How to silent/quiet HTTPServer and BasicHTTPRequestHandler's stderr output?

Asked 2/8, 2010 at 15:39 Answered 29/12, 2023 at 11:5

I am writing a simple http server as part of my project. Below is a skeleton of my script:

from BaseHTTPServer import HTTPServer, BaseHTTPRequestHandler

class MyHanlder(BaseHTTPRequestHandler):
    def do_GET(self):
        self.send_response(200)
        self.send_header('Content-type', 'text/html')
        self.end_headers()
        self.wfile.write('<html><body><p>OK</p></body></html>')

httpd = HTTPServer(('', 8001), MyHanlder)
httpd.serve_forever()

My question: how do I suppress the stderr log output my script produces every time a client connects to my server?

I have looked at the HTTPServer class up to its parent, but was unable to find any flag or function call to achieve this. I also looked at the BaseHTTPRequestHandler class, but could not find a clue. I am sure there must be a way. If you do, please share with me and others; I appreciate your effort.

Theretofore answered 2/8, 2010 at 15:39 Comment(1)

The more time I use Python, the more I realise just how much gibberish is involved. Take this: ``` from BaseHTTPServer import HTTPServer, BaseHTTPRequestHandler class MyHanlder(BaseHTTPRequestHandler): def do_GET(self): ``` – Mccafferty 16/2 at 21:40

155

This will probably do it:

from BaseHTTPServer import HTTPServer, BaseHTTPRequestHandler

class MyHandler(BaseHTTPRequestHandler):
    def do_GET(self):
        self.send_response(200)
        self.send_header('Content-type', 'text/html')
        self.end_headers()
        self.wfile.write('<html><body><p>OK</p></body></html>')
    def log_message(self, format, *args):
        return

httpd = HTTPServer(('', 8001), MyHandler)
httpd.serve_forever()

Reconvert answered 2/8, 2010 at 16:3 Comment(6)

This gave me such a headache because my httpserver wasn't returning anything when I ran it in the background without a tty. You are a life saver. Thanks! – Chrysa 29/4, 2015 at 7:41

@agressen, same frustration here -- and same thanks to MattH. My app is implemented as a .pyw because it's a Tkinter interface, so not having a console window was preventing any replies from being sent. – Blackface 2/1, 2020 at 17:5

you probably want to override log_request instead of log_message, since the latter is used for other types of logging including errros. – Osteo 21/9, 2020 at 4:50

Thanks for the hint, which leads me to this official doc – Frisbie 4/12, 2020 at 6:54

Note that if you still want to see errors (which you usually do), you can instead override the log_request function instead, as def log_request(self, code='-', size='-'): return. – Kelbee 15/11, 2022 at 17:38

took me a while to notice the difference – Fredrick 21/1, 2023 at 15:54

To silent/quiet HTTP Server and Basic HTTPRequestHandler stderr output, you can subclass SimpleHTTPServer.SimpleHTTPRequestHandler and override the log_message method. Here is the method you will be overriding, sans docstring:

def log_message(self, format, *args):
    sys.stderr.write("%s - - [%s] %s\n" % (
        self.address_string(), 
        self.log_date_time_string(),
        format%args)
    )

Spotter answered 29/12, 2023 at 11:5 Comment(1)

This explains @matth's answer https://mcmap.net/q/268635/-how-to-silent-quiet-httpserver-and-basichttprequesthandler-39-s-stderr-output and extends it (to show what the original code does, which might be useful). – Asthenopia 29/12, 2023 at 20:37

This answer might be late but you can also try changing/setting sys.stdout and sys.stderr

import io

stream = io.StringIO()
if (sys.stdout is None) or (sys.stderr is None):
    sys.stdout, sys.stderr = stream, stream

It worked for me.

Samaritan answered 29/12, 2023 at 11:3 Comment(0)

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