
[observers addObject:[center addObserverForName:UIKeyboardWillShowNotification
object:nil queue:queue usingBlock:^(NSNotification *note) {
[me keyboardWillShow:note];
}]];
[observers addObject:[center addObserverForName:UIKeyboardWillHideNotification
object:nil queue:queue usingBlock:^(NSNotification *note) {
[me keyboardWillHide:note];
}]];
[observers addObject:[center addObserverForName:UIApplicationWillResignActiveNotification
object:nil queue:queue usingBlock:^(NSNotification *note) {
[me applicationWillResignActive:note];
}]];
}
- (void)deregisterForKeyboardNotifications {
for (id observer in observers) {
[[NSNotificationCenter defaultCenter] removeObserver:observer];
}
observers = nil;
}
- (void)viewWillDisappear:(BOOL)animated {
[super viewWillDisappear:animated];
[self deregisterForKeyboardNotifications];
}
- (void)dealloc {
[self deregisterForKeyboardNotifications];
}
Since every observer returned by addObserverForName:object:queue:usingBlock:
is a new object that has only one registration, each call to removeObserver:
is guaranteed to only remove that observer's one registration.
Update for iOS 9 / macOS 10.11 and later
As of iOS 9 and macOS 10.11, NSNotificationCenter
automatically deregisters an observer if the observer is deallocated. It is no longer necessary to deregister yourself manually in your dealloc
method (or deinit
in Swift) if your deployment target is iOS 9 or later or macOS 10.11 or later.