How can I know which radio button is selected via jQuery?

Question

I have two radio buttons and want to post the value of the selected one. How can I get the value with jQuery?

I can get all of them like this:

$("form :radio")

How do I know which one is selected?

Fairground

Answer 1

To get the value of the selected radioName item of a form with id myForm:

$('input[name=radioName]:checked', '#myForm').val()

Here's an example:

$('#myForm input').on('change', function() {
  alert($('input[name=radioName]:checked', '#myForm').val());
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form id="myForm">
  <fieldset>
    <legend>Choose radioName</legend>
    <label><input type="radio" name="radioName" value="1" /> 1</label> <br />
    <label><input type="radio" name="radioName" value="2" /> 2</label> <br />
    <label><input type="radio" name="radioName" value="3" /> 3</label> <br />
  </fieldset>
</form>

Rosamariarosamond

Just going to add this because it might help someone. If the name of the radio has brackets like radioName[0] (sometimes used in Wordpress), you will want to use quotes around the name like input[name='radioName[0]']:checked – Amara

Just noting, in the onChange method example, you can also use this.value instead of $('input[name=radioName]:checked', '#myForm').val() :) – Valarievalda

For a non-jquery version, see here: jsfiddle.net/2y76vp1e – Cain

@ ZeroNine, that's also the case in Symfony framework that I use. – Rations

This is a great answer. I'd like to confirm something: if a class of "radio" is assigned to the radio button, does something like $(".radio:checked", "#myForm").val() work as well? And what about $("#myForm .radio:checked").val()? – Davison

@AngelUmeh that's right! – Rosamariarosamond

Answer 2

Use this..

$("#myform input[type='radio']:checked").val();

Tebet

Answer 3

If you already have a reference to a radio button group, for example:

var myRadio = $("input[name=myRadio]");

Use the filter() function, not find(). (find() is for locating child/descendant elements, whereas filter() searches top-level elements in your selection.)

var checkedValue = myRadio.filter(":checked").val();

---

Notes: This answer was originally correcting another answer that recommended using find(), which seems to have since been changed. find() could still be useful for the situation where you already had a reference to a container element, but not to the radio buttons, e.g.:

var form = $("#mainForm");
...
var checkedValue = form.find("input[name=myRadio]:checked").val();

Incubation

Answer 4

This should work:

$("input[name='radioName']:checked").val()

Note the "" usaged around the input:checked and not '' like the Peter J's solution

Faithless

Why does this returns me "on" instead of the value of the selected radio button? – Meritocracy

Answer 5

You can use the :checked selector along with the radio selector.

 $("form:radio:checked").val();

Hocuspocus

This looks nice, however, the jQuery documentation recommends using [type=radio] rather than :radio for better performance. It is a tradeoff between readability and performance. I normally take readability over performance on such trivial matters, but in this case I think [type=radio] is actually clearer. So in this case it would look like $("form input[type=radio]:checked").val(). Still a valid answer though. – Exsanguine

Answer 6

If you want just the boolean value, i.e. if it's checked or not try this:

$("#Myradio").is(":checked")

Woodbury

Answer 7

Get all radios:

var radios = jQuery("input[type='radio']");

Filter to get the one thats checked

radios.filter(":checked")

Frontage

Answer 8

Another option is:

$('input[name=radioName]:checked').val()

Sudd

The ":radio" part isn't necessary here. – Incubation

Answer 9

$("input:radio:checked").val();

Sander

Answer 10

In my case I have two radio buttons in one form and I wanted to know the status of each button. This below worked for me:

// get radio buttons value
console.log( "radio1: " +  $('input[id=radio1]:checked', '#toggle-form').val() );
console.log( "radio2: " +  $('input[id=radio2]:checked', '#toggle-form').val() );


    

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form id="toggle-form">
  <div id="radio">
    <input type="radio" id="radio1" name="radio" checked="checked" /><label for="radio1">Plot single</label>
    <input type="radio" id="radio2" name="radio"/><label for="radio2">Plot all</label>
  </div>
</form>

Jolly

What do you mean the status of each button? radio buttons with the same name allows only one to be checked, therefor, if you get the checked one, the rest are unchecked. – Porcelain

Answer 11

Here's how I would write the form and handle the getting of the checked radio.

