if I create a shared library without a SONAME like this
gcc -shared libfoo.o -o libfoo.so
and link against it, how does the linker find my shared library?
Is the filename libfoo.so
considered as default SONAME by the linker?
if I create a shared library without a SONAME like this
gcc -shared libfoo.o -o libfoo.so
and link against it, how does the linker find my shared library?
Is the filename libfoo.so
considered as default SONAME by the linker?
I think you're right. Here what ld man pages say:
-soname=name
When creating an ELF shared object, set the internal DT_SONAME field to the specified name. When an executable is linked with a shared object which has a DT_SONAME field, then when the executable is run the dynamic linker will attempt to load the shared object specified by the DT_SONAME field rather than the using the file name given to the linker.
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