How to customize the auth.User Admin page in Django CRUD?

Question

I just want to add the subscription date in the User list in the Django CRUD Administration site. How can I do that ?

Thank you for your help

Otology

Answer 1

I finally did like this in my admin.py file :

from django.contrib.auth.admin import UserAdmin
from django.contrib.auth.models import User

UserAdmin.list_display = ('email', 'first_name', 'last_name', 'is_active', 'date_joined', 'is_staff')

admin.site.unregister(User)
admin.site.register(User, UserAdmin)

Otology

We can also extends the UserAdmin instead of dynamically modifying it ! – Otology

To clarify, this should be added to your site's top-level admin.py file. – Labelle

can I ask what you mean by top-level? – Uphold

It means that you should create an admin.py file at the root of your Django project (on the same level as your wsgi.py or settings.py files.) – Otology

It doesn't seem like you need to unregister and reregister – Tramline

According to @Carl Meyer on the other answer you need to unregister. How would you do without unregistering? – Lucius

using your code above I do get import error as admin is not found – Homebred

I think the code organisation may have changed in the last versions of Django. – Otology

No it didn't: github.com/django/django/blob/master/django/contrib/auth/… – Otology

Maybe you are missing from django.contrib import admin ? – Otology

This is also asked as "how to make a project admin.py" that might be helpful to people who land here. #24128886 – Ameliorate

@JamieForrest In Django 2.1 top-level admin.py file doesn't work. I put it to my own App:(accounts.admin.py) then it works, Don't know why but anyway it works. BTW: There is a full example in docs.djangoproject.com/en/2.1/topics/auth/customizing – Typeset

Answer 2

Another way to do this is extending the UserAdmin class.

You can also create a function to put on list_display

from django.contrib.auth.admin import UserAdmin
from django.contrib.auth.models import User

class CustomUserAdmin(UserAdmin):
    def __init__(self, *args, **kwargs):
        super(UserAdmin,self).__init__(*args, **kwargs)
        UserAdmin.list_display = list(UserAdmin.list_display) + ['date_joined', 'some_function']

    # Function to count objects of each user from another Model (where user is FK)
    def some_function(self, obj):
        return obj.another_model_set.count()


admin.site.unregister(User)
admin.site.register(User, CustomUserAdmin)

Binnacle

Can I also do the following (without __init__), or is there a problem with it? class CustomUserAdmin(UserAdmin): list_display = list(UserAdmin.list_display) + ['date_joined'] – Donyadoodad

shouldn't that be CustomUserAdmin.list_display = .. rather than UserAdmin.list_display = ? – Reynold

@AmichaiSchreiber I think both works, but I agree that CustomUserAdmin.list_display = is the cleaner solution – Expertise

Answer 3

In admin.py

Import UserAdmin

from django.contrib.auth.admin import UserAdmin

Put which fields you need:

UserAdmin.list_display = ('email','is_active')  # Put what you need

Thats all! It works with Django3

Bazan

Or you can extend the list_display with additional fields (using Django4): UserAdmin.list_display = list(UserAdmin.list_display) + ['is_active', 'date_joined'] – Impatient

Answer 4

Assuming that your user class is User and your subscription date field is subscription_date, this is what you need to add on your admin.py

class UserAdmin(admin.ModelAdmin):
    list_display = ('subscription_date',)

admin.site.register(User, UserAdmin)

Emigrant

This should inherit from the built-in UserAdmin, otherwise you lose all the rest of the customizations. And you have to unregister the built-in registration too; Natim's answer has the right code. – Vichy