Using a form called myForm:

<form id='myForm'>
    <input type='radio' name='radio1' class='radio1' value='val1' />
    <input type='radio' name='radio1' class='radio1' value='val2' />
    ...
</form>

Get the value from the form:

$('#myForm .radio1:checked').val();

If you're not posting the form, I would simplify it further by using:

<input type='radio' class='radio1' value='val1' />
<input type='radio' class='radio1' value='val2' />

Then getting the checked value becomes:

    $('.radio1:checked').val();

Having a class name on the input allows me to easily style the inputs...

Moderate

Answer 12

try this one. it worked for me

$('input[type="radio"][name="name"]:checked').val();

Townes

Answer 13

In a JSF generated radio button (using <h:selectOneRadio> tag), you can do this:

radiobuttonvalue = jQuery("input[name='form_id\:radiobutton_id']:checked").val();

where selectOneRadio ID is radiobutton_id and form ID is form_id.

Be sure to use name instead id, as indicated, because jQuery uses this attribute (name is generated automatically by JSF resembling control ID).

Hallel

Answer 14

Also, check if the user does not select anything.

var radioanswer = 'none';
if ($('input[name=myRadio]:checked').val() != null) {           
   radioanswer = $('input[name=myRadio]:checked').val();
}

Sri

Answer 15

If you have Multiple radio buttons in single form then

var myRadio1 = $('input[name=radioButtonName1]');
var value1 = myRadio1.filter(':checked').val();

var myRadio2 = $('input[name=radioButtonName2]');
var value2 = myRadio2.filter(':checked').val();

This is working for me.

Leucoderma

Answer 16

I wrote a jQuery plugin for setting and getting radio-button values. It also respects the "change" event on them.

(function ($) {

    function changeRadioButton(element, value) {
        var name = $(element).attr("name");
        $("[type=radio][name=" + name + "]:checked").removeAttr("checked");
        $("[type=radio][name=" + name + "][value=" + value + "]").attr("checked", "checked");
        $("[type=radio][name=" + name + "]:checked").change();
    }

    function getRadioButton(element) {
        var name = $(element).attr("name");
        return $("[type=radio][name=" + name + "]:checked").attr("value");
    }

    var originalVal = $.fn.val;
    $.fn.val = function(value) {

        //is it a radio button? treat it differently.
        if($(this).is("[type=radio]")) {

            if (typeof value != 'undefined') {

                //setter
                changeRadioButton(this, value);
                return $(this);

            } else {

                //getter
                return getRadioButton(this);

            }

        } else {

            //it wasn't a radio button - let's call the default val function.
            if (typeof value != 'undefined') {
                return originalVal.call(this, value);
            } else {
                return originalVal.call(this);
            }

        }
    };
})(jQuery);

Put the code anywhere to enable the addin. Then enjoy! It just overrides the default val function without breaking anything.

You can visit this jsFiddle to try it in action, and see how it works.

Fiddle

Propend

Answer 17

 $(".Stat").click(function () {
     var rdbVal1 = $("input[name$=S]:checked").val();
 }

Somniloquy

Answer 18

This works fine

$('input[type="radio"][class="className"]:checked').val()

Working Demo

The :checked selector works for checkboxes, radio buttons, and select elements. For select elements only, use the :selected selector.

API for :checked Selector

Micheal

Answer 19

To get the value of the selected radio that uses a class:

$('.class:checked').val()

Weswesa

Answer 20

I use this simple script

$('input[name="myRadio"]').on('change', function() {
  var radioValue = $('input[name="myRadio"]:checked').val();        
  alert(radioValue); 
});

Climacteric

Use the click event rather than the change event if you want it to work in all browsers – Incubation

Answer 21

Use this:

value = $('input[name=button-name]:checked').val();

Datum

Answer 22

DEMO : https://jsfiddle.net/ipsjolly/xygr065w/

	$(function(){
	    $("#submit").click(function(){      
	        alert($('input:radio:checked').val());
	    });
	 });

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<table>
       <tr>
         <td>Sales Promotion</td>
         <td><input type="radio" name="q12_3" value="1">1</td>
         <td><input type="radio" name="q12_3" value="2">2</td>
         <td><input type="radio" name="q12_3" value="3">3</td>
         <td><input type="radio" name="q12_3" value="4">4</td>
         <td><input type="radio" name="q12_3" value="5">5</td>
      </tr>
    </table>
<button id="submit">submit</button>

Reeva

Answer 23

If you only have 1 set of radio buttons on 1 form, the jQuery code is as simple as this:

$( "input:checked" ).val()

Unipersonal

Answer 24

Using $('input[name="radioName"]').filter(":checked").val(); is the best way for me.

