pass variable number of arguments in scala (2.8) case class to parent constructor
Asked Answered
G

2

9

I was experimenting with variable constructor arguments for case classes in Scala, but am unable to pass them to the constructor of a case classes' parent:

abstract case class Node(val blocks: (Node => Option[Node])*)
case class Root(val elementBlocks: (Node => Option[Node])*) extends Node(elementBlocks)

the above doesn't compile... is it actually possible to do this?

Galateah answered 2/11, 2009 at 9:55 Comment(3)
sure, didn't have time to look at the answers earlier.Galateah
possible duplicate of How to pass List to Int* method in scala?Impale
I've marked a new one question as parent question cause it's ask for general case, not only for case classesImpale
R
8

This works with 2.7:

abstract case class A(val a: String*)
case class B(val b: String*) extends A(b:_*)

Should work with 2.8.

Ravage answered 2/11, 2009 at 11:15 Comment(1)
Actually, case class inheritance is bound for being disallowed.Sect
W
21

You need to use the :_* syntax which means "treat this sequence as a sequence"! Otherwise, your sequence of n items will be treated as a sequence of 1 item (which will be your sequence of n items).

def funcWhichTakesSeq(seq: Any*) = println(seq.length + ": " + seq)

val seq = List(1, 2, 3)
funcWhichTakesSeq(seq)      //1: Array(List(1, 2, 3)) -i.e. a Seq with one entry
funcWhichTakesSeq(seq: _*)  //3: List(1, 2, 3)
Wilser answered 2/11, 2009 at 11:38 Comment(0)
R
8

This works with 2.7:

abstract case class A(val a: String*)
case class B(val b: String*) extends A(b:_*)

Should work with 2.8.

Ravage answered 2/11, 2009 at 11:15 Comment(1)
Actually, case class inheritance is bound for being disallowed.Sect

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