As the title, I have one column (series) in pandas, and each row of it is a list like [0,1,2,3,4,5]
. Each list has 6 numbers. I want to change this column into 6 columns, for example, the [0,1,2,3,4,5]
will become 6 columns, with 0
is the first column, 1
is the second, 2
is the third and so on. How can I make it?
How to expand one column in Pandas to many columns?
Asked Answered
Not as fast as @jezrael's solution. But elegant :-)
apply
with pd.Series
df.a.apply(pd.Series)
0 1 2 3 4 5
0 0 1 2 3 4 5
1 0 1 2 3 4 5
or
df.a.apply(pd.Series, index=list('abcdef'))
a b c d e f
0 0 1 2 3 4 5
1 0 1 2 3 4 5
bigdata - it will be very slow ;) –
Lifegiving
@Lifegiving yes it will –
Natale
You can convert lists to numpy array
by values
and then use DataFrame
constructor:
df = pd.DataFrame({'a':[[0,1,2,3,4,5],[0,1,2,3,4,5]]})
print (df)
a
0 [0, 1, 2, 3, 4, 5]
1 [0, 1, 2, 3, 4, 5]
df1 = pd.DataFrame(df['a'].values.tolist())
print (df1)
0 1 2 3 4 5
0 0 1 2 3 4 5
1 0 1 2 3 4 5
cols = list('abcdef')
df1 = pd.DataFrame(df['a'].values.tolist(), columns=cols)
print (df1)
a b c d e f
0 0 1 2 3 4 5
1 0 1 2 3 4 5
If I understood your question correctly, you are looking for a transpose operation.
df = pd.DataFrame([1,2,3,4,5],columns='a')
# .T stands for transpose
print(df.T)
But I have 1000 rows, and I want to transfer each of all the rows into 6 individual columns.. –
Abbreviate
import pandas as pd
# create a sample DataFrame with a column containing comma-separated values
df = pd.DataFrame({'Name': ['John,Doe', 'Jane,Smith', 'Bob,Jones']})
# split the values in the 'Name' column and create new columns for each element
df[['First Name', 'Last Name']] = df['Name'].str.split(',', expand=True)
# drop the original 'Name' column
df = df.drop('Name', axis=1)
# print the resulting DataFrame
print(df)
© 2022 - 2025 — McMap. All rights reserved.