If I have a non for loop threaded task being run alongside tkinter such as time.sleep(seconds) how can I safely end the task before it has concluded, or, before the time.sleep() has ended.
If you run the program and click the button and then close the GUI window then finished will still print in the interpreter window a few seconds later.
Please note that in this case time.sleep() is just a placeholder for a long running non for loop function.
# python 3 imports
import tkinter as tk
import threading
import queue
import time
def center_app(toplevel):
toplevel.update_idletasks()
w = toplevel.winfo_screenwidth() - 20
h = toplevel.winfo_screenheight() - 100
size = tuple(int(Q) for Q in toplevel.geometry().split("+")[0].split("x"))
toplevel.geometry("%dx%d+%d+%d" % (size + (w / 2 - size[0] / 2, h / 2 - size[1] / 2)))
class app(tk.Tk):
def __init__(self):
tk.Tk.__init__(self)
self.protocol("WM_DELETE_WINDOW", self.USER_HAS_CLOSED_WINDOW)
self.b1 = tk.Button(self, text = "*** Start Thread ***", font = ("Arial",25,"bold"), command = self.func_1)
self.b1.pack(side = "top", fill = "both", expand = True)
center_app(self)
self.queue = queue.Queue()
def USER_HAS_CLOSED_WINDOW(self, callback = None):
print ("attempting to end thread")
# end the running thread
self.destroy()
def func_1(self):
self.b1.config(text = " Thread Running ")
self.b1.update_idletasks()
t = ThreadedFunction(self.queue).start()
self.after(50, self.check_queue)
def check_queue(self):
try:
x = self.queue.get(0) # check if threaded function is done
self.b1.config(text = "*** Start Thread ***")
self.b1.update_idletasks()
except:
self.after(50, self.check_queue)
class ThreadedFunction(threading.Thread):
def __init__(self, queue):
threading.Thread.__init__(self, daemon = True)
self.queue = queue
def run(self):
time.sleep(10) # how to end this if user closes GUI
print ("finished")
self.queue.put("result")
a = app()
a.mainloop()
I have made a function USER_HAS_CLOSED_WINDOW to catch the user closing the window, where I was thinking I would put something to end the running thread, but I'm not sure how.
I guess the other option is to put an appropriate timeout on the thread and use .join() somehow. But I'm not sure how to do that either