If I have a boolean field like:
private static final boolean DEBUG = false;
and within my code I have statements like:
if(DEBUG) System.err.println("err1");
does the Java preprocessor just get rid of the if statement and the unreachable code?
If I have a boolean field like:
private static final boolean DEBUG = false;
and within my code I have statements like:
if(DEBUG) System.err.println("err1");
does the Java preprocessor just get rid of the if statement and the unreachable code?
Most compilers will eliminate the statement. For example:
public class Test {
private static final boolean DEBUG = false;
public static void main(String... args) {
if (DEBUG) {
System.out.println("Here I am");
}
}
}
After compiling this class, I then print a listing of the produced instructions via the javap
command:
javap -c Test Compiled from "Test.java" public class Test extends java.lang.Object{ public Test(); Code: 0: aload_0 1: invokespecial #1; //Method java/lang/Object."":()V 4: return public static void main(java.lang.String[]); Code: 0: return }
As you can see, no System.out.println
! :)
if(DEBUG && condition_that_may_be_true) ...
, and if DEBUG
is always false it cuts it out. –
Fertilization Yes, the Java compiler will eliminate the compiled code within if
blocks that are controlled by constants. This is an acceptable way to conditionally compile "debug" code that you don't want to include in a production build.
if
statement is right near the end of that section. –
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