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python flask display image on a html page [duplicate]
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I am trying to pass a filename of an image and render it on a template, Although I am passing the actual name through it does not display on the page

@app.route('/', methods=['GET','POST'])
@app.route('/start', methods=['GET','POST'])
def start():
person_to_show = 'tim'
profilepic_filename = os.path.join(people_dir, person_to_show, "img.jpg")
return render_template('start.html',profilepic_filename  =profilepic_filename )

For example: profilepic_filename = /data/tim/img.jpg I have tried

{{profilepic_filename}}
<img src="{{ url_for('data', filename='tim/img.jpg') }}"></img>

And I have also tried

<img src="{{profilepic_filename}}"></img>

Neither of which worked

Latoyialatreece answered 17/10, 2017 at 8:13 Comment(0)
A
79

I have created people_photo in static folder and placed an image named shovon.jpg. From the application.py I passed the image as variable to template and showed it using img tag in the template.

In application.py:

from flask import Flask, render_template
import os

PEOPLE_FOLDER = os.path.join('static', 'people_photo')

app = Flask(__name__)
app.config['UPLOAD_FOLDER'] = PEOPLE_FOLDER

@app.route('/')
@app.route('/index')
def show_index():
    full_filename = os.path.join(app.config['UPLOAD_FOLDER'], 'shovon.jpg')
    return render_template("index.html", user_image = full_filename)

In index.html:

<!DOCTYPE html>
<html>
<head>
    <title>Index</title>
</head>
<body>
    <img src="{{ user_image }}" alt="User Image">
</body>
</html>

Output:

enter image description here

Archduchy answered 17/10, 2017 at 16:5 Comment(7)
Did anyone else have trouble getting this to work? pycharm tells me Process finished with exit code 0 but localhost:5000 isn't showing any images – Disuse
@frank, localhost:5000is available as long as the program remains in running state. There might be something that stopped the program and you got Process finished with exit code 0. – Archduchy
How can we display an image from S3 links? Any help would be appreciated. – Pettifer
@vinitkantrod, it is not in the scope of this question. It will be better if you can create a new question regarding S3 bucket image usage in Flask. I think future readers will be benefited. – Archduchy
is there a way to use a sub-folder instead of the static folder and pass through the local ressource error? – Ewan
add app.run(host='0.0.0.0') to end of the file to start this as a server – Leclerc
Somehow the method in this answer by @Archduchy did not work for me but I followed the method in this other blog which worked for me: kanchanardj.medium.com/… – Soapwort

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