Hibernate: Where do insertable = false, updatable = false belong in composite primary key constellations involving foreign keys?
Asked Answered
G

1

39

When implementing composite primary keys in Hibernate or other ORMs there are up to three places where to put the insertable = false, updatable = false in composite primary key constellations that use identifying relationships (FKs that are part of the PK):

  1. Into the composite PK class' @Column annotation (@Embeddable classes only) or
  2. Into the entity class' association @JoinColumn/s annotation or
  3. Into the entity class' redundant PK property's @Column annotation (@IdClass classes only)

The third is the only way to do with @IdClass and JPA 1.0 AFAIK. See http://en.wikibooks.org/wiki/Java_Persistence/Identity_and_Sequencing#Primary_Keys_through_OneToOne_Relationships. I will consider only cases 1. and 2.

Q: Which way is the preferred place to put the "insertable = false, updatable = false" to generally?

I have experienced problems with Hibernate concerning this question. For example, Hibernate 3.5.x will complain about the Zips table

CREATE TABLE Zips
(
  country_code CHAR(2),
  code VARCHAR(10),
  PRIMARY KEY (country_code, code),
  FOREIGN KEY (country_code) REFERENCES Countries (iso_code)
)

with:

org.hibernate.MappingException: Repeated column in mapping for entity: com.kawoolutions.bbstats.model.Zip column: country_code (should be mapped with insert="false" update="false")
org.hibernate.mapping.PersistentClass.checkColumnDuplication(PersistentClass.java:676)
org.hibernate.mapping.PersistentClass.checkPropertyColumnDuplication(PersistentClass.java:698)
...

As you can see the country_code column is both PK and FK. Here are its classes:

Entity class:

@Entity
@Table(name = "Zips")
public class Zip implements Serializable
{
    @EmbeddedId
    private ZipId id;

    @ManyToOne
    @JoinColumn(name = "country_code", referencedColumnName = "iso_code")
    private Country country = null;
...
}

Composite PK class:

@Embeddable
public class ZipId implements Serializable
{
    @Column(name = "country_code", insertable = false, updatable = false)
    private String countryCode;

    @Column(name = "code")
    private String code;
...
}

When putting the insertable = false, updatable = false into the entity class association's @JoinColumn all exceptions disappear and everything work fine. However, I don't see why the above code should not be working. It might be Hibernate having problems with this. Is the described a Hibernate bug, as it doesn't seem to evaluate @Column "insertable = false, updatable = false"?

In essence, what's the standard JPA way, the best practice, or preference where to put "insertable = false, updatable = false"?

Garry answered 8/9, 2010 at 16:30 Comment(2)
Did you try the below answer? I did not see any comments or accepted answer. I know it might be late, but it will be helpful for any one visiting this page in future.Thank you.Heterogeneous
ManuPK, I have noticed your answer ever since. However, I will have to study this more in-depth which isn't possible right now.Garry
H
90

Let me answer step by step.

1. When do you need ` insertable = false, updatable = false`?

Let's look at the below mapping,

public class Zip {

    @ManyToOne
    @JoinColumn(name = "country_code", referencedColumnName = "iso_code")
    private Country country = null

    @Column(name = "country_code")
    private String countryCode;

}

Here we are referring to the same column in the table using two different properties. In the below code,

Zip z = new Zip();

z.setCountry(getCountry("US"));
z.setCountryCode("IN");

saveZip(z);

What will Hibernate do here??

To prevent these kind of inconsistency, Hibernate is asking you to specify the update point of relationships. Which means you can refer to the same column in the table n number of times but only one of them can be used to update and all others will be read only.

2. Why is Hibernate complaining about your mapping?

In your Zip class you are referring to the Embedded id class ZipId that again contains the country code. As in the above scenario now you have a possibility of updating the country_code column from two places. Hence the error given by Hibernate is proper.

3. How to fix it in your case?

No. Ideally you want your ZipId class to generate the id, so you should not add insertable = false, updatable = false to the countryCode inside the ZipId. So the fix is as below modify the country mapping in your Zip class as below,

@ManyToOne
@JoinColumn(name = "country_code", referencedColumnName = "iso_code",
insertable =  false, updatable = false)
private Country country;

Hope this helps your understanding.

Heterogeneous answered 25/2, 2012 at 8:19 Comment(0)

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