M

17

47

How, in Yii, to get the current page's URL. For example:

http://www.yoursite.com/your_yii_application/?lg=pl&id=15

but excluding the $GET_['lg'] (without parsing the string manually)?

I mean, I'm looking for something similar to the Yii::app()->requestUrl / Chtml::link() methods, for returning URLs minus some of the $_GET variables.

Edit: Current solution:

unset $_GET['lg'];

echo Yii::app()->createUrl(
  Yii::app()->controller->getId().'/'.Yii::app()->controller->getAction()->getId() , 
  $_GET 
);

Moir answered 7/12, 2011 at 9:32 Comment(2)

possible duplicate of How to remove the querystring and get only the url? – Wells 16/4, 2015 at 13:8

#8413562 – Aerothermodynamics 17/8, 2015 at 11:55

O

80

Yii 1

Yii::app()->request->url

For Yii2:

Yii::$app->request->url

Octopod answered 29/10, 2012 at 15:46 Comment(5)

This should be the correct answer, since the asker want to be done with Yii – Olathe 25/11, 2012 at 11:24

This is not what the poster asked for. See the answer below: #8413562 – Synapse 17/3, 2014 at 17:6

This is the wrong answer. User needs to EXCLUDE some GET parameters. – Alary 17/9, 2014 at 19:47

This anwer has a lot of up votes but it is misleading, @MichaelButler answer is very good but you can see shorter yii2 specific answer #8413562 – Walt 19/11, 2015 at 8:24

Yii2: Yii::$app->request->url – Appointed 31/8, 2016 at 8:42

C

32

Yii::app()->createAbsoluteUrl(Yii::app()->request->url)

This will output something in the following format:

http://www.yoursite.com/your_yii_application/

Caesium answered 22/12, 2012 at 6:23 Comment(3)

This should be the correct answer, sometimes the url includes not just controller and action, but view, and depends on the route methods. – Judo 20/10, 2014 at 16:26

I think this is wrong. Because createAbsoluteUrl expects a route not a URL. The author's original solution is quite right but a more correct one would be: $this->createUrl($this->getRoute(), $_GET) and before calling it, unset from $_GET the params that you don't wish. – Capacity 29/9, 2016 at 18:41

This is terrible answer, don't use it! It will give you a bunch of bugs when your URLs does not match routes. For example if /news/index should display route news/view for News model with slug index. With this answer you will get incorrect URL - it will redirect you to URL for /news/index route instead /news/view. – Perforation 9/6, 2018 at 13:7

S

23

Yii 1

Most of the other answers are wrong. The poster is asking for the url WITHOUT (some) $_GET-parameters.

Here is a complete breakdown (creating url for the currently active controller, modules or not):

// without $_GET-parameters
Yii::app()->controller->createUrl(Yii::app()->controller->action->id);

// with $_GET-parameters, HAVING ONLY supplied keys
Yii::app()->controller->createUrl(Yii::app()->controller->action->id,
    array_intersect_key($_GET, array_flip(['id']))); // include 'id'

// with all $_GET-parameters, EXCEPT supplied keys
Yii::app()->controller->createUrl(Yii::app()->controller->action->id,
    array_diff_key($_GET, array_flip(['lg']))); // exclude 'lg'

// with ALL $_GET-parameters (as mensioned in other answers)
Yii::app()->controller->createUrl(Yii::app()->controller->action->id, $_GET);
Yii::app()->request->url;

When you don't have the same active controller, you have to specify the full path like this:

Yii::app()->createUrl('/controller/action');
Yii::app()->createUrl('/module/controller/action');

Check out the Yii guide for building url's in general: http://www.yiiframework.com/doc/guide/1.1/en/topics.url#creating-urls

Synapse answered 17/3, 2014 at 17:5 Comment(2)

Yes, great answer! (and indeed the only correct one to the question) Could use an update it for Yii2 too though.. – Enthalpy 10/3, 2015 at 13:53

found it: Yii2: Yii::$app->urlManager->createUrl(array_merge([Yii::$app->requestedRoute], $getParams)); – Enthalpy 10/3, 2015 at 14:5

