Fit a gaussian function
Asked Answered
W

4

28

I have a histogram (see below) and I am trying to find the mean and standard deviation along with code which fits a curve to my histogram. I think there is something in SciPy or matplotlib that can help, but every example I've tried doesn't work.

import matplotlib.pyplot as plt
import numpy as np

with open('gau_b_g_s.csv') as f:
    v = np.loadtxt(f, delimiter= ',', dtype="float", skiprows=1, usecols=None)

fig, ax = plt.subplots()

plt.hist(v, bins=500, color='#7F38EC', histtype='step')

plt.title("Gaussian")
plt.axis([-1, 2, 0, 20000])

plt.show()
Warfare answered 16/7, 2012 at 15:2 Comment(5)
What do you mean by doesn't work? It doesn't run, or the output isn't correct?Therewithal
I can't get the codes from the internet to run, to actually make a curve like they are supposed toWarfare
which is most likely happening because I just started programming and I generally have no idea what i'm doingWarfare
So are you getting an error message when you try to run it? Or does the program complete without producing anything?Therewithal
I just don't know how to properly make it work with my dataWarfare
M
47

Take a look at this answer for fitting arbitrary curves to data. Basically you can use scipy.optimize.curve_fit to fit any function you want to your data. The code below shows how you can fit a Gaussian to some random data (credit to this SciPy-User mailing list post).

import numpy
from scipy.optimize import curve_fit
import matplotlib.pyplot as plt

# Define some test data which is close to Gaussian
data = numpy.random.normal(size=10000)

hist, bin_edges = numpy.histogram(data, density=True)
bin_centres = (bin_edges[:-1] + bin_edges[1:])/2

# Define model function to be used to fit to the data above:
def gauss(x, *p):
    A, mu, sigma = p
    return A*numpy.exp(-(x-mu)**2/(2.*sigma**2))

# p0 is the initial guess for the fitting coefficients (A, mu and sigma above)
p0 = [1., 0., 1.]

coeff, var_matrix = curve_fit(gauss, bin_centres, hist, p0=p0)

# Get the fitted curve
hist_fit = gauss(bin_centres, *coeff)

plt.plot(bin_centres, hist, label='Test data')
plt.plot(bin_centres, hist_fit, label='Fitted data')

# Finally, lets get the fitting parameters, i.e. the mean and standard deviation:
print 'Fitted mean = ', coeff[1]
print 'Fitted standard deviation = ', coeff[2]

plt.show()
Military answered 16/7, 2012 at 15:42 Comment(6)
thanks, this got the mean and sd well, but the curve fit doesn't actually produce a curve, it produces linesWarfare
Do you mean my example just produces lines? Or when you apply the above code to your data you get lines? Also, what is the difference between a line and a curve?Military
as opposed to bell curve type shape, it just looks like a carrot ^Warfare
Without more information I can't really help you. Do you mean it looks like a carrot with your data? If so, then presumably it is because that is what your data looks like. When asking questions it is best to include a short, self contained example.Military
I suspect @Warfare means that, in his case, there aren't that many <bin_centres>, so when you plot(bin_centres, hist_fit), it comes out poorly sampled Gaussian ("carrot"). He should just subsample the bin_centers, using new_bin_centers = numpy.linspace(bin_centres[0], bin_centres[-1], 200), new_hist_fit = gauss(new_bin_centres, *coeff), and plot(new_bin_centres, new_hist_fit)Filly
it produces lines - @Military actually it does "not always" "produce lines". I made a quick example to showcase the issue. I like your code btw. Its neet. python-fiddle.com/saved/Bu000o3KIqQ0Kns5ggaJLitchfield
P
16

You can try sklearn gaussian mixture model estimation as below :

import numpy as np
import sklearn.mixture

gmm = sklearn.mixture.GMM()

# sample data
a = np.random.randn(1000)

# result
r = gmm.fit(a[:, np.newaxis]) # GMM requires 2D data as of sklearn version 0.16
print("mean : %f, var : %f" % (r.means_[0, 0], r.covars_[0, 0]))

Reference : http://scikit-learn.org/stable/modules/mixture.html#mixture

Note that in this way, you don't need to estimate your sample distribution with an histogram.

Proprietary answered 16/7, 2012 at 15:35 Comment(1)
sklearn.mixture.GMM seems to have been replaced with sklearn.mixture.GaussianMixture at some point.Mittel
B
3

Kind of an old question, but for anybody looking just to plot a density fit for a series, you could try matplotlib's .plot(kind='kde'). Docs here.

Example with pandas:

mydf.x.plot(kind='kde')
Blues answered 28/9, 2015 at 16:37 Comment(1)
wow, TIL matplotlib has kernel density estimation built in. +1Detrimental
P
1

I am not sure what your input is, but possibly your y-axis scale is too large (20000), try reducing this number. The following code works for me:

import matplotlib.pyplot as plt
import numpy as np

#created my variable
v = np.random.normal(0,1,1000)


fig, ax = plt.subplots()


plt.hist(v, bins=500, normed=1, color='#7F38EC', histtype='step')

#plot
plt.title("Gaussian")
plt.axis([-1, 2, 0, 1]) #changed 20000 to 1

plt.show()

Edit:

If you want the actual count of values on y-axis, you can set normed=0. And would just get rid of the plt.axis([-1, 2, 0, 1]).

import matplotlib.pyplot as plt
import numpy as np

#function
v = np.random.normal(0,1,500000)


fig, ax = plt.subplots()

# changed normed=1 to normed=0
plt.hist(v, bins=500, normed=0, color='#7F38EC', histtype='step')

#plot
plt.title("Gaussian")
#plt.axis([-1, 2, 0, 20000]) 

plt.show()
Praetorian answered 16/7, 2012 at 15:29 Comment(4)
no im working with over half a million points so I want the scale to be that big because I don't want like 50,000 binsWarfare
@I believe the value on y-axis does not tell you the number of observations in each bin, it tells you percentage in each bin. Just comment out the whole plt.axis([-1, 2, 0, 1]) line and run it, you should get a distribution plot.Praetorian
its definitely telling me the number in each bin because i can see the histogram itself with the y axis at 20,000Warfare
Downvoter, can you please explain the reason for the downvote?Praetorian

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