Is there anything wrong when deleting an object like this in C++?
MyCls* c = new MyCls();
void* p = (void*)c;
delete (MyCls*)p;
Is there anything wrong when deleting an object like this in C++?
MyCls* c = new MyCls();
void* p = (void*)c;
delete (MyCls*)p;
This as written is legal.
The cast back to MyCls*
is critical. Without that, you will invoke undefined behavior--the MyCls destructor will not be called, and other problems may arise as well (such as a crash). You must cast back to the correct type.
Also note that this can be complicated if multiple inheritance is involved and multiple casts are used. Your casts must "match" in either direction.
If your code is structured such that you won't know the type at the time of destruction, give each deletable object a common base class with a virtual destructor. Then cast back to the base class before delete is called.
The code is well-defined. Both casts are static casts, although it is good style to make this explicit (static_cast<void*>
, etc.) instead of using C-style casts. The standard says that if a pointer to object is converted to a void pointer and back by static casts, it will keep its original value. Thus, your final delete
expression shall have the same effect as delete c
.
That being said, use of void*
is often a code smell in C++.
void*
. I have so many war stories from cleaning up after former Java programmers who expect delete someVoidPointer;
to Just Work... –
Trickery Although this code is valid, it is not good practice.
As a general guideline, there shouldn't be new
s and delete
s in the wild. Try to enforce a rule that only constructors can call new
and only destructors can call delete
will help you organize your code better.
If you are using C++11, always try std::shared_ptr
and the like, this will do the above automatically for you.
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void *
and then back to its original type is guaranteed to preserve its value. – Ree