Convert a File Object to Bitmap

Question

I am using Universal-Image-Loader and there is this functionality that access the file cache of the image from sd card. But I don't know how to convert the returned file cache into bitmap. Basically I just wanted to assign the bitmap to an ImageView.

File mSaveBit = imageLoader.getDiscCache().get(easyPuzzle);

Log.d("#ImageValue: ", ""+mSaveBit.toString());
mImageView.setImageBitmap(mSaveBit);

Error: "The method setImageBitmap(Bitmap) in the type ImageView is not applicable for the arguments (File)"

Angio

use bitmapfactory to create bitmap from file – Kiushu

@PulkitSethi Can you show me how to do that, not sure of this. most examples uses path string of the image. In my case I am using the file itself. – Angio

Answer 1

You should be able to use BitmapFactory:

File mSaveBit; // Your image file
String filePath = mSaveBit.getPath();  
Bitmap bitmap = BitmapFactory.decodeFile(filePath);
mImageView.setImageBitmap(bitmap);

Appose

I got error: The method decodeFile(String) in the type BitmapFactory is not applicable for the arguments (File) – Angio

Updated my answer, sorry, missed the getPath() method. – Appose

@Appose Please add description when answering questions so that everybody can understand your answer, i.e. here, what is type of filePath, mSaveBit, it can be known from the question but still its a good habbit, well good answer (upvoted). – Duda

returning null in android 10 – Leander

Answer 2

1. Define File

   String fileName = "/myImage.jpg";
   File file = new File(fileName); 
   

2. get Bitmap of Image

   Bitmap bitmap = BitmapFactory.decodeFile(file.getAbsolutePath());
   

3. Set Bitmap to ImageView

   myImageView.setImageBitmap(bitmap);
   

Glengarry

Answer 3

You can use this function to get Bitmap from file path

fun getBitmap(filePath:String):Bitmap?{
    var bitmap:Bitmap?=null
    try{
        var f:File = File(path)
        var options = BitmapFactory.Options()
        options.inPreferredConfig = Bitmap.Config.ARGB_8888
        bitmap = BitmapFactory.decodeStream(FileInputStream(f),null,options)
    }catch (e:Exception){

    }
    return bitmap
}

Dracula

Answer 4

Here is a simple code to create a scaled image for ImageView in this case - Width:400 - Height:400

final File file = new File(Environment.getExternalStorageDirectory(),"b.jpg");
ImageView img = (ImageView) findViewById(R.id.imageview);
img.setImageBitmap(Bitmap.createScaledBitmap(BitmapFactory.decodeFile(file.getAbsolutePath()),400,400,false));

Junket

Answer 5

Kotlin Version

  if (requestCode==PICK_IMAGE_REQUEST){
            if (data!=null){
                selectedfileUri=data.data
                if (selectedfileUri!=null && !selectedfileUri!!.path.isEmpty()){
                    val file = FileUtils.getFile(context,selectedfileUri)
                    val bitmap = BitmapFactory.decodeFile(file.path)
                    uimg!!.setImageBitmap(bitmap)
                }
            }
        }

Bybee

Answer 6

This is not the right question, but if you use flag .cacheInMemory() in ImageLoader setup you can retrive the bitmap without need of recreate at any time using BitmapFactory to safe memory usage .

Just use:

Bitmap bitmap = ImageLoader.getInstance().getMemoryCache()·get("url as key");

Maisonette