Numpy minimum in (row, column) format

Question

How can I know the (row, column) index of the minimum of a numpy array/matrix?

For example, if A = array([[1, 2], [3, 0]]), I want to get (1, 1)

Thanks!

Kurbash

Answer 1

Use unravel_index:

numpy.unravel_index(A.argmin(), A.shape)

Idzik

Thanks, but to comment this is surely a incredibly complex syntax for doing a simple stuff. – Duchy

it really is quite standard syntax, simple even...its just one function extra function call beyond A.argmin(), which returns an index.... – Specification

@linello, just create a function and reuse it, the complexity of the syntax doesn't matter – Crepuscule

Answer 2

[Corrected typo]

Another simple solution is

ri, ci = A.argmin()//A.shape[1], A.argmin()%A.shape[1]

As numpy.argmin returns the index reading in row-major order

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Yes, you are right, it was a typo, which worked for square matrix

Hochman