UISegmentedControl deselect (make none of the segments selected)

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in fact the title contains my question. I have a UISegmentedControl, and need to deselect currently selected tab. I tried:

[menu setSelectedSegmentIndex:-1];

menu being the UBOutlet for uisegmentedcontrol but this gives me exception. anyone have some idea? thanks peter

Goingover answered 5/2, 2010 at 9:8 Comment(2)

I'd also suggest using UISegmentedControlNoSegment instead of -1 - it's not a source of problem here but just in case – Milkfish 5/2, 2010 at 9:48

2010-02-05 11:10:16.799 Gazetapl[30839:20b] *** -[NSCFArray length]: unrecognized selector sent to instance 0x3d39ed0 [Session started at 2010-02-05 11:10:16 +0100.] 2010-02-05 11:10:16.800 Gazetapl[30839:20b] *** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '*** -[NSCFArray length]: unrecognized selector sent to instance 0x3d39ed0' 2010-02-05 11:10:16.802 Gazetapl[30839:20b] Stack: ( – Goingover 5/2, 2010 at 10:10

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I would assume that you've called [myArray length] instead of the proper [myArray count] somewhere in your code. NSArray uses the count method, not length for the number of items it contains.

Heliacal answered 5/2, 2010 at 17:29 Comment(7)

hi, i don't understand. what does this have to do with uisegmentedcontrol – Goingover 7/2, 2010 at 21:17

Nothing directly, but based on the exception you posted, the problem is not with UISegementedControl. Perhaps somewhere in your handling of changing the selected segment you access an array. – Heliacal 8/2, 2010 at 1:18

Why the down vote? Mine is the only answer that actually addresses the problem dusker was having. – Heliacal 17/11, 2014 at 17:17

Actually, your answer does not address the question. The op wants to deselect a segment from a UISegmentedController. – Trammell 23/12, 2015 at 14:18

The OP asked the wrong question (can be clearly seen by the exception), this is the correct answer. It addresses the problem 100%. – Abruption 16/1, 2016 at 18:58

What a tangent. But I commend your insight. – Bawdy 1/4, 2016 at 9:18

This doesn't answer the question of how to have no option selected at all...swift option below show be the accepted answer. – Mckamey 28/4, 2017 at 2:49

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253

The right way to do this is:

[menu setSelectedSegmentIndex:UISegmentedControlNoSegment];

Edit:

Swift 5:

menu.selectedSegmentIndex = UISegmentedControl.noSegment

Appear answered 6/2, 2012 at 18:11 Comment(3)

I do not understand why OP does not select this answer!. – Execrative 10/11, 2014 at 4:39

@Execrative because this wasn't his question. He was already doing this (mostly) correctly. His problem was elsewhere as I explained. – Heliacal 17/11, 2014 at 17:16

@DavidKanarek but it really doesn't make sense, this is the answer and I had the same problem, I googled it, this was the first google result, and this is the answer, strange, also in the question I can't see any other code or exceptions..! – Egress 14/9, 2015 at 7:14

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Setting the segmentedControl to .momentary = YES changes the way the user can interact with the segmentedControl. If you want to have nothing selected initially when the page loads but have segmentedControl behave the same after a selection is made by the user then you will want something more like this:

Swift 4 solution:

 @IBOutlet weak var segmentedControl: UISegmentedControl!

 self.segmentedControl.selectedSegmentIndex = UISegmentedControlNoSegment

Swift 5.1:

 self.segmentedControl.selectedSegmentIndex = UISegmentedControl.noSegment

Turncoat answered 15/3, 2016 at 16:34 Comment(0)

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31

I guess you try to create a momentary selection in segmented control. In interface builder set the segmentedcontrol to momentary. Or in code you can do:

menu.momentary = YES;

Chaotic answered 19/5, 2011 at 18:0 Comment(1)

Momentary will still result in a segment being selected on load. Besides, use of Momentary should only be because you actually want a Momentary segment control, not just to try to force no segment selection. Use the UISegmentedControlNoSegment solution. – Layman 1/4, 2016 at 20:28

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8

I did class which supports this kind of interaction:

class UIDeselectableSegmentedControl: UISegmentedControl {

    override func touchesEnded(_ touches: Set<UITouch>, with event: UIEvent?) {
        let previousSelectedSegmentIndex = self.selectedSegmentIndex

        super.touchesEnded(touches, with: event)

        if previousSelectedSegmentIndex == self.selectedSegmentIndex {

            self.selectedSegmentIndex = UISegmentedControl.noSegment
            let touch = touches.first!
            let touchLocation = touch.location(in: self)
            if bounds.contains(touchLocation) {
                self.sendActions(for: .valueChanged)
            }
        }
    }
}

The main advantage of that is that you just need to modify which class the Storyboard/Xib/ViewCode is using and this will work like a charm ;]

Vanir answered 22/11, 2019 at 20:42 Comment(0)

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7

swift 4

@IBOutlet weak var segmentControl: UISegmentedControl! {
    didSet {
        segmentControl.selectedSegmentIndex = UISegmentedControl.noSegment
    }
}

Franctireur answered 20/12, 2018 at 6:33 Comment(0)

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3

You can now do this in xcode 6 in the interface builder:

Deselect the 'Selected' option under segmented control behaviour in attributes inspector.

Ames answered 11/10, 2014 at 9:21 Comment(0)

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2

The Swift solution: @IBOutlet weak var mySegmentedControl: UISegmentedControl! and mySegmentedControl.selectedSegmentIndex = -1.

Issie answered 20/11, 2015 at 3:47 Comment(0)

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