To associate Lambda expression each other:
An other way is to use the following code. It s more flexible than the Schotime answer in my advice and work perfectly. No external Nuggets needed
Framework 4.0
// Usage first.Compose(second, Expression.And)
public static Expression<T> Compose<T>(this Expression<T> First, Expression<T> Second, Func<Expression, Expression, Expression> Merge)
{
// build parameter map (from parameters of second to parameters of first)
Dictionary<ParameterExpression,ParameterExpression> map = First.Parameters.Select((f, i) => new { f, s = Second.Parameters[i] }).ToDictionary(p => p.s, p => p.f);
// replace parameters in the second lambda expression with parameters from the first
Expression secondBody = ParameterRebinder.ReplaceParameters(map, Second.Body);
// apply composition of lambda expression bodies to parameters from the first expression
return Expression.Lambda<T>(Merge(First.Body, secondBody), First.Parameters);
}
public static Expression<Func<T, bool>> And<T>(this Expression<Func<T, bool>> First, Expression<Func<T, bool>> Second)
{
return First.Compose(Second, Expression.And);
}
public static Expression<Func<T, bool>> Or<T>(this Expression<Func<T, bool>> First, Expression<Func<T, bool>> second)
{
return First.Compose(second, Expression.Or);
}
public class ParameterRebinder : ExpressionVisitor
{
private readonly Dictionary<ParameterExpression, ParameterExpression> map;
public ParameterRebinder(Dictionary<ParameterExpression, ParameterExpression> map)
{
this.map = map ?? new Dictionary<ParameterExpression, ParameterExpression>();
}
public static Expression ReplaceParameters(Dictionary<ParameterExpression, ParameterExpression> map, Expression exp)
{
return new ParameterRebinder(map).Visit(exp);
}
protected override Expression VisitParameter(ParameterExpression p)
{
ParameterExpression replacement;
if (map.TryGetValue(p, out replacement))
{
p = replacement;
}
return base.VisitParameter(p);
}
}