I

15

To get the absolute current request url (exactly as seen in the address bar, with GET params and http://) I found that the following works well:

Yii::app()->request->hostInfo . Yii::app()->request->url

Ism answered 17/6, 2014 at 15:0 Comment(0)

W

12

In Yii2 you can do:

use yii\helpers\Url;
$withoutLg = Url::current(['lg'=>null], true);

More info: https://www.yiiframework.com/doc/api/2.0/yii-helpers-baseurl#current%28%29-detail

Walt answered 29/10, 2015 at 8:34 Comment(0)

O

6

I don't know about doing it in Yii, but you could just do this, and it should work anywhere (largely lifted from my answer here):

// Get HTTP/HTTPS (the possible values for this vary from server to server)
$myUrl = (isset($_SERVER['HTTPS']) && $_SERVER['HTTPS'] && !in_array(strtolower($_SERVER['HTTPS']),array('off','no'))) ? 'https' : 'http';
// Get domain portion
$myUrl .= '://'.$_SERVER['HTTP_HOST'];
// Get path to script
$myUrl .= $_SERVER['REQUEST_URI'];
// Add path info, if any
if (!empty($_SERVER['PATH_INFO'])) $myUrl .= $_SERVER['PATH_INFO'];

$get = $_GET; // Create a copy of $_GET
unset($get['lg']); // Unset whatever you don't want
if (count($get)) { // Only add a query string if there's anything left
  $myUrl .= '?'.http_build_query($get);
}

echo $myUrl;

Alternatively, you could pass the result of one of the Yii methods into parse_url(), and manipulate the result to re-build what you want.

Omnibus answered 7/12, 2011 at 9:40 Comment(5)

This is really helpful. My only consideration is that Yii is using either the 'normal' (?var=value) format, or PATH (/var/value), they are toggled in a config file. That's why links in Yii are constructed using Chtml::link() with an array of $_GET variables. – Moir 7/12, 2011 at 10:1

Oh ! So I can... give the whole $_GET array as an input parameter, after unsetting one value :). [leaves for a minute to try it]. – Moir 7/12, 2011 at 10:9

@Moir This could be easily re-worked to use it in /var/value format - the exact details of how it would be done depend on the situation, but in effect you are just reformatting strings from the input data, so it's not that difficult. You can just do something like foreach ($get as $key => val) $myUrl .= "/$key/$val"; (may need slight alteration depending on exactly how your URLs are formatted). – Omnibus 7/12, 2011 at 10:21

elegant trick with the "/$key/$val"! Another solution: Yii::app()->createUrl(Yii::app()->controller->getId().'/'.Yii::app()->controller->getAction()->getId(), $_GET ); seems to work (after unsetting $_GET['lg'] :)! – Moir 7/12, 2011 at 10:59

No need to write code that Yii already provides. Read this: yiiframework.com/doc/api/1.1/CHttpRequest – Synapse 17/3, 2014 at 17:6

K

6

You are definitely searching for this

Yii::app()->request->pathInfo

Klausenburg answered 7/12, 2015 at 5:53 Comment(1)

This one is the correct answer. But for yii2 it should be Yii::$app->request->pathInfo – Frisette 28/8, 2016 at 3:42

K

5

So, you may use

Yii::app()->getBaseUrl(true)

to get an Absolute webroot url, and strip the http[s]://

Kraemer answered 15/5, 2014 at 7:24 Comment(0)

A

1

Something like this should work, if run in the controller:

$controller = $this;
$path = '/path/to/app/' 
  . $controller->module->getId() // only necessary if you're using modules
  . '/' . $controller->getId() 
  . '/' . $controller->getAction()->getId()
. '/';

This assumes that you are using 'friendly' URLs in your app config.

