How do I programmatically list all projects in a solution?
Asked Answered
O

14

55

How do I programmatically list all of the projects in a solution? I'll take a script, command-line, or API calls.

Obie answered 27/9, 2010 at 8:7 Comment(0)
G
75

Here's a PowerShell script that retrieves project details from a .sln file:

Get-Content 'Foo.sln' |
  Select-String 'Project\(' |
    ForEach-Object {
      $projectParts = $_ -Split '[,=]' | ForEach-Object { $_.Trim('[ "{}]') };
      New-Object PSObject -Property @{
        Name = $projectParts[1];
        File = $projectParts[2];
        Guid = $projectParts[3]
      }
    }
Gallant answered 27/9, 2010 at 8:49 Comment(2)
I know this is old, but it is beautiful. Saved me a bunch of time.Studley
If you need to, you can filter out solution folders by adding an additional Select-String between lines 2 and 3 as follows: Select-String "{2150E333-8FDC-42A3-9474-1A3956D46DE8}" -NotMatch |Diplo
P
21
    var Content = File.ReadAllText(SlnPath);
    Regex projReg = new Regex(
        "Project\\(\"\\{[\\w-]*\\}\"\\) = \"([\\w _]*.*)\", \"(.*\\.(cs|vcx|vb)proj)\""
        , RegexOptions.Compiled);
    var matches = projReg.Matches(Content).Cast<Match>();
    var Projects = matches.Select(x => x.Groups[2].Value).ToList();
    for (int i = 0; i < Projects.Count; ++i)
    {
        if (!Path.IsPathRooted(Projects[i]))
            Projects[i] = Path.Combine(Path.GetDirectoryName(SlnPath),
                Projects[i]);
        Projects[i] = Path.GetFullPath(Projects[i]);
    }

Edit: Amended the regex to include the ".*" as per the comment by Kumar Vaibhav

Passim answered 8/2, 2013 at 12:22 Comment(2)
The above works but there is a little problem. If your projects are named like "AB.CD" - I mean when the '.' is there then the regex would not recognize those. The following little change would make it work - Regex projReg = new Regex( "Project\(\"\\{[\\w-]*\\}\"\) = \"([\\w _]*.*)\", \"(.*\\.(cs|vcx|vb)proj)\"" , RegexOptions.Compiled);Idelson
Can anyone explain why you need IsPathRooted here? Not sure why a project would ever be rooted, because I've never seen such a solution file.Trichinosis
P
13

The trick is to choose the right MsBuild.dll. Under VS2017 it is indeed "C:\Program Files (x86)\Microsoft Visual Studio\2017\Professional\MSBuild\15.0\Bin\amd64\Microsoft.Build.dll" (Dont use the standard Msbuild ddl in references. Browse to this path)

c#:

var solutionFile =    
SolutionFile.Parse(@"c:\NuGetApp1\NuGetApp1.sln");//your solution full path name
var projectsInSolution = solutionFile.ProjectsInOrder;
foreach(var project in projectsInSolution)
{
   switch (project.ProjectType)
   {
      case SolutionProjectType.KnownToBeMSBuildFormat:
     {
         break;
     }
     case SolutionProjectType.SolutionFolder:
     {
         break;
     }
  }
}

powershell:

Add-Type -Path (${env:ProgramFiles(x86)} + '\Microsoft Visual 
Studio\2017\Professional\MSBuild\15.0\Bin\amd64\Microsoft.Build.dll')

$slnPath = 'c:\NuGetApp1\NuGetApp1.sln'
$slnFile = [Microsoft.Build.Construction.SolutionFile]::Parse($slnPath)
$pjcts = $slnFile.ProjectsInOrder

foreach ($item in $pjcts)
{

    switch($item.ProjectType)
    {
        'KnownToBeMSBuildFormat'{Write-Host Project  : $item.ProjectName}
        'SolutionFolder'{Write-Host Solution Folder : $item.ProjectName}
    }
}  
Primogenitor answered 1/4, 2018 at 16:42 Comment(0)
F
12

You can use the EnvDTE.Solution.Projects object to programmatically get access to the projects in a solution.

One gotcha though is that if you have any SolutionFolders in your solution, any projects in these folders are not shown in the above collection.

