One function to detect NaN, NA, Inf, -Inf, etc.?

Question

Is there a single function in R that determines if a value is NA, NaN, Inf, -Inf, or otherwise not a well-formed number?

Alfrediaalfredo

Answer 1

You want is.finite

> is.finite(NA)
[1] FALSE
> is.finite(NaN)
[1] FALSE
> is.finite(Inf)
[1] FALSE
> is.finite(1L)
[1] TRUE
> is.finite(1.0)
[1] TRUE
> is.finite("A")
[1] FALSE
> is.finite(pi)
[1] TRUE
> is.finite(1+0i)
[1] TRUE

Starfish

Note that is.finite(TRUE) also returns TRUE. – Flagitious

@kohske: Good point. is.finite(FALSE) also returns TRUE. This is likely because TRUE and FALSE are just integers. – Starfish

True and false aren't integers - but they will be coerced without error/warning message – Miscarriage

@hadley: I wasn't clear; thanks for clarifying. I was referring to R booleans being 32-bit integers at the C level, not that is.integer(TRUE) would return TRUE. – Starfish