Allanallana answered 13/12, 2011 at 0:22 Comment(1)

Relying on one particular url style is bad and unnessecary. See this topic about creating url's in general: yiiframework.com/doc/guide/1.1/en/topics.url#creating-urls – Synapse 17/3, 2014 at 17:8

P

1

$validar= Yii::app()->request->getParam('id');

Protolanguage answered 11/3, 2015 at 6:53 Comment(0)

I

0

Yii2

Url::current([], true);

or

Url::current();

Ilka answered 30/6, 2018 at 9:25 Comment(0)

S

0

For Yii2: This should be safer Yii::$app->request->absoluteUrl rather than Yii::$app->request->url

Salman answered 5/10, 2018 at 11:31 Comment(0)

K

0

For Yii1

I find it a clean way to first get the current route from the CUrlManager, and then use that route again to build the new url. This way you don't 'see' the baseUrl of the app, see the examples below.

Example with a controller/action:

GET /app/customer/index/?random=param
$route = Yii::app()->urlManager->parseUrl(Yii::app()->request);
var_dump($route); // string 'customer/index' (length=14)
$new = Yii::app()->urlManager->createUrl($route, array('new' => 'param'));
var_dump($new); // string '/app/customer/index?new=param' (length=29)

Example with a module/controller/action:

GET /app/order/product/admin/?random=param
$route = Yii::app()->urlManager->parseUrl(Yii::app()->request);
var_dump($route); // string 'order/product/admin' (length=19)
$new = Yii::app()->urlManager->createUrl($route, array('new' => 'param'));
var_dump($new); string '/app/order/product/admin?new=param' (length=34)

This works only if your urls are covered perfectly by the rules of CUrlManager :)

Katydid answered 30/6, 2021 at 22:2 Comment(0)

N

0

For Yii2

I was rather surprised that the correct answer for Yii2 was in none of the responses.

The answer I use is:

Url::to(['']),

You can also use:

Url::to()

...but I think the first version makes it more obvious that your intention is to generate a url with the curent request route. (i.e. "/index.php?admin%2Findex" if you happened to be running from the actionIndex() in the AdminController.

You can get an absolute route with the schema and domain by passing true as a second parameter, so:

Url::to([''], true)

...would return something like "https://your.site.domain/index.php?admin%2Findex" instead.

Novelia answered 16/12, 2022 at 22:34 Comment(0)

I

-1

Try to use this variant:

<?php echo Yii::app()->createAbsoluteUrl('your_yii_application/?lg=pl', array('id'=>$model->id));?>

It is the easiest way, I guess.

Isolt answered 8/2, 2014 at 11:35 Comment(1)

Hardcoding the url is a bad practise. See this topic about creating url's in general: yiiframework.com/doc/guide/1.1/en/topics.url#creating-urls – Synapse 17/3, 2014 at 17:7

R

-1

Most of the answers are wrong.

The Question is to get url without some query param .

Here is the function that works. It does more things actually. You can remove the param that you don't want and you can add or modify an existing one.

/**
 * Function merges the query string values with the given array and returns the new URL
 * @param string $route
 * @param array $mergeQueryVars
 * @param array $removeQueryVars
 * @return string
 */
public static function getUpdatedUrl($route = '', $mergeQueryVars = [], $removeQueryVars = [])
{
    $currentParams = $request = Yii::$app->request->getQueryParams();

    foreach($mergeQueryVars as $key=> $value)
    {
        $currentParams[$key] = $value;
    }

    foreach($removeQueryVars as $queryVar)
    {
        unset($currentParams[$queryVar]);
    }

    $currentParams[0] = $route == '' ? Yii::$app->controller->getRoute() : $route;

    return Yii::$app->urlManager->createUrl($currentParams);

}

usage:

ClassName:: getUpdatedUrl('',[],['remove_this1','remove_this2'])

This will remove query params 'remove_this1' and 'remove_this2' from URL and return you the new URL

Riggle answered 12/1, 2017 at 10:2 Comment(0)

F

-1

echo Yii::$app->request->url;

Friseur answered 8/6, 2018 at 12:2 Comment(1)

How does this remove "some" of the variables from the URL? – Lumpy 18/7, 2018 at 6:44

Yii 1

For Yii2:

Yii 1

For Yii2

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