I've written an article including a code sample on how to get all projects regardless of any solutionfolders

Floro answered 2/4, 2011 at 14:1 Comment(3)
This can only be used in a VS extension, so it useless for anybody who wants a stand alone tool for reading source projects in a solution.Benner
You can get a reference to a running instance of VS or you can access $dte from the package manager console. If you dont have VS running at all then you need an alternative solution. The new MSBuild packages now contain classes for parsing solution and project files but these are still pre-RTMFloro
updated link: wwwlicious.com/envdte-getting-all-projects-htmlShoemaker
H
10

Currently you can use Package Manager Console in VS to obtain that info. Use powershell Get-Project command

Get-Project -All
Howells answered 12/12, 2015 at 18:9 Comment(2)
Which Visual Studio version ?Obie
This gets the full project name for really long project names and sorts the output too: Get-Project -All | Select-Object ProjectName,FullName | Sort-Object -Property ProjectNameDecimal
N
7

from powershelll and in the solution's folder write

dotnet sln list

Nunciata answered 3/3, 2022 at 13:7 Comment(0)
H
5

just read the list from *.sln file. There are "Project"-"EndProject" sections.
Here is an article from MSDN.

Howdy answered 27/9, 2010 at 8:14 Comment(2)
@Obie I'm afraid I didn't understand your commentHowdy
not any Parser C# class for read sln files ? Similar like #707607 #1243522Obie
S
3

If you write your program as Visual Studio Add-in you can access the EnvDTE to find out all the projects within the currently opened solution.

Sonnie answered 27/9, 2010 at 8:20 Comment(0)
E
3

There's a really elegant solution here: Parsing Visual Studio Solution files

The answer by John Leidegren involves wrapping the internal Microsoft.Build.Construction.SolutionParser class.

Eskimo answered 28/2, 2013 at 2:39 Comment(0)
S
3

Since Visual Studio 2013 the Microsoft.Build.dll provides a SolutionFile object with some very handy functions.

Here's an example of using the v14.0 version to list the relative path of all the projects in the order they appear in the solution.

Add-Type -Path (${env:ProgramFiles(x86)} + '\Reference Assemblies\Microsoft\MSBuild\v14.0\Microsoft.Build.dll')
$solutionFile = '<FULL PATH TO SOLUTION FILE>'
$solution = [Microsoft.Build.Construction.SolutionFile] $solutionFile
($solution.ProjectsInOrder | Where-Object {$_.ProjectType -eq 'KnownToBeMSBuildFormat'}).RelativePath

There are plenty of other properties on the project object (ProjectName, AbsolutePath, configurations etc) that may be of use. In the above example I used the ProjectType to filter out Solution Folders.

Schenk answered 7/12, 2016 at 5:14 Comment(1)
For VS2017, it is under VS2017 "C:\Program Files (x86)\Microsoft Visual Studio\2017\Professional\MSBuild\15.0\Bin\amd64\Microsoft.Build.dll" And annoying, but for sqlprojs files, project type is Unknown [SolutionProjectType]::UnknownBrassy
T
2

I know that this is maybe already answered question, but I would like to share my approach of reading sln file. Also during run time I am determining if project is Test project or not

function ReadSolutionFile($solutionName)
{
    $startTime = (Get-Date).Millisecond
    Write-Host "---------------Read Start---------------" 
    $solutionProjects = @()

    dotnet  sln "$solutionName.sln" list | ForEach-Object{     
        if($_  -Match ".csproj" )
        {
            #$projData = ($projectString -split '\\')

            $proj = New-Object PSObject -Property @{

                Project = [string]$_;
                IsTestProject =   If ([string]$_ -Match "test") {$True} Else {$False}  
            }

            $solutionProjects += $proj

        }
    }

    Write-Host "---------------Read finish---------------" 
    $solutionProjects

    $finishTime = (Get-Date).Millisecond
    Write-Host "Script run time: $($finishTime-$startTime) mil" 
}

Hope this will be helpfull.

Tungusic answered 13/11, 2019 at 17:52 Comment(0)
P
1

If you need to do this on a non Windows machine, you can use the following Bash command:

grep "Project(" NameOfYourSolution.sln | cut -d'"' -f4

Pronation answered 24/6, 2016 at 22:20 Comment(0)
A
0

To expand on the answer by @brianpeiris:

Function Global:Get-ProjectInSolution {
    [CmdletBinding()] param (
        [Parameter()][string]$Solution
    )
    $SolutionPath = Join-Path (Get-Location) $Solution
    $SolutionFile = Get-Item $SolutionPath
    $SolutionFolder = $SolutionFile.Directory.FullName

    Get-Content $Solution |
        Select-String 'Project\(' |
        ForEach-Object {
            $projectParts = $_ -Split '[,=]' | ForEach-Object { $_.Trim('[ "{}]') }
            [PSCustomObject]@{
                File = $projectParts[2]
                Guid = $projectParts[3]
                Name = $projectParts[1]
            }
        } |
        Where-Object File -match "csproj$" |
        ForEach-Object {
            Add-Member -InputObject $_ -NotePropertyName FullName -NotePropertyValue (Join-Path $SolutionFolder $_.File) -PassThru
        }
}

This filters to only .csproj files and adds the full path of each based on the File field and the path containing the sln file.

