How to send json data in the Http request using NSURLRequest
Asked Answered
R

8

80

I'm new to objective-c and I'm starting to put a great deal of effort into request/response as of recent. I have a working example that can call a url (via http GET) and parse the json returned.

The working example of this is below

- (void)connection:(NSURLConnection *)connection didReceiveResponse:(NSURLResponse *)response {
    [responseData setLength:0];
}

- (void)connection:(NSURLConnection *)connection didReceiveData:(NSData *)data {
    [responseData appendData:data];
}

- (void)connection:(NSURLConnection *)connection didFailWithError:(NSError *)error {
  NSLog([NSString stringWithFormat:@"Connection failed: %@", [error description]]);
}

- (void)connectionDidFinishLoading:(NSURLConnection *)connection {
    [connection release];
  //do something with the json that comes back ... (the fun part)
}

- (void)viewDidLoad
{
  [self searchForStuff:@"iPhone"];
}

-(void)searchForStuff:(NSString *)text
{
  responseData = [[NSMutableData data] retain];
    NSURLRequest *request = [NSURLRequest requestWithURL:[NSURL URLWithString:@"http://www.whatever.com/json"]];
    [[NSURLConnection alloc] initWithRequest:request delegate:self];
}

My first question is - will this approach scale up? Or is this not async (meaning I block the UI thread while the app is waiting for the response)

My second question is - how might I modify the request part of this to do a POST instead of GET? Is it simply to modify the HttpMethod like so?

[request setHTTPMethod:@"POST"];

And finally - how do I add a set of json data to this post as a simple string (for example)

{
    "magic":{
               "real":true
            },
    "options":{
               "happy":true,
                "joy":true,
                "joy2":true
              },
    "key":"123"
}

Thank you in advance

Rearward answered 16/12, 2010 at 2:30 Comment(1)
Here is a tutorial: mobileorchard.com/tutorial-json-over-http-on-the-iphoneCortez
C
104

Here's what I do (please note that the JSON going to my server needs to be a dictionary with one value (another dictionary) for key = question..i.e. {:question => { dictionary } } ):

NSArray *objects = [NSArray arrayWithObjects:[[NSUserDefaults standardUserDefaults]valueForKey:@"StoreNickName"],
  [[UIDevice currentDevice] uniqueIdentifier], [dict objectForKey:@"user_question"],     nil];
NSArray *keys = [NSArray arrayWithObjects:@"nick_name", @"UDID", @"user_question", nil];
NSDictionary *questionDict = [NSDictionary dictionaryWithObjects:objects forKeys:keys];

NSDictionary *jsonDict = [NSDictionary dictionaryWithObject:questionDict forKey:@"question"];
          
NSString *jsonRequest = [jsonDict JSONRepresentation];

NSLog(@"jsonRequest is %@", jsonRequest);

NSURL *url = [NSURL URLWithString:@"https://xxxxxxx.com/questions"];

NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url
             cachePolicy:NSURLRequestUseProtocolCachePolicy timeoutInterval:60.0];


NSData *requestData = [jsonRequest dataUsingEncoding:NSUTF8StringEncoding];

[request setHTTPMethod:@"POST"];
[request setValue:@"application/json" forHTTPHeaderField:@"Accept"];
[request setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
[request setValue:[NSString stringWithFormat:@"%d", [requestData length]] forHTTPHeaderField:@"Content-Length"];
[request setHTTPBody: requestData];

NSURLConnection *connection = [[NSURLConnection alloc]initWithRequest:request delegate:self];
if (connection) {
 receivedData = [[NSMutableData data] retain];
}

The receivedData is then handled by:

NSString *jsonString = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];
NSDictionary *jsonDict = [jsonString JSONValue];
NSDictionary *question = [jsonDict objectForKey:@"question"];

This isn't 100% clear and will take some re-reading, but everything should be here to get you started. And from what I can tell, this is asynchronous. My UI is not locked up while these calls are made.

