The following snippet:
#include <memory>
#include <utility>
namespace foo
{
template <typename T>
void swap(T& a, T& b)
{
T tmp = std::move(a);
a = std::move(b);
b = std::move(tmp);
}
struct bar { };
}
void baz()
{
std::unique_ptr<foo::bar> ptr;
ptr.reset();
}
does not compile for me:
$ g++ -std=c++11 -c foo.cpp
In file included from /usr/include/c++/5.3.0/memory:81:0,
from foo.cpp:1:
/usr/include/c++/5.3.0/bits/unique_ptr.h: In instantiation of ‘void std::unique_ptr<_Tp, _Dp>::reset(std::unique_ptr<_Tp, _Dp>::pointer) [with _Tp = foo::bar; _Dp = std::default_delete<foo::bar>; std::unique_ptr<_Tp, _Dp>::pointer = foo::bar*]’:
foo.cpp:20:15: required from here
/usr/include/c++/5.3.0/bits/unique_ptr.h:342:6: error: call of overloaded ‘swap(foo::bar*&, foo::bar*&)’ is ambiguous
swap(std::get<0>(_M_t), __p);
^
In file included from /usr/include/c++/5.3.0/bits/stl_pair.h:59:0,
from /usr/include/c++/5.3.0/bits/stl_algobase.h:64,
from /usr/include/c++/5.3.0/memory:62,
from foo.cpp:1:
/usr/include/c++/5.3.0/bits/move.h:176:5: note: candidate: void std::swap(_Tp&, _Tp&) [with _Tp = foo::bar*]
swap(_Tp& __a, _Tp& __b)
^
foo.cpp:7:10: note: candidate: void foo::swap(T&, T&) [with T = foo::bar*]
void swap(T& a, T& b)
Is this my fault for declaring a swap()
function so general that it conflicts with std::swap
?
If so, is there a way to define foo::swap()
so that it doesn't get hauled in by Koenig lookup?
swap
template in a very specific namespace containing only specific types. Just define a non-templateswap
overload forfoo::bar
. Leave general swapping tostd::swap
, and only provide specific overloads. – Darrinfoo
is a layer of indirection we use over the standard library. Many of the platforms we support have incomplete/buggy standard libraries, and on those platforms we will do things like directfoo::shared_ptr
toboost::shared_ptr
instead ofstd::shared_ptr
. One of our platforms has an oldstd::swap()
that copies instead of moves, so we provided a replacement infoo
. – Goth