C++ Equivalent of %ld in Java for String.format()

Question

For instance, %11.2lf in C++ becomes %11.2f in Java. How about for long format?

Judsonjudus

Answer 1

As you may have worked out, it's not necessary to specify the l flag. According to the docs, a decimal integer is specified by d just like in C++. So the answer is just %d.

Moonstone

%d wouldn't suffice if the value you are trying to print is long. In that case, you have to parse it. – Judsonjudus

@Milli: While I'm not sure about the 1st sentence (don't think signedness is a consideration), I just confirmed experimentally that %d will correctly format longs! – Chablis

You are RIGHT! My bad.. I had also String in the same statement with long.. The error was caused by the %d %d while it should have been %d %s. Thank you Andrzej! – Judsonjudus

@CarlSmotricz is correct, signedness has nothing to do with it. I cleaned up the question to remove that. – Inlier

String.format() will throw java.util.UnknownFormatConversionException at runtime if you use the 'l' flag with the 'd' flag (e.g. %ld) (demonstrated on Java 7). – Arlyne

Answer 2

Use %d for decimals (long, int). It works OK. E.g.:

System.err.println(String.format("%d", 193874120937489387L));

...will print just fine. Read up on java.util.Formatter for more details. %d will take a long, no problem.

Burdine

WORKS PERFECT!! – Orpah