How to findAll in mongoosejs?

Question

My code is like that:

SiteModel.find(
    {},
    function(docs) {
        next(null, { data: docs });
    }
);

but it never returns anything... but if I specify something in the {} then there is one record. so, how to findall?

Affectional

Answer 1

Try this code to debug:

SiteModel.find({}, function(err, docs) {
    if (!err) { 
        console.log(docs);
        process.exit();
    }
    else {
        throw err;
    }
});

Keifer

Any ideas why this wouldn't work when I run this from the terminal like node filename.js? – Extraterritorial

Note you don't even need the empty curly braces if you are using a then-catch like paradigm. – Charmine

Answer 2

The 2017 Node 8.5 way

try {
  const results = await SiteModel.find({});
  console.log(results);
} catch (err) {
  throw err;
}

Ona

Answer 3

From the documentation:

let result = SiteModel.find({}, function (err, docs) {});

or using async await you can do like this also:

let result = await SiteModel.find({});

Diddle

Answer 4

const result = await SiteModel.find() - Without the {} in the .find() function works as well.

Netti

Answer 5

exports.getAllUsers = (req, res) => { userSchema .find() .then((data) => res.status(200).json({ status: "success", results: data.length, data: { data, }, }) ) .catch((err) => res.status(404).json({ status: "error", message: "Not records found", }) ); };

Transvestite

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