std::cout to print character N times

Question

How can I print a character N number of times using std::cout without looping?

Is there a way to move the text cursor back to nullify the effect of std::cout << std::endl;? i.e. to move up a line (say we never printed anything after doing the std::cout << std::endl; operation).

Ciscaucasia

C: #14679448 – Naturalize

Answer 1

 std::cout << std::string(100, '*') << std::endl;

To move a line up, you have to resort to terminal escapes (assuming that isatty() indicates that you are running on one).

Dzungaria

Or not pint the EOL in the first place ?? – Antler

True, I considered that. In my particular program it seemed easier otherwise. – Ciscaucasia

This does not work with Unicode characters. – Observance

@Mr.Clear Clearly, unicode wasn't supported (and the little machinery that exists has been deprecated). The best idea I have would probably be fmt::format here : compiler-explorer.com/z/1f98dTn5e – Dzungaria

Answer 2

std::cout << std::setfill(the_char) << std::setw(100) << "";

Hate

Answer 3

is there a way to back our way to nullify the effect of cout << endl; i.e. to move up a line(say we never printed anything after doing the cout << endl; operation) Thank you so much!

Use the ternary operator (or an if statement if you refer) ... something like ...

void PrintCharNtimes(char chatToPrint; int numTimes)
{
   std::cout << std::string(numTimes, chatToPrint) << (numTimes > 0) ? std::endl : ;
}

Antler