Use Get-ProjectInSolution MySolution.sln | Select-Object FullName to get each of the full file paths.

The reason I wanted the full path was to be able to access the packages.config files beside each project file and then get the packages from all of them:

Get-ProjectInSolution MySolution.sln |
    %{Join-Path ($_.FullName | Split-Path) packages.config} |
    %{select-xml "//package[@id]" $_ | %{$_.Node.GetAttribute("id")}} |
    select -unique
Assent answered 20/8, 2020 at 14:33 Comment(0)
B
0

Here is a modified approach I used to look at the problem from a Solution-first stance:

Function Get-ProjectReferences ($rootFolder) {
    $ns = @{ defaultNamespace = "http://schemas.microsoft.com/developer/msbuild/2003" }
    $solutionFilesWithContent = Get-ChildItem $rootFolder -Filter *.sln -Recurse |
    ForEach-Object {
        New-Object PSObject -Property @{
            SolutionFile    = $_;
            SolutionContent = Get-Content $_;
        }
    }
    $projectFilesWithContent = Get-ChildItem $rootFolder -Filter *.csproj -Recurse |
    ForEach-Object {
        New-Object PSObject -Property @{
            ProjectFile    = $_;
            ProjectContent = [xml](Get-Content $_);
        }  
    }

    $solutionFilesWithContent | ForEach-Object {
        $solutionFileWithContent = $_
        $projectsInSolutionStrings = $solutionFileWithContent.SolutionContent | Select-String 'Project\('
        $projectsInSolution = $projectsInSolutionStrings |
        ForEach-Object {
            $projectParts = $_ -Split '[,=]' | ForEach-Object { $_.Trim('[ "{}]') };
            if ($projectParts[2].Contains(".csproj")) {
                New-Object PSObject -Property @{
                    Name = $projectParts[1];
                    File = $projectParts[2];
                    Guid = $projectParts[3];
                }                    
            }
        }

        $projectsInSolution | ForEach-Object {
            $projectFileSearchName = $_.Name + ".csproj"
            $projectInSolutionFile = $projectFilesWithContent | Where-Object { $_.ProjectFile.Name -eq $projectFileSearchName } | Select-Object -First 1
            if (($null -eq $projectInSolutionFile) -and ($null -eq $projectInSolutionFile.ProjectContent)) {
                Write-Host "Project was null"
            }
            else {
                $projectInSolutionName = $projectInSolutionFile.ProjectFile | Select-Object -ExpandProperty BaseName
                $projectReferences = $projectInSolutionFile.ProjectContent | Select-Xml '//defaultNamespace:ProjectReference/defaultNamespace:Name' -Namespace $ns | Select-Object -ExpandProperty Node | Select-Object -ExpandProperty "#text"
                $projectTarget = $projectInSolutionFile.ProjectContent | Select-Xml "//defaultNamespace:TargetFrameworkVersion" -Namespace $ns | Select-Object -ExpandProperty Node | Select-Object -ExpandProperty "#text"
        
                $projectReferences | ForEach-Object {
                    $projectFileName = $_ + ".csproj"
                    $referenceProjectFile = $projectFilesWithContent | Where-Object { $_.ProjectFile.Name -eq $projectFileName } | Select-Object -First 1
                    if ($null -eq $referenceProjectFile) {
                        $referenceProjectTarget = "Unknown"
                    }
                    else {
                        $referenceProjectTarget = $referenceProjectFile.ProjectContent | Select-Xml "//defaultNamespace:TargetFrameworkVersion" -Namespace $ns | Select-Object -ExpandProperty Node | Select-Object -ExpandProperty "#text"                    
                    }
                    "[" + $solutionFileWithContent.SolutionFile.Name + "] -> [" + $projectInSolutionName + " " + $projectTarget + "] -> [" + $_ + " " + $referenceProjectTarget + "]"
                }
            }
        }
    }
}

Get-ProjectReferences "C:\src\repos\MyRepo" | Out-File "C:\src\repos\FrameworkDependencyAnalysis\FrameworkDependencyAnalysis.txt"
Bituminous answered 15/3, 2022 at 21:50 Comment(2)
For Net Framework or Net Core (Net 5, 6,...) ?Obie
In this case I was focused on .NET Framework, because my department has a large inventory of .NET Framework projects still targeting 4.5.* and we're starting an effort to move them to 4.8.Bituminous

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