Generate a sequence of characters from 'A'-'Z'
Asked Answered
P

5

43

I can make a sequence of numbers like this:

s = seq(from=1, to=10, by=1)

How do I make a sequence of characters from A-Z? This doesn't work:

seq(from=1, to=10)
Polypetalous answered 6/12, 2010 at 19:13 Comment(0)
I
62

Use LETTERS and letters (for uppercase and lowercase respectively).

Inebriety answered 6/12, 2010 at 19:18 Comment(0)
K
48

Use the code you have with letters and/or LETTERS:

> LETTERS[seq( from = 1, to = 10 )]
 [1] "A" "B" "C" "D" "E" "F" "G" "H" "I" "J"
> letters[seq( from = 1, to = 10 )]
 [1] "a" "b" "c" "d" "e" "f" "g" "h" "i" "j"
Konyn answered 6/12, 2010 at 19:19 Comment(1)
Or just LETTERS[1:10]Jenifferjenilee
H
16

Just use the predefined variables letters and LETTERS.

And for completeness, here it something using seq:

R> rawToChar(as.raw(seq(as.numeric(charToRaw('a')), as.numeric(charToRaw('z')))))
[1] "abcdefghijklmnopqrstuvwxyz"
R> 
Hannis answered 6/12, 2010 at 19:18 Comment(0)
A
12

R.oo package has an intToChar function, that uses ASCII values, if LETTERS and letters aren't any good. A is 65 in ASCII:

> require(R.oo)
> intToChar(65:79)
 [1] "A" "B" "C" "D" "E" "F" "G" "H" "I" "J" "K" "L" "M" "N" "O"

or you can use the fact that the lowest unicode numbers are ascii and hence intToUtf8 in R-base like this:

> intToUtf8(65:78,multiple=TRUE)
 [1] "A" "B" "C" "D" "E" "F" "G" "H" "I" "J" "K" "L" "M" "N"

or faff around with rawToChar:

> rawToChar(as.raw(65:78))
[1] "ABCDEFGHIJKLMN"
Anguish answered 6/12, 2010 at 19:27 Comment(0)
F
2

LETTERS returns A-Z

To generate A-E for instance

Uppercase:

> LETTERS[1:5]

Lowercase

letters[1:5]
Fraenum answered 15/12, 2021 at 12:5 Comment(0)

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