Java - Check if JTextField is empty or not
Asked Answered
E

13

34

So I got know this is a popular question and already found the solution. But when I try this it doesn't work properly.

My JTextField is empty and the button isn't enabled. When I write something in my textfield the button doesn't get enabled.

So my program should check this field every second whether it's empty or not. As soon as someone writes something into the textfield the button should be enabled.^^

loginbt = new JButton("Login");
    loginbt.addActionListener(new loginHandler());
    add(loginbt);

    if(name.getText().equals("")) {
        loginbt.setEnabled(false);
    }else {
        loginbt.setEnabled(true);
    }
Elevate answered 16/6, 2013 at 10:43 Comment(2)
BTW, I'll use loginbt.setEnabled(name.getText().length()!=0);Sather
@Sather loginbt.setEnabled(name.getText().isEmpty());Aime
B
39

For that you need to add change listener (a DocumentListener which reacts for change in the text) for your JTextField, and within actionPerformed(), you need to update the loginButton to enabled/disabled depending on the whether the JTextfield is empty or not.

Below is what I found from this thread.

yourJTextField.getDocument().addDocumentListener(new DocumentListener() {
  public void changedUpdate(DocumentEvent e) {
    changed();
  }
  public void removeUpdate(DocumentEvent e) {
    changed();
  }
  public void insertUpdate(DocumentEvent e) {
    changed();
  }

  public void changed() {
     if (yourJTextField.getText().equals("")){
       loginButton.setEnabled(false);
     }
     else {
       loginButton.setEnabled(true);
    }

  }
});
Betterment answered 16/6, 2013 at 10:47 Comment(3)
I wanted to ask whether the procedure changes if the button were to depend on more than 1 text field. Would I use the same logic to define the action or is there some other way with less code? Thanks for your time!!Lactoscope
Then you create one DocumentListener implementation which handles that button and add them as listeners to all the textboxes?Betterment
yes..thanks..forgot basic stuff: how to write document listenerLactoscope
N
22

The following will return true if the JTextField name does not contain text:

name.getText().isEmpty();

Note answered 1/2, 2015 at 8:24 Comment(0)
V
4

What you need is something called Document Listener. See How to Write a Document Listener.

Venerable answered 16/6, 2013 at 10:48 Comment(0)
M
4

To Check JTextFiled is empty or not condition:

if( (billnotf.getText().length()==0)||(billtabtf.getText().length()==0))
Minda answered 1/3, 2014 at 20:23 Comment(1)
Nice. I like this.Beanie
F
3

Well, the code that renders the button enabled/disabled:

if(name.getText().equals("")) {
    loginbt.setEnabled(false);
}else {
    loginbt.setEnabled(true);
}

must be written in javax.swing.event.ChangeListener and attached to the field (see here). A change in field's value should trigger the listener to reevaluate the object state. What did you expect?

Farrow answered 16/6, 2013 at 10:48 Comment(0)
B
2

use the following code :

if(name.getText().equals(""))
{
loginbt.disable();
}
Binetta answered 10/11, 2014 at 3:10 Comment(0)
D
2

you can use isEmpty() or isBlank() methods regarding what you need.


Returns true if, and only if, length() is 0.

this.name.getText().isEmpty();

Returns true if the string is empty or contains only white space codepoints, otherwise false

this.name.getText().isBlank();
Dairyman answered 29/10, 2019 at 19:20 Comment(1)
Note that isBlank() works since Java 11.Washboard
S
0

Try this

if(name.getText() != null && name.getText().equals(""))
{
        loginbt.setEnabled(false);
}
else
{
        loginbt.setEnabled(true);
}
Seto answered 16/6, 2013 at 11:5 Comment(0)
D
0
if(name.getText().hashCode() != 0){
    JOptionPane.showMessageDialog(null, "not empty");
}
else{
    JOptionPane.showMessageDialog(null, "empty");
}
Danettedaney answered 9/4, 2015 at 19:42 Comment(1)
Cold you please explain why you think that this is a solution?Defect
A
0

Try this one and change booleans statements around.

String text = name.getText(); 
if(!text.isEmpty()) {
    loginbt.setEnabled(true);
}else {
    loginbt.setEnabled(false);
}

In my action method it worked fine.

public void actionPerformed(ActionEvent e){
    String inputText = e.getActionCommand();
    String itext = text1.getText();
    if(inputText.equals("Submit") && !itext.isEmpty()){
        label1.setText(text1.getText());
        text1.setText("");
    }
}
Avisavitaminosis answered 30/5, 2022 at 8:56 Comment(0)
R
0

You can use

`loginbt = new JButton("Login"); loginbt.addActionListener(new loginHandler()); add(loginbt);

if(String.valueOf(name.getText()).isEmpty() {
    loginbt.setEnabled(false);
}else {
    loginbt.setEnabled(true);
}

`

Rickrickard answered 22/11, 2023 at 15:30 Comment(1)
Your answer doesn't add much to the existing ones. String.valueOf is not needed here since getText already returns a String object.Calcimine
A
-1

Try with keyListener in your textfield

jTextField.addKeyListener(new KeyListener() {

        @Override
        public void keyTyped(KeyEvent e) {
        }

        @Override
        public void keyPressed(KeyEvent e) {
            if (text.getText().length() >= 1) {
                button.setEnabled(true);
            } else {
                button.setEnabled(false);
            }
        }

        @Override
        public void keyReleased(KeyEvent e) {
        }

    });
Alphonsealphonsine answered 16/6, 2013 at 10:58 Comment(2)
-1 A DocumentListener is the preferred approach. There is rarely a reason to use a KeyListener. That is old design when using AWT. Also the code would not work anyway because no text has been added to the Document when the keyPressed event is generated, so the length will still be 0 when the first event is fired.Gavette
Thanks for the correction,i will see the DocumentListener in the futureAlphonsealphonsine
A
-1
private void jButton4ActionPerformed(java.awt.event.ActionEvent evt) {                                         
    // Submit Button        

    String Fname = jTextField1.getText();
    String Lname = jTextField2.getText();
    String Desig = jTextField3.getText();
    String Nic = jTextField4.getText();
    String Phone = jTextField5.getText();
    String Add = jTextArea1.getText();
    String Dob = jTextField6.getText();
    // String Gender;
    // Image

    if (Fname.hashCode() == 0 || Lname.hashCode() == 0 || Desig.hashCode() == 0 || Nic.hashCode() == 0 || Phone.hashCode() == 0 || Add.hashCode() == 0)
    {
        JOptionPane.showMessageDialog(null, "Some fields are empty!");
    }
    else
    {
        JOptionPane.showMessageDialog(null, "OK");
    }
}
Aletheaalethia answered 21/12, 2019 at 12:17 Comment(2)
Hi @HarinduLakshan, please consider adding more information to improve the quality of the answer.Instauration
This answer has multiple issues. It doesn't clearly address the question, the variable names don't adhere to Java conventions, and it uses hashCode() rather than isEmpty() to check for missing values. It also contains unnecessary comments.Thruster

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