Tested, this works

Form

<form id="myForm">
  <input type="radio" name="radioName" value="Option1"> Option1
  <input type="radio" name="radioName" value="Option2" checked> Option2
  <input type="radio" name="radioName" value="Option3"> Option3
</form>

Jquery

$(document).ready(function() {
  $('input[name="radioName"]').on('change', function() {
     const val = $(this).filter(":checked").val();
     alert(val);
  })

  // First load check
  const val = $('input[name="radioName"]').filter(":checked").val();
  alert(val);
});

Example here: https://codepen.io/abinhho/pen/mdLrqbX

Bestial

Answer 25

I've released a library to help with this. Pulls all possible input values, actually, but also includes which radio button was checked. You can check it out at https://github.com/mazondo/formalizedata

It'll give you a js object of the answers, so a form like:

<form>
<input type="radio" name"favorite-color" value="blue" checked> Blue
<input type="radio" name="favorite-color" value="red"> Red
</form>

will give you:

$("form").formalizeData()
{
  "favorite-color" : "blue"
}

Malefic

Answer 26

JQuery to get all the radio buttons in the form and the checked value.

$.each($("input[type='radio']").filter(":checked"), function () {
  console.log("Name:" + this.name);
  console.log("Value:" + $(this).val());
});

Lamellirostral

Answer 27

To retrieve all radio buttons values in JavaScript array use following jQuery code :

var values = jQuery('input:checkbox:checked.group1').map(function () {
    return this.value;
}).get();

Bipropellant

Radio buttons are not the same as checkboxes. This example uses checkboxes. – Incubation

Answer 28

try it-

var radioVal = $("#myform").find("input[type='radio']:checked").val();

console.log(radioVal);

Shizukoshizuoka

Answer 29

Another way to get it:

 $("#myForm input[type=radio]").on("change",function(){
   if(this.checked) {
    alert(this.value);
    }
  });

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form id="myForm">
   <span><input type="radio" name="q12_3" value="1">1</span><br>
   <span><input type="radio" name="q12_3" value="2">2</span>
</form>

Jamilla

Answer 30

From this question, I came up with an alternate way to access the currently selected input when you're within a click event for its respective label. The reason why is because the newly selected input isn't updated until after its label's click event.

TL;DR

$('label').click(function() {
  var selected = $('#' + $(this).attr('for')).val();

  ...
});

$(function() {
  // this outright does not work properly as explained above
  $('#reported label').click(function() {
    var query = $('input[name="filter"]:checked').val();
    var time = (new Date()).toString();

    $('.query[data-method="click event"]').html(query + ' at ' + time);
  });

  // this works, but fails to update when same label is clicked consecutively
  $('#reported input[name="filter"]').on('change', function() {
    var query = $('input[name="filter"]:checked').val();
    var time = (new Date()).toString();

    $('.query[data-method="change event"]').html(query + ' at ' + time);
  });

  // here is the solution I came up with
  $('#reported label').click(function() {
    var query = $('#' + $(this).attr('for')).val();
    var time = (new Date()).toString();

    $('.query[data-method="click event with this"]').html(query + ' at ' + time);
  });
});

input[name="filter"] {
  display: none;
}
#reported label {
  background-color: #ccc;
  padding: 5px;
  margin: 5px;
  border-radius: 5px;
  cursor: pointer;
}
.query {
  padding: 5px;
  margin: 5px;
}
.query:before {
  content: "on " attr(data-method)": ";
}
[data-method="click event"] {
  color: red;
}
[data-method="change event"] {
  color: #cc0;
}
[data-method="click event with this"] {
  color: green;
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form id="reported">
  <input type="radio" name="filter" id="question" value="questions" checked="checked">
  <label for="question">Questions</label>

  <input type="radio" name="filter" id="answer" value="answers">
  <label for="answer">Answers</label>

  <input type="radio" name="filter" id="comment" value="comments">
  <label for="comment">Comments</label>

  <input type="radio" name="filter" id="user" value="users">
  <label for="user">Users</label>

  <input type="radio" name="filter" id="company" value="companies">
  <label for="company">Companies</label>

  <div class="query" data-method="click event"></div>
  <div class="query" data-method="change event"></div>
  <div class="query" data-method="click event with this"></div>
</form>

