What is the difference between DataFrame repartition()
and DataFrameWriter partitionBy()
methods?
I hope both are used to "partition data based on dataframe column"? Or is there any difference?
What is the difference between DataFrame repartition()
and DataFrameWriter partitionBy()
methods?
I hope both are used to "partition data based on dataframe column"? Or is there any difference?
If you run repartition(COL)
you change the partitioning during calculations - you will get spark.sql.shuffle.partitions
(default: 200) partitions. If you then call .write
you will get one directory with many files.
If you run .write.partitionBy(COL)
then as the result you will get as many directories as unique values in COL. This speeds up futher data reading (if you filter by partitioning column) and saves some space on storage (partitioning column is removed from data files).
UPDATE: See @conradlee's answer. He explains in details not only how the directories structure will look like after applying different methods but also what will be resulting number of files in both scenarios.
Watch out: I believe the accepted answer is not quite right! I'm glad you ask this question, because the behavior of these similarly-named functions differs in important and unexpected ways that are not well documented in the official spark documentation.
The first part of the accepted answer is correct: calling df.repartition(COL, numPartitions=k)
will create a dataframe with k
partitions using a hash-based partitioner. COL
here defines the partitioning key--it can be a single column or a list of columns. The hash-based partitioner takes each input row's partition key, hashes it into a space of k
partitions via something like partition = hash(partitionKey) % k
. This guarantees that all rows with the same partition key end up in the same partition. However, rows from multiple partition keys can also end up in the same partition (when a hash collision between the partition keys occurs) and some partitions might be empty.
In summary, the unintuitive aspects of df.repartition(COL, numPartitions=k)
are that
k
partitions may be empty, whereas others may contain rows from multiple partition keysThe behavior of df.write.partitionBy
is quite different, in a way that many users won't expect. Let's say that you want your output files to be date-partitioned, and your data spans over 7 days. Let's also assume that df
has 10 partitions to begin with. When you run df.write.partitionBy('day')
, how many output files should you expect? The answer is 'it depends'. If each partition of your starting partitions in df
contains data from each day, then the answer is 70. If each of your starting partitions in df
contains data from exactly one day, then the answer is 10.
How can we explain this behavior? When you run df.write
, each of the original partitions in df
is written independently. That is, each of your original 10 partitions is sub-partitioned separately on the 'day' column, and a separate file is written for each sub-partition.
I find this behavior rather annoying and wish there were a way to do a global repartitioning when writing dataframes.
df.write().repartition(COL).partitionBy(COL)
? What I'm aiming for is the partitionBy()
behavior, but with roughly the same file size and number of files as I had originally. Can this be easily accomplished? The partitionBy(date)
=> 70 files example is relevant. I would want ~10 files, one for each day, and maybe 2 or 3 for days that have more data. –
Irishirishism df.repartition(df.date, 1000)
. Many people expect each partition to contain exactly one day of data. However, some of the 1000 partitions will be empty, and other partitions will contain multiple days worth of data. Many people find that unintuitive (maybe you don't and hence the confusion). –
Mathia hash(partition_key) % N_PARTITIONS
. So the range of the hash algorithm is collapsed down into space of N_PARTITIONS
. Given that N_PARTITIONS
is often in the range of a few hundred to a few ten thousand, collisions can be common. –
Mathia df.repartition()
. However, once you specify a column, the distribution of rows to partitions depends on how many rows have each column value. Increasing dataset size won't always overcome data skew issues. Sometimes it will, but it totally depends on the idiosyncrasies of your dataset. –
Mathia If you run repartition(COL)
you change the partitioning during calculations - you will get spark.sql.shuffle.partitions
(default: 200) partitions. If you then call .write
you will get one directory with many files.
If you run .write.partitionBy(COL)
then as the result you will get as many directories as unique values in COL. This speeds up futher data reading (if you filter by partitioning column) and saves some space on storage (partitioning column is removed from data files).
UPDATE: See @conradlee's answer. He explains in details not only how the directories structure will look like after applying different methods but also what will be resulting number of files in both scenarios.
repartition()
is used to partition data in memory and partitionBy
is used to partition data on disk. They're often used in conjunction.
Both repartition()
and partitionBy
can be used to "partition data based on dataframe column", but repartition()
partitions the data in memory and partitionBy
partitions the data on disk.
repartition()
Let's play around with some code to better understand partitioning. Suppose you have the following CSV data.
first_name,last_name,country
Ernesto,Guevara,Argentina
Vladimir,Putin,Russia
Maria,Sharapova,Russia
Bruce,Lee,China
Jack,Ma,China
df.repartition(col("country"))
will repartition the data by country in memory.
Let's write out the data so we can inspect the contents of each memory partition.
val outputPath = new java.io.File("./tmp/partitioned_by_country/").getCanonicalPath
df.repartition(col("country"))
.write
.csv(outputPath)
Here's how the data is written out on disk:
partitioned_by_country/
part-00002-95acd280-42dc-457e-ad4f-c6c73be6226f-c000.csv
part-00044-95acd280-42dc-457e-ad4f-c6c73be6226f-c000.csv
part-00059-95acd280-42dc-457e-ad4f-c6c73be6226f-c000.csv
Each file contains data for a single country - the part-00059-95acd280-42dc-457e-ad4f-c6c73be6226f-c000.csv
file contains this China data for example:
Bruce,Lee,China
Jack,Ma,China
partitionBy()
Let's write out data to disk with partitionBy
and see how the filesystem output differs.
Here's the code to write out the data to disk partitions.
val outputPath = new java.io.File("./tmp/partitionedBy_disk/").getCanonicalPath
df
.write
.partitionBy("country")
.csv(outputPath)
Here's what the data looks like on disk:
partitionedBy_disk/
country=Argentina/
part-00000-906f845c-ecdc-4b37-a13d-099c211527b4.c000.csv
country=China/
part-00000-906f845c-ecdc-4b37-a13d-099c211527b4.c000
country=Russia/
part-00000-906f845c-ecdc-4b37-a13d-099c211527b4.c000
Why partition data on disk?
Partitioning data on disk can make certain queries run much faster.
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