Replace -inf with zero value

Question

I have an array:

x =  numpy.array([-inf, -inf, 37.49668579])

Is there a way to change the -inf values to just 0?

Mirador

Answer 1

There is:

from numpy import inf
x[x == -inf] = 0

Queue

this is around 20% faster than np.isneginf based on my test – Condominium

How are the brackets used here? Is this indexing with a conditional, or list comprehension? – Armistead

No list comprehension. It is numpy indexing using a boolean array. In this case: "Elements of x equal to -inf". – Pinnatisect

NameError: global name 'inf' is not defined – Sinister

@johnktejik did you run the import statement from numpy import inf ? – Lahey

I believe it's better to use X[~np.isfinite(X)] = 0 or x[numpy.isneginf(x)] = 0 as in the second answer – Coheman

Answer 2

Perhaps even easier and more flexible to use numpy.nan_to_num:

numpy.nan_to_num(x, neginf=0) 

Out[1]: array([ 0.        ,  0.        , 37.49668579])

Rottweiler

Answer 3

Use isneginf http://docs.scipy.org/doc/numpy/reference/generated/numpy.isneginf.html#numpy.isneginf

x[numpy.isneginf(x)] = 0

Boonie