Sabaean

Answer 31

$(function () {
// Someone has clicked one of the radio buttons
var myform= 'form.myform';
$(myform).click(function () {
    var radValue= "";
    $(this).find('input[type=radio]:checked').each(function () {
        radValue= $(this).val();
    });
  })
});

Golf

Answer 32

Try

myForm.myOption.value

function check() {
  console.log( myForm.myOption.value );
}

<form id="myForm">
  <input type="radio" name="myOption" value="1"> 1 <br>
  <input type="radio" name="myOption" value="2"> 2 <br>
  <input type="radio" name="myOption" value="3"> 3 <br>
</form>
<button onclick="check()">check</button>

Overexpose

Answer 33

This solution does not require jQuery.

const RADIO_NAME = "radioName";
const radios = Array.from(document.getElementsByName(RADIO_NAME));
const checkedRadio = radios.filter(e=>e.checked);

This uses jQuery:

const radios = Array.from($(`[name=${RADIO_NAME}`));
const checkedRadio = radios.filter(e=>e.checked);

jQuery adds an extra layer of abstraction that isn't needed here.

You could also use:

const radios = Array.from(document.querySelectorAll(`[name=${RADIO_NAME}`));
const checkedRadio = radios.filter(e=>e.checked)[0];

But getElementsByName is simple and clear enough.

Abstractionism

Your vanilla solution seems a bit bloated. One could use document.querySelector('[name=radioName]:checked') instead. And document.querySelectorAll(':checked') for all the checked radios in the document. – Plascencia

Answer 34

What I needed to do was simplify C# code, that is do as much as possible in the front end JavaScript. I'm using a fieldset container because I'm working in DNN and it has its own form. So I can't add a form.

I need to test which text box out of 3 is being used and if it is, what's the type of search? Starts with the value, Contains the value, Exact Match of the value.

HTML:

<fieldset id="fsPartNum" class="form-inline">
<div class="form-group">
    <label for="txtPartNumber">Part Number:</label>
    <input type="text" id="txtPartNumber" class="input-margin-pn" />
</div>
<div class="form-group">
    <label for="radPNStartsWith">Starts With: </label>
    <input type="radio" id="radPNStartsWith" name="partNumber" checked  value="StartsWith"/>
</div>
<div class="form-group">
    <label for="radPNContains">Contains: </label>
    <input type="radio" id="radPNContains" name="partNumber" value="Contains" />
</div>
<div class="form-group">
    <label for="radPNExactMatch">Exact Match: </label>
    <input type="radio" id="radPNExactMatch" name="partNumber" value="ExactMatch" />
</div>

And my JavaScript is:

        alert($('input[name=partNumber]:checked', '#fsPartNum').val()); 
    if(txtPartNumber.val() !== ''){
        message = 'Customer Part Number';
    }
    else if(txtCommercialPartNumber.val() !== ''){

    }
    else if(txtDescription.val() !== ''){

    }

Just saying any containing tag with an ID can be used. For DNNers, this is good to know. The end goal here is pass to the mid-level code what is needed to start a parts search in SQL Server.

This way I don't have to copy the much more complicated previous C# code also. The heavy lifting is being done right here.

I had to look a bit for this and then tinker with it to get it to work. So for other DNNers, hopefully this is easy to find.

Classmate

Answer 35

You need access with the :checked selector:

Check this doc:

• https://api.jquery.com/checked-selector/

a example:

$('input[name=radioName]:checked', '#myForm').val()
$('#myForm input').on('change', function() {
	$('#val').text($('input[name=radioName]:checked', '#myForm').val());
});

#val {
  color: #EB0054;
  font-size: 1.5em;
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<h3>Radio value: <span id='val'><span></h3>
<form id="myForm">
  <input type="radio" name="radioName" value="a"> a <br>
  <input type="radio" name="radioName" value="b"> b <br>
  <input type="radio" name="radioName" value="c"> c <br>
</form>

Ultra

Answer 36

How about this?

Using change and get the value of radio type is checked...

