React-Router v6+ Answer
TL;DR: You can use the new useNavigate
hook.
import { useNavigate } from "react-router-dom";
function Component() {
let navigate = useNavigate();
// Somewhere in your code, e.g. inside a handler:
navigate("/posts");
}
The useNavigate
hook returns a function which can be used for programmatic navigation.
Example from the react router documentation
import { useNavigate } from "react-router-dom";
function SignupForm() {
let navigate = useNavigate();
async function handleSubmit(event) {
event.preventDefault();
await submitForm(event.target);
navigate("../success", { replace: true });
// replace: true will replace the current entry in
// the history stack instead of adding a new one.
}
return <form onSubmit={handleSubmit}>{/* ... */}</form>;
}
React-Router 5.1.0+ Answer (using hooks and React >16.8)
You can use the useHistory
hook on Functional Components and Programmatically navigate:
import { useHistory } from "react-router-dom";
function HomeButton() {
let history = useHistory();
// use history.push('/some/path') here
};
React-Router 4.0.0+ Answer
In 4.0 and above, use the history as a prop of your component.
class Example extends React.Component {
// use `this.props.history.push('/some/path')` here
};
NOTE: this.props.history
does not exist in the case your component was not rendered by <Route>
. You should use <Route path="..." component={YourComponent}/>
to have this.props.history
in YourComponent
React-Router 3.0.0+ Answer
In 3.0 and above, use the router as a prop of your component.
class Example extends React.Component {
// use `this.props.router.push('/some/path')` here
};
React-Router 2.4.0+ Answer
In 2.4 and above, use a higher order component to get the router as a prop of your component.
import { withRouter } from 'react-router';
class Example extends React.Component {
// use `this.props.router.push('/some/path')` here
};
// Export the decorated class
var DecoratedExample = withRouter(Example);
// PropTypes
Example.propTypes = {
router: React.PropTypes.shape({
push: React.PropTypes.func.isRequired
}).isRequired
};
React-Router 2.0.0+ Answer
This version is backwards compatible with 1.x so there's no need to an Upgrade Guide. Just going through the examples should be good enough.
That said, if you wish to switch to the new pattern, there's a browserHistory
module inside the router that you can access with
import { browserHistory } from 'react-router'
Now you have access to your browser history, so you can do things like push, replace, etc... Like:
browserHistory.push('/some/path')
Further reading:
Histories and
Navigation
React-Router 1.x.x Answer
I will not go into upgrading details. You can read about that in the Upgrade Guide
The main change about the question here is the change from Navigation
mixin to History
. Now it's using the browser historyAPI to change route so we will use pushState()
from now on.
Here's an exemple using Mixin:
var Example = React.createClass({
mixins: [ History ],
navigateToHelpPage () {
this.history.pushState(null, `/help`);
}
})
Note that this History
comes from rackt/history project. Not from React-Router itself.
If you don't want to use Mixin for some reason (maybe because of ES6 class), then you can access the history that you get from the router from this.props.history
. It will be only accessible for the components rendered by your Router
. So, if you want to use it in any child components it needs to be passed down as an attribute via props
.
You can read more about the new release at their 1.0.x documentation
Here is a help page specifically about navigating outside your component
It recommends grabbing a reference history = createHistory()
and calling replaceState
on that.
React-Router 0.13.x Answer
I got into the same problem and could only find the solution with the Navigation mixin that comes with react-router.
Here's how I did it
import React from 'react';
import {Navigation} from 'react-router';
let Authentication = React.createClass({
mixins: [Navigation],
handleClick(e) {
e.preventDefault();
this.transitionTo('/');
},
render(){
return (<div onClick={this.handleClick}>Click me!</div>);
}
});
I was able to call transitionTo()
without the need to access .context
Or you could try the fancy ES6 class
import React from 'react';
export default class Authentication extends React.Component {
constructor(props) {
super(props);
this.handleClick = this.handleClick.bind(this);
}
handleClick(e) {
e.preventDefault();
this.context.router.transitionTo('/');
}
render(){
return (<div onClick={this.handleClick}>Click me!</div>);
}
}
Authentication.contextTypes = {
router: React.PropTypes.func.isRequired
};
React-Router-Redux
Note: if you're using Redux, there is another project called
React-Router-Redux that gives you
redux bindings for ReactRouter, using somewhat the same approach that
React-Redux does
React-Router-Redux has a few methods available that allow for simple navigating from inside action creators. These can be particularly useful for people that have existing architecture in React Native, and they wish to utilize the same patterns in React Web with minimal boilerplate overhead.
Explore the following methods:
push(location)
replace(location)
go(number)
goBack()
goForward()
Here is an example usage, with Redux-Thunk:
./actioncreators.js
import { goBack } from 'react-router-redux'
export const onBackPress = () => (dispatch) => dispatch(goBack())
./viewcomponent.js
<button
disabled={submitting}
className="cancel_button"
onClick={(e) => {
e.preventDefault()
this.props.onBackPress()
}}
>
CANCEL
</button>