Java has binary-or |
and binary-and &
operators:
int a = 5 | 10;
int b = 5 & 10;
They do not seem to work in Kotlin:
val a = 5 | 10;
val b = 5 & 10;
How do I use Java's bitwise operators in Kotlin?
Java has binary-or |
and binary-and &
operators:
int a = 5 | 10;
int b = 5 & 10;
They do not seem to work in Kotlin:
val a = 5 | 10;
val b = 5 & 10;
How do I use Java's bitwise operators in Kotlin?
You have named functions for them.
Directly from Kotlin docs
Bitwise operations are represented by functions that can be called in infix form. They can be applied only to
Int
andLong
.
for example:
val x = (1 shl 2) and 0x000FF000
Here is the complete list of bitwise operations:
shl(bits) – signed shift left (Java's <<)
shr(bits) – signed shift right (Java's >>)
ushr(bits) – unsigned shift right (Java's >>>)
and(bits) – bitwise and
or(bits) – bitwise or
xor(bits) – bitwise xor
inv() – bitwise inversion
5.inv()
, not as infix like the others –
Welloiled if (condition1 or condition2) and condition3: do this
. This is much more intuitive and just naturally easy to understand. –
Brown you can do this in Kotlin
val a = 5 or 10;
val b = 5 and 10;
here list of operations that you can use
shl(bits) – signed shift left (Java's <<)
shr(bits) – signed shift right (Java's >>)
ushr(bits) – unsigned shift right (Java's >>>)
and(bits) – bitwise and
or(bits) – bitwise or
xor(bits) – bitwise xor
inv() – bitwise inversion
This is currently not supported, but most probably will be by the new Kotlin compiler K2, see Roman Elizarov's comment on the YouTrack issue KT-1440.
See KT-46756 for the upcoming alpha release and keep an eye on the roadmap.
Another example:
Java:
byte dataHigh = (byte) ((data[byteOffset] & 0xF0) >> 4);
Kotlin
val d = (data[byteOffset] and 0xF0.toByte())
val dataHigh = (d.toInt() shr 4).toByte()
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? – Definiendum