I would like to check, if a date is today, tomorrow, yesterday or else. But my code doesn't work.
Code:
$timestamp = "2014.09.02T13:34";
$date = date("d.m.Y H:i");
$match_date = date('d.m.Y H:i', strtotime($timestamp));
if($date == $match_date) {
//Today
} elseif(strtotime("-1 day", $date) == $match_date) {
//Yesterday
} elseif(strtotime("+1 day", $date) == $match_date) {
//Tomorrow
} else {
//Sometime
}
The Code always goes in the else case.
First. You have mistake in using function strtotime see PHP documentation
int strtotime ( string $time [, int $now = time() ] )
You need modify your code to pass integer timestamp into this function.
Second. You use format d.m.Y H:i that includes time part. If you wish to compare only dates, you must remove time part, e.g. `$date = date("d.m.Y");``
Third. I am not sure if it works in the same way for you, but my PHP doesn't understand date format from $timestamp and returns 01.01.1970 02:00 into $match_date
$timestamp = "2014.09.02T13:34";
date('d.m.Y H:i', strtotime($timestamp)) === "01.01.1970 02:00";
You need to check if strtotime($timestamp) returns correct date string. If no, you need to specify format which is used in $timestamp variable. You can do this using one of functions date_parse_from_format or DateTime::createFromFormat
This is a work example:
$timestamp = "2014.09.02T13:34";
$today = new DateTime("today"); // This object represents current date/time with time set to midnight
$match_date = DateTime::createFromFormat( "Y.m.d\\TH:i", $timestamp );
$match_date->setTime( 0, 0, 0 ); // set time part to midnight, in order to prevent partial comparison
$diff = $today->diff( $match_date );
$diffDays = (integer)$diff->format( "%R%a" ); // Extract days count in interval
switch( $diffDays ) {
case 0:
echo "//Today";
break;
case -1:
echo "//Yesterday";
break;
case +1:
echo "//Tomorrow";
break;
default:
echo "//Sometime";
}
case would lead to the "sometimes" in your switch? Only when $today or $match_date don't properly format as dates, maybe? –
Justification $today can be defined as just new DateTime("today"), which means today at midnight -- the time part will be automatically zeroed out. –
Womera (integer)$diff->format( "%R%a" ) == 0 on its own is inaccurate. It is true for the same day ten years ago too. Check $diff->days == 0 for today, and $diff->days == 1 with $diff->invert for yesterday / tomorrow. –
Jenkins <?php
$current = strtotime(date("Y-m-d"));
$date = strtotime("2014-09-05");
$datediff = $date - $current;
$difference = floor($datediff/(60*60*24));
if($difference==0)
{
echo 'today';
}
else if($difference > 1)
{
echo 'Future Date';
}
else if($difference > 0)
{
echo 'tomorrow';
}
else if($difference < -1)
{
echo 'Long Back';
}
else
{
echo 'yesterday';
}
?>
I think this will help you:
<?php
$date = new DateTime();
$match_date = new DateTime($timestamp);
$interval = $date->diff($match_date);
if($interval->days == 0) {
//Today
} elseif($interval->days == 1) {
if($interval->invert == 0) {
//Yesterday
} else {
//Tomorrow
}
} else {
//Sometime
}
Simple one liners for today/yesterday/tomorrow:
$someDate = '2021-11-07'; // date in any format
$isToday = date('Ymd') == date('Ymd', strtotime($someDate));
$isYesterday = date('Ymd') == date('Ymd', strtotime($someDate) + 86400);
$isTomorrow = date('Ymd') == date('Ymd', strtotime($someDate) - 86400);
There is no built-in functions to do that in Php (shame ^^). You want to compare a date string to today, you could use a simple substr to achieve it:
if (substr($timestamp, 0, 10) === date('Y.m.d')) { today }
elseif (substr($timestamp, 0, 10) === date('Y.m.d', strtotime('-1 day')) { yesterday }
No date conversion, simple.
function getRangeDateString($timestamp) {
if ($timestamp) {
$currentTime=strtotime('today');
// Reset time to 00:00:00
$timestamp=strtotime(date('Y-m-d 00:00:00',$timestamp));
$days=round(($timestamp-$currentTime)/86400);
switch($days) {
case '0';
return 'Today';
break;
case '-1';
return 'Yesterday';
break;
case '-2';
return 'Day before yesterday';
break;
case '1';
return 'Tomorrow';
break;
case '2';
return 'Day after tomorrow';
break;
default:
if ($days > 0) {
return 'In '.$days.' days';
} else {
return ($days*-1).' days ago';
}
break;
}
}
}
Pass the date into the function.