Calotte answered 17/12, 2010 at 1:11 Comment(10)
Everything looks good except the this line [dict objectForKey:@"user_question"], nil]; -- dict is not declared in your sample. Is this just a simple dictionary or something special?Rearward
Sorry about that. Yes, "dict" is just a simple dictionary that I load from the iOS users documents.Calotte
This is using NSDictionary instance method JSONRepresentation. I might suggest I using NSJSONSerialization class method dataWithJSONObject, instead of the json-framework.Caesarean
It is more efficient to convert the NSUInteger to an NSString through an NSNumber like [[NSNumber numberWithUnsignedInt:requestData.length] stringValue].Amphiarthrosis
@MikeG Fixed a long standing and so far unnoticed bug in the code sample. Sorry, for editing your post ;)Vanhouten
Can we achieve the same using GET instead of POST?Bequest
MikeG Removed external dependency referred to by @Rob.Tetrarch
@Caesarean well my edit was rejected 3 to 2 so I made my edit an answer here:https://mcmap.net/q/259699/-how-to-send-json-data-in-the-http-request-using-nsurlrequestTetrarch
i was spending too much time investigating the reason for my nil response. This post helped me, especially setting the "content-type" and "content-length" along with "accept" to "application/json". This post has resolved my issue of nil data being returned from the web api. Thanks for the post.Dodecanese
Critical warning: 'initWithRequest:delegate:' is deprecated: first deprecated in iOS 9.0 - Use NSURLSession (see NSURLSession.h)Flex
C
7

I struggled with this for a while. Running PHP on the server. This code will post a json and get the json reply from the server

NSURL *url = [NSURL URLWithString:@"http://example.co/index.php"];
NSMutableURLRequest *rq = [NSMutableURLRequest requestWithURL:url];
[rq setHTTPMethod:@"POST"];
NSString *post = [NSString stringWithFormat:@"command1=c1&command2=c2"];
NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding];
[rq setHTTPBody:postData];
[rq setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];
NSOperationQueue *queue = [[NSOperationQueue alloc] init];

[NSURLConnection sendAsynchronousRequest:rq queue:queue completionHandler:^(NSURLResponse *response, NSData *data, NSError *error)
 {
     if ([data length] > 0 && error == nil){
         NSError *parseError = nil;
         NSDictionary *dictionary = [NSJSONSerialization JSONObjectWithData:data options:0 error:&parseError];
         NSLog(@"Server Response (we want to see a 200 return code) %@",response);
         NSLog(@"dictionary %@",dictionary);
     }
     else if ([data length] == 0 && error == nil){
         NSLog(@"no data returned");
         //no data, but tried
     }
     else if (error != nil)
     {
         NSLog(@"there was a download error");
         //couldn't download

     }
 }];
Caducous answered 11/2, 2015 at 15:3 Comment(2)
content type = "application/x-www-form-urlencoded" did the trick. ThanksBricole
Nice answer. I used "application/json" in my caseLydgate
E
6

I would suggest to use ASIHTTPRequest

ASIHTTPRequest is an easy to use wrapper around the CFNetwork API that makes some of the more tedious aspects of communicating with web servers easier. It is written in Objective-C and works in both Mac OS X and iPhone applications.

It is suitable performing basic HTTP requests and interacting with REST-based services (GET / POST / PUT / DELETE). The included ASIFormDataRequest subclass makes it easy to submit POST data and files using multipart/form-data.


Please note, that the original author discontinued with this project. See the followring post for reasons and alternatives: http://allseeing-i.com/%5Brequest_release%5D;

Personally I am a big fan of AFNetworking

Eyeglass answered 16/12, 2010 at 2:33 Comment(0)
C
3

Most of you already know this by now, but I am posting this, just incase, some of you are still struggling with JSON in iOS6+.

In iOS6 and later, we have the NSJSONSerialization Class that is fast and has no dependency on including "outside" libraries.

NSDictionary *result = [NSJSONSerialization JSONObjectWithData:[resultStr dataUsingEncoding:NSUTF8StringEncoding] options:0 error:nil]; 

This is the way iOS6 and later can now parse JSON efficiently.The use of SBJson is also pre-ARC implementation and brings with it those issues too if you are working in an ARC environment.

