How to make google-test classes friends with my classes?
Asked Answered
M

5

62

I heard there is a possibility to enable google-test TestCase classes friends to my classes, thus enabling tests to access my private/protected members.

How to accomplish that?

Madgemadhouse answered 7/3, 2010 at 13:22 Comment(3)
Not an answer to this specific question, but a (controversial, to say the least) workaround for the same problem: one can always #define private public before including the definition of the class being tested.Axes
@Axes the #define private public solution may not always be applicable as you may link against the actual unit (i.e. built without this re-#definition) possibly leading to missing linker symbols. In this case the FRIEND_TEST solution can help. All in all I would also recommend restricting the use of either solution to legacy code that can't / shouldn't be refactored. New code shall be directly designed for testability.Visit
"Free your functions! by Klaus Iglberger" introduces a different way of thinking. It helped me a lot.Skillless
S
63

Try this (straight from Google Test docs...):

FRIEND_TEST(TestCaseName, TestName);

For example:

// foo.h
#include <gtest/gtest_prod.h>

// Defines FRIEND_TEST.
class Foo {
  ...
 private:
  FRIEND_TEST(FooTest, BarReturnsZeroOnNull);
  int Bar(void* x);
};

// foo_test.cc
...
TEST(FooTest, BarReturnsZeroOnNull) {
  Foo foo;
  EXPECT_EQ(0, foo.Bar(NULL));
  // Uses Foo's private member Bar().
}
Soughtafter answered 7/3, 2010 at 13:38 Comment(6)
What about if I have another test for instance BarReturnsOneOnSth. Do I have to add another FRIEND_TEST declaration for that test too?Madgemadhouse
Yes. Each test is technically a class, and you need to befriend them one at a time.Soughtafter
How can I do it in a way which does not force me to include googletest header files in the header file with class Foo?Ovipositor
@quant_dev: Refer to Ralfizzle's answer for doing it without including it the gtest header.Jussive
Note that test and to be tested class have to be in the same namespace, as explained in googletest gtest_prod.hOaks
Here's the documentation for how to use FRIEND_TEST(), and here's the definition for the FRIEND_TEST macro.Bravo
E
43

I know this is old but I was searching for the same answer today. "gtest_prod.h" just introduces a simple macro to reference test classes.

#define FRIEND_TEST(test_case_name, test_name)\
friend class test_case_name##_##test_name##_Test

So FRIEND_TEST(FooTest, BarReturnsZeroOnNull); is equivalent to:

friend class FooTest_BarReturnsZeroOnNull_Test;

This works because each test is its own class as mentioned in the previous answer.

E answered 8/10, 2012 at 16:18 Comment(0)
H
12

A far better strategy is to not allow friend tests among your unit tests.

Allowing friend tests accessing private members will lead to a code base that is hard to maintain. Tests that break whenever a component's inner implementation details are refactored is not what you want. If extra effort is instead put into getting a design where components can be tested through their public interface, you will get tests that only need updating whenever the public interface of a component is updated.

Tests relying on gtest/gtest_prod.h should be seen as a sign of poor design.

Holierthanthou answered 18/4, 2017 at 17:30 Comment(6)
I understand that this is controversial (hopefully it earned you some kind of "controversial answer" badge <grin>), but I am glad someone brought up this viewpoint. Many agree with @Martin on this! dzone.com/articles/principles-creatingLidialidice
This is true in general, but for UI testing (thinking of QT) you'll often want to get at child widgets that wouldn't normally be exposed. For example I need to check that when a button is pressed a widget becomes visible. The widget normally would not be exposed publicly.Gentianella
There are tradeoffs along various axes in developing testing strategies. The advantage you point to is valid, but that doesn't mean using friend for testing is always a bad idea.Mordvin
I think this is very application dependent, in some cases I can see your point. If you, however, consider for example HPC/scientific computing applications this would not be a sign of poor design. In many cases, the interface to a solver is made very simple - .solve(), but relies on complicated mathematics and solving of governing equations. These equations will be broken into smaller private functions, which you would definitely want to unit test.Philodendron
@BevanJones, that sounds like bad design to me. Anyways, of course we often have a system that has both good and bad sides to it. And often it's not reasonable to suggest that it should be re-written from scratch to make it more testable or whatever. That's reality, but it's still a sign of poor design choices. Not necessarily yours.Holierthanthou
@Martin G What would be considered better designs? Only potential options that immediately come to mind would be 1) exposing the private methods just for test (bad?), 2) keeping all the code in one big .solve() method (bad?), 3) moving the private functions to a helper class or some equivalent. Option 3 may be a better solution IFF the private helper functions are meaningful elsewhere which is not a guarantee.Radiance
I
10

When your tested class and your test class are in a different namespace (e.g. your tests are in the global namespace), you may need to forward-declare your test class and add your namespace prefix in FRIEND_TEST:

// foo.h
#include <gtest/gtest_prod.h>

// forward-declaration of test class
class FooTest_BarReturnsZeroOnNull_Test; 

// Defines FRIEND_TEST.
class my_namespace::Foo {
    ...
private:
    // Specify the global namespace (`::`) in the `FRIEND_TEST()` usage
    FRIEND_TEST(::FooTest, BarReturnsZeroOnNull);
    int Bar(void* x);
};

// forward-declaration of this namespace from foo_test.cc
using namespace my_namespace;

...
TEST(FooTest, BarReturnsZeroOnNull) {
    Foo foo;
    EXPECT_EQ(0, foo.Bar(NULL));
    // Uses Foo's private member Bar().
}

I know that friend unit tests (or the friendliness in C++ in general) and white-box testing are a controversial subject, but when you work on complex, scientific algorithms, each step of which you need to test and validate, but that you don't want to expose in public (or even protected) interfaces, friend tests appear to me as a simple and pragmatic solution, especially in a test-driven development approach. It is always possible to refactor the code later (or to completely remove white-box tests) if it's against one's religion to use the friendliness or white-box testing.

Irishirishism answered 16/7, 2019 at 9:8 Comment(2)
This answer points one important thing other answers missed and save my world: the namespace matters quite a lot when using friend class.Bobwhite
Forward declaration might not be enough.Countermine
I
0

If you don't want to have to individually list each test case with FRIEND_TEST, another option is to define a test fixture class and then friend that instead:

class Foo
{
    ...
private:
    friend class FooTest;
};
...
class FooTest : public ::testing::Test
{
protected:
    int AccessPrivateFooThing(Foo& foo) { ... }    
    ...
};
...
TEST_F(FooTest, PrivateThing)
{
   ...
   int result = AccessPrivateFooThing(foo);
   ...
}

However a caveat with this is that only methods defined in the test fixture itself will have access to Foo's private members; the tests themselves will not. You'll have to define accessors, bouncers, or other helper methods within the fixture where that access is required. This requires a bit more boilerplate than some other solutions, but is also more explicit, which hopefully discourages too much reaching into internals.

If you encounter issues with namespaces, simply ensure that the test fixture is in the same namespace as the class in question; this is a good practice anyway.

It's still strongly encouraged to test only public members where reasonably feasible, though I do agree that there are some times where this makes more sense.

Isabelisabelita answered 20/5 at 6:32 Comment(0)

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