$('#my-radio-form').on('change', function() {
  console.log($('[type="radio"]:checked').val());
});

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.0.0/jquery.min.js"></script>
<form id="my-radio-form">
  <input type="radio" name="input-radio" value="a" />a
  <input type="radio" name="input-radio" value="b" />b
  <input type="radio" name="input-radio" value="c" />c
  <input type="radio" name="input-radio" value="d" />d
</form>

Sequela

Answer 37

**Please try below example to check which radio button in selected **

<script>
    $('#form1 input').on('change', function() {
       alert($('input[name=age]:checked', '#form1 ').val()); 
    });
</script>
 <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js">
    <form id="form1">
      <input type="radio" name="age" value="18" /> 18 <br />
      <input type="radio" name="age" value="20" /> 20 <br />
      <input type="radio" name="age" value="22" /> 22 <br />
    </form>

Hi

Answer 38

Along with the CSS selector :checked, you can also use the prop function (as of jQuery 1.6). I can't remember what project I was working on where simply using $('#something').is(':checked') only worked sometimes, and I resorted to also using $('#something').prop('checked') worked when it failed, but it led me to using both.

In my code snippet below, I've written two helper functions, is_checked and get_group_value. The function is_checked returns a boolean true/false value; true if the input passed in the parameter is checked (also checks with the prop() function) or false if it's not checked. The function get_group_value takes the name of the radio inputs and returns the value of the one that is checked, or an empty string if none are checked. These helper functions will also work with checkboxes, not just radio buttons.

Since the question did not define when they're retrieving the value(s), I've written a few listeners for four (3) different scenarios: when interacting with any radio button, when submitting the form, and when clicking one of these hard-coded buttons to do a one-time retrieval of the value of the group.

Please note that I'm using "click" to identify when the user interacts with the radio input element because "change" will never get triggered since the "value" attribute doesn't get changed when it's checked or not. I use this for checkboxes as well as radio buttons.

function is_checked(input) {
  var $input = $(input);
  return $input.is(':checked') || $input.prop('checked'); //Returns a boolean value. True if checked, false if not.
}
function get_group_value(group_name) {
  var $inputs = $('[name="' + group_name + '"]:checked');
  if ($inputs.length) { return $inputs.first().val(); } //If it exists, return the value of the first one found
  return ''; //If it doesn't exist, return nothing
}
$('form').on('submit', function(e) {
  e.preventDefault();
  var $form = $(this), results = {};
  $form.find('input[type=radio]').each(function() {
    var $input = $(this);
    if (is_checked(this)) {
      results[$input.attr('name')] = $input.val();
    }
  });
  console.info('Form Results', results);
});
$('form input[type=radio]').on('click', function(e) {
  var group_name = $(this).attr('name');
  console.info('Radio Button Click', group_name, get_group_value(group_name));
});
$('button.radio-button').on('click', function(e) {
  var group_name = $(this).attr('id');
  console.info('Button Click', group_name, get_group_value(group_name));
});

.my-test {
  background: #ffffff;
  color: #000000;
  padding: 16px;
}

form {
  padding: 8px;
  border: 1px solid #999999;
}

fieldset {
  border: none;
}

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="my-test">
  <form>
    Group 1
    <fieldset>
      <label><input type="radio" name="example-1" value="Foo" required />Foo</label>
      <label><input type="radio" name="example-1" value="Bar" required />Bar</label>
    </fieldset>
    Group 2
    <fieldset>
      <label><input type="radio" name="example-2" value="Banana" required />Banana</label>
      <label><input type="radio" name="example-2" value="Apple" required />Apple</label>
    </fieldset>
    <button type="submit">Submit</button>
  </form>
  <p>Press this button to just get the value of the first group: <button class="radio-button" id="example-1">Foo or Bar?</button></p>
  <p>Press this button to just get the value of the second group: <button class="radio-button" id="example-2">Banana or Apple?</button></p>
</div>

Postilion

Answer 39

jQuery plugin for setting and getting radio-button values. It also respects the "change" event on them.

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
    <form id="toggle-form">
      <div id="radio">
        <input type="radio" id="radio1" name="radio" checked="checked" /><label for="radio1">Plot single</label>
        <input type="radio" id="radio2" name="radio"/><label for="radio2">Plot all</label>
      </div>
    </form>
    <script type="text/javascript">
    $( document ).ready(function() {
     //Get all radios:
     var radios = jQuery("input[type='radio']");
     checked_radios=radios.filter(":checked");
for(i=0;i<checked_radios.length;i++)
{
   console.log(checked_radios[i]);
}

    });
    </script>

or another way

<script type="text/javascript">
$( document ).ready(function() {
  //Get all radios:
  checked_radios=jQuery('input[name=radio]:checked').val(); 
for(i=0;i<checked_radios.length;i++)
{
   console.log(checked_radios[i]);
}

});
</script>

Ruberta