<?php
function getTheDay($date)
{
$curr_date=strtotime(date("Y-m-d H:i:s"));
$the_date=strtotime($date);
$diff=floor(($curr_date-$the_date)/(60*60*24));
switch($diff)
{
case 0:
return "Today";
break;
case 1:
return "Yesterday";
break;
default:
return $diff." Days ago";
}
}
?>
date('Y-m-d') then it will be comparing midnight on each day and they will either be equal or a multiple of 24 hours apart. Technically, you then wouldn't need the floor() function either. –
Saguaro Here is a more polished version of the accepted answer. It accepts only timestamps and returns a relative date or a formatted date string for everything +/-2 days
<?php
/**
* Relative time
*
* date Format http://php.net/manual/en/function.date.php
* strftime Format http://php.net/manual/en/function.strftime.php
* latter can be used with setlocale(LC_ALL, 'de_DE@euro', 'de_DE', 'deu_deu');
*
* @param timestamp $target
* @param timestamp $base start time, defaults to time()
* @param string $format use date('Y') or strftime('%Y') format string
* @return string
*/
function relative_time($target, $base = NULL, $format = 'Y-m-d H:i:s')
{
if(is_null($base)) {
$base = time();
}
$baseDate = new DateTime();
$targetDate = new DateTime();
$baseDate->setTimestamp($base);
$targetDate->setTimestamp($target);
// don't modify original dates
$baseDateTemp = clone $baseDate;
$targetDateTemp = clone $targetDate;
// normalize times -> reset to midnight that day
$baseDateTemp = $baseDateTemp->modify('midnight');
$targetDateTemp = $targetDateTemp->modify('midnight');
$interval = (int) $baseDateTemp->diff($targetDateTemp)->format('%R%a');
d($baseDate->format($format));
switch($interval) {
case 0:
return (string) 'today';
break;
case -1:
return (string) 'yesterday';
break;
case 1:
return (string) 'tomorrow';
break;
default:
if(strpos($format,'%') !== false )
{
return (string) strftime($format, $targetDate->getTimestamp());
}
return (string) $targetDate->format($format);
break;
}
}
setlocale(LC_ALL, 'de_DE@euro', 'de_DE', 'deu_deu');
echo relative_time($weather->time, null, '%A, %#d. %B'); // Montag, 6. August
echo relative_time($weather->time, null, 'l, j. F'); // Monday, 6. August
This worked for me, where I wanted to display keyword "today" or "yesterday" only if date was today and previous day otherwise display date in d-M-Y format
<?php
function findDayDiff($date){
$param_date=date('d-m-Y',strtotime($date);
$response = $param_date;
if($param_date==date('d-m-Y',strtotime("now"))){
$response = 'Today';
}else if($param_date==date('d-m-Y',strtotime("-1 days"))){
$response = 'Yesterday';
}
return $response;
}
?>
function get_when($date) {
$current = strtotime(date('Y-m-d H:i'));
$date_diff = $date - $current;
$difference = round($date_diff/(60*60*24));
if($difference >= 0) {
return 'Today';
} else if($difference == -1) {
return 'Yesterday';
} else if($difference == -2 || $difference == -3 || $difference == -4 || $difference == -5) {
return date('l', $date);
} else {
return ('on ' . date('jS/m/y', $date));
}
}
get_when(date('Y-m-d H:i', strtotime($your_targeted_date)));
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$timestampdefined and where? – Vladamar"2014.09.02T13:34"– Savino