Equation parsing in Python
Asked Answered
Q

7

44

How can I (easily) take a string such as "sin(x)*x^2" which might be entered by a user at runtime and produce a Python function that could be evaluated for any value of x?

Quipu answered 27/2, 2009 at 10:42 Comment(0)
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53

Python's own internal compiler can parse this, if you use Python notation.

If your change the notation slightly, you'll be happier.

import compiler
eq= "sin(x)*x**2"
ast= compiler.parse( eq )

You get an abstract syntax tree that you can work with.

Ozonosphere answered 27/2, 2009 at 11:12 Comment(10)
Can you add a sample code on how to use the derived function?Modernistic
@Don: You don't need to use the syntax tree. Use the original function. eval("sin(x)*x**2") after setting x and using from math import *.Ozonosphere
eval() works, but the answer doesn't actually solve the problem :(Ferdinana
@JamesBroadhead: How does eval() not solve the problem? Can you explain what's missing? "evaluated for any value" seems to be covered by eval. What's missing?Ozonosphere
It's not in the Answer ;). Ideally, you'd edit the answer to point that out (and the various problems associated with compiler.parse() and eval() that others have mentioned.Ferdinana
"various problems associated with compiler.parse() and eval() that others have mentioned" seems redundant. Also. I asked the wrong question about your comment. "the answer doesn't actually solve the problem"? What more should be there -- outside of eval() which I specifically tried to avoid putting in the answer.Ozonosphere
import compiler doesn't work with Python 3.3 Could you please update your answer + tags to make sure the reader know which one it is about. It's a good question and should have the relevant tags covered.Amphimixis
@hagubear the replacement of the compiler module for python 3 is described here: #909592Bijugate
Do NOT use eval with data coming from an external source (e.g. web) as that is an easy attack vector.Lorentz
The compiler module is deprecated since Python 2.6. This answer is obsoleteAcceptant
M
34

EDIT parser is deprecated in Python 3.9: https://docs.python.org/3/whatsnew/3.9.html#new-parser

You can use Python parser:

import parser
from math import sin

formula = "sin(x)*x**2"
code = parser.expr(formula).compile()
x = 10
print(eval(code))

It performs better than pure eval and, of course, avoids code injection!

Modernistic answered 9/5, 2011 at 12:23 Comment(5)
One important thing to note is that using pure eval() on user input can be very dangerous.Tableland
@devxeq I mean that it won't accept such things as formula = "os.system('format C:')" :)Modernistic
@Modernistic Fair enough. :)Cayuga
I'm not sure how this is any better than using eval on the string itself. It will still happily execute all code, not just formulas. Including bad things like os.system calls. >>> eval(parser.expr("os.system('echo evil syscall')").compile()) evil syscallGlidebomb
parser is deprecated in python 3.9 docs.python.org/3/whatsnew/3.9.html#new-parserNeedlecraft
V
15
 f = parser.parse('sin(x)*x^2').to_pyfunc()

Where parser could be defined using PLY, pyparsing, builtin tokenizer, parser, ast.

Don't use eval on user input.

Vainglorious answered 27/2, 2009 at 10:51 Comment(3)
eval on user input is indeed bad.Camion
Could you be more specific? I have tried to import parser module in Python 3.8 but it complains: Module 'parser' has no attribute 'parse'Enchain
@s.ouchene: "parser" here is just a stand-in for a custom module that implements the corresponding functionality (it is not literally stdlib's parser module). Here's an example for arithmetic expressionsVainglorious
S
10

pyparsing might do what you want (http://pyparsing.wikispaces.com/) especially if the strings are from an untrusted source.

See also http://pyparsing.wikispaces.com/file/view/fourFn.py for a fairly full-featured calculator built with it.

Sensual answered 29/3, 2010 at 12:11 Comment(2)
The links are no longer avaible on wikispaces.Seize
Pyparsing is no longer hosted on wikispaces.com. Go to github.com/pyparsing/pyparsingDornick
O
3

To emphasize J.F. Sebastian's advice, 'eval' and even the 'compiler' solutions can be open to subtle security holes. How trustworthy is the input? With 'compiler' you can at least filter out things like getattr lookups from the AST, but I've found it's easier to use PLY or pyparsing for this sort of thing than it is to secure the result of letting Python help out.

Also, 'compiler' is clumsy and hard to use. It's deprecated and removed in 3.0. You should use the 'ast' module (added in 2.6, available in 2.5 as '_ast').

Overmodest answered 27/2, 2009 at 11:57 Comment(0)
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In agreement with vartec. I would use SymPy - in particular the lambdify function should do exactly what you want.

See: http://showmedo.com/videotutorials/video?name=7200080&fromSeriesID=720

for a very nice explanation of this.

Best wishes,

Lightner answered 29/3, 2010 at 11:44 Comment(1)
Please include all the relevant information in the post itself, "Here is a link to a video that answers the question" is not a good answer.Quest
E
0

Sage is intended as matlab replacement and in intro videos it's demonstrated how similar to yours cases are handled. They seem to be supporting a wide range of approaches. Since the code is open-source you could browse and see for yourself how the authors handle such cases.

Extrusive answered 27/2, 2009 at 10:50 Comment(0)

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