I would like to do something like this in .NET 3.5. What's the quickest way?
IEnumerable<DataRow> collection =
TypedDataSet.TypedTableBase<DataRow>.Rows as IEnumerable<DataRow>;
I would like to do something like this in .NET 3.5. What's the quickest way?
IEnumerable<DataRow> collection =
TypedDataSet.TypedTableBase<DataRow>.Rows as IEnumerable<DataRow>;
Assuming you're using .NET 4.0, which introduces covariance:
// Presumably your table is of some type deriving from TypedTableBase<T>,
// where T is an auto-generated type deriving from DataRow.
IEnumerable<DataRow> collection = myTypedTable;
The table type itself implements IEnumerable<T> where T : DataRow
.
Otherwise:
IEnumerable<DataRow> collection = myTypedTable.Cast<DataRow>();
You can call OfType<DataRow>()
on the DataRowCollection
.
IEnumerable
s it definitely isn't. –
Vining Assuming you're using .NET 4.0, which introduces covariance:
// Presumably your table is of some type deriving from TypedTableBase<T>,
// where T is an auto-generated type deriving from DataRow.
IEnumerable<DataRow> collection = myTypedTable;
The table type itself implements IEnumerable<T> where T : DataRow
.
Otherwise:
IEnumerable<DataRow> collection = myTypedTable.Cast<DataRow>();
A simple direct solution is to use the method "Select()" of a System.Data.DataTable
object, which produces DataRow[]
. From this you can treat as an IEnumerable<DataRow>
using Linq like below:
List<MyItem> items = dtItems.Select()
.Select(row => new MyItem(row))
.ToList();
Providing a useful list of objects for each row.
There is a built in extension method if you include System.Data.DataSetExtensions.dll
in to your project that adds a AsEnumerable()
method.
IEnumerable<DataRow> collection = TypedDataSet.TypedTableBase<DataRow>.AsEnumerable();
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