I hope this helps!

Crone answered 12/11, 2013 at 14:49 Comment(0)
G
2

Here is a great article using Restkit

It explains on serializing nested data into JSON and attaching the data to a HTTP POST request.

Glaser answered 19/8, 2013 at 16:34 Comment(0)
T
2

Since my edit to Mike G's answer to modernize the code was rejected 3 to 2 as

This edit was intended to address the author of the post and makes no sense as an edit. It should have been written as a comment or an answer

I'm reposting my edit as a separate answer here. This edit removes the JSONRepresentation dependency with NSJSONSerialization as Rob's comment with 15 upvotes suggests.

    NSArray *objects = [NSArray arrayWithObjects:[[NSUserDefaults standardUserDefaults]valueForKey:@"StoreNickName"],
      [[UIDevice currentDevice] uniqueIdentifier], [dict objectForKey:@"user_question"],     nil];
    NSArray *keys = [NSArray arrayWithObjects:@"nick_name", @"UDID", @"user_question", nil];
    NSDictionary *questionDict = [NSDictionary dictionaryWithObjects:objects forKeys:keys];

    NSDictionary *jsonDict = [NSDictionary dictionaryWithObject:questionDict forKey:@"question"];

    NSLog(@"jsonRequest is %@", jsonRequest);

    NSURL *url = [NSURL URLWithString:@"https://xxxxxxx.com/questions"];

    NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url
                 cachePolicy:NSURLRequestUseProtocolCachePolicy timeoutInterval:60.0];


    NSData *requestData = [NSJSONSerialization dataWithJSONObject:dict options:0 error:nil]; //TODO handle error

    [request setHTTPMethod:@"POST"];
    [request setValue:@"application/json" forHTTPHeaderField:@"Accept"];
    [request setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
    [request setValue:[NSString stringWithFormat:@"%d", [requestData length]] forHTTPHeaderField:@"Content-Length"];
    [request setHTTPBody: requestData];

    NSURLConnection *connection = [[NSURLConnection alloc]initWithRequest:request delegate:self];
    if (connection) {
     receivedData = [[NSMutableData data] retain];
    }

The receivedData is then handled by:

NSDictionary *jsonDict = [NSJSONSerialization JSONObjectWithData:data options:0 error:nil];
    NSDictionary *question = [jsonDict objectForKey:@"question"];
Tetrarch answered 3/11, 2015 at 17:54 Comment(0)
D
0

Here's an updated example that is using NSURLConnection +sendAsynchronousRequest: (10.7+, iOS 5+), The "Post" request remains the same as with the accepted answer and is omitted here for the sake of clarity:

NSURL *apiURL = [NSURL URLWithString:
    [NSString stringWithFormat:@"http://www.myserver.com/api/api.php?request=%@", @"someRequest"]];
NSURLRequest *request = [NSURLRequest requestWithURL:apiURL]; // this is using GET, for POST examples see the other answers here on this page
[NSURLConnection sendAsynchronousRequest:request
                                   queue:[NSOperationQueue mainQueue]
                       completionHandler:^(NSURLResponse *response, NSData *data, NSError *connectionError) {
     if(data.length) {
         NSString *responseString = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];
         if(responseString && responseString.length) {
             NSLog(@"%@", responseString);
         }
     }
}];
Dislocation answered 9/12, 2013 at 14:42 Comment(2)
the question was about POSTBalladry
no, the first part of the question is about asynchronicity and there is no answer here that answers that. Cheers for the downvote.Dislocation
S
0

You can try this code for send json string

NSData *jsonData = [NSJSONSerialization dataWithJSONObject:ARRAY_CONTAIN_JSON_STRING options:NSJSONWritin*emphasized text*gPrettyPrinted error:NULL];
NSString *jsonString = [[NSString alloc] initWithData:jsonData encoding:NSUTF8StringEncoding];
NSString *WS_test = [NSString stringWithFormat:@"www.test.com?xyz.php&param=%@",jsonString];
Sandpaper answered 4/10, 2016 at 12:28 Comment(0)

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