Regular Expression to match valid dates
Asked Answered
Z

17

80

I'm trying to write a regular expression that validates a date. The regex needs to match the following

  • M/D/YYYY
  • MM/DD/YYYY
  • Single digit months can start with a leading zero (eg: 03/12/2008)
  • Single digit days can start with a leading zero (eg: 3/02/2008)
  • CANNOT include February 30 or February 31 (eg: 2/31/2008)

So far I have

^(([1-9]|1[012])[-/.]([1-9]|[12][0-9]|3[01])[-/.](19|20)\d\d)|((1[012]|0[1-9])(3[01]|2\d|1\d|0[1-9])(19|20)\d\d)|((1[012]|0[1-9])[-/.](3[01]|2\d|1\d|0[1-9])[-/.](19|20)\d\d)$

This matches properly EXCEPT it still includes 2/30/2008 & 2/31/2008.

Does anyone have a better suggestion?

Edit: I found the answer on RegExLib

^((((0[13578])|([13578])|(1[02]))[\/](([1-9])|([0-2][0-9])|(3[01])))|(((0[469])|([469])|(11))[\/](([1-9])|([0-2][0-9])|(30)))|((2|02)[\/](([1-9])|([0-2][0-9]))))[\/]\d{4}$|^\d{4}$

It matches all valid months that follow the MM/DD/YYYY format.

Thanks everyone for the help.

Zealous answered 9/9, 2008 at 4:30 Comment(3)
This doesn't take leap year into consideration. It outputs 02/29/2011 as a valid date.Unifilar
Check my answer for a reg ex that takes leap years into consideration.Unifilar
It matches all valid months that follow the MM/DD/YYYY format. Fails to validate 1234 ! :(Dolt
D
159

This is not an appropriate use of regular expressions. You'd be better off using

[0-9]{2}/[0-9]{2}/[0-9]{4}

and then checking ranges in a higher-level language.

Depone answered 9/9, 2008 at 4:37 Comment(6)
This is not a correct regex as it only checks number of digits in month/data/year.Vendace
Agreed, that's like using a regular expression for phone numbers that checks all possible area codes. What is the point of not including 2/30 or 2/31 if you include 2/29 for non-leap years, and if you include 4/31, 6/31, 9/31, and 11/31?Disapproval
@SanjeevSingh that is the point - regular expressions should not be used for data validation. This will match date-like strings, which can then be validated using a proper date library if needed.Forborne
@Chris perhaps, you add ^ at the beginning and $ at the end of your answer to match the whole date string only. (By the way: I followed your recommendation to realize the check for leap year etc. in the code. Yes: That's definitely better as you said).Anamorphic
^(([0-9]{0,2})( "separator" )?){0,2}[1-2]?([0-9]{0,3})T
can be a challenge to write a regex that does that or you don't have means to add additional checks besides the regex match... so even though i agree regex is not meant to be used for that, this is barely a correct answerJimenez
U
65

Here is the Reg ex that matches all valid dates including leap years. Formats accepted mm/dd/yyyy or mm-dd-yyyy or mm.dd.yyyy format

^(?:(?:(?:0?[13578]|1[02])(\/|-|\.)31)\1|(?:(?:0?[1,3-9]|1[0-2])(\/|-|\.)(?:29|30)\2))(?:(?:1[6-9]|[2-9]\d)?\d{2})$|^(?:0?2(\/|-|\.)29\3(?:(?:(?:1[6-9]|[2-9]\d)?(?:0[48]|[2468][048]|[13579][26])|(?:(?:16|[2468][048]|[3579][26])00))))$|^(?:(?:0?[1-9])|(?:1[0-2]))(\/|-|\.)(?:0?[1-9]|1\d|2[0-8])\4(?:(?:1[6-9]|[2-9]\d)?\d{2})$

courtesy Asiq Ahamed

Unifilar answered 7/1, 2012 at 7:58 Comment(9)
What about year 20BC? (like -20/1/1 )Robespierre
@Robespierre - Did you actually need to program that for something, or did you pull that criticism out of a hat?Honduras
Yes, at the time of my comment (2+ years ago) I needed to represent dates dating that back and more.Robespierre
To declare in js use in the following way var dateReg = new RegExp(['^(?:(?:(?:0?[13578]|1[02])(\\/|-|\\.)31)', '\\1|(?:(?:0?[1,3-9]|1[0-2])(\\/|-|\\.)(?:29|30)', '\\2))(?:(?:1[6-9]|[2-9]\\d)?\d{2})$|^(?:0?2(\\/|-|\\.)', '29\\3(?:(?:(?:1[6-9]|[2-9]\\d)?(?:0[48]|[2468][048]|', '[13579][26])|(?:(?:16|[2468][048]|[3579][26])00))))', '$|^(?:(?:0?[1-9])|(?:1[0-2]))(\\/|-|\\.)', '(?:0?[1-9]|1\\d|2[0-8])\\4', '(?:(?:1[6-9]|[2-9]\\d)?\\d{2})$'].join(''),"g");Penton
could we get a modified version of dd/mm/yyyy?Palladian
If I want to check the date format like DDMMYYYY. Please help me for the same.Palazzo
@Yokhen , I think i am late but this will help so many developers. To DD/MM/YYYY try /(((0[1-9]|[12][0-9]|3[01])([/])(0[13578]|10|12)([/])(\d{4}))|(([0][1-9]|[12][0-9]|30)([/])(0[469]|11)([/])(\d{4}))|((0[1-9]|1[0-9]|2[0-8])([/])(02)([/])(\d{4}))|((29)(\/)(02)([/])([02468][048]00))|((29)([/])(02)([/])([13579][26]00))|((29)([/])(02)([/])([0-9][0-9][0][48]))|((29)([/])(02)([/])([0-9][0-9][2468][048]))|((29)([/])(02)([/])([0-9][0-9][13579][26])))/ Antonantone
@HimanshuNTatariya DDMMYYYY /(((0[1-9]|[12][0-9]|3[01])(0[13578]|10|12)(\d{4}))|(([0][1-9]|[12][0-9]|30)(0[469]|11)(\d{4}))|((0[1-9]|1[0-9]|2[0-8])(02)(\d{4}))|((29)(02)([02468][048]00))|((29)(02)([13579][26]00))|((29)(02)([0-9][0-9][0][48]))|((29)(02)([0-9][0-9][2468][048]))|((29)(02)([0-9][0-9][13579][26])))/Bebel
YYYY-MM-DD /^((1[6-9]|[2-9]\d)\d{2})-(((0[13578]|1[02])-31)|((0[1,3-9]|1[0-2])-(29|30)))$|^((((1[6-9]|[2-9]\d)?(0[48]|[2468][048]|[13579][26])|((16|[2468][048]|[3579][26])00)))-02-29)$|^((1[6-9]|[2-9]\d)\d{2})-((0[1-9])|(1[0-2]))-(0[1-9]|1\d|2[0-8])$/ Jimenez
P
42

I landed here because the title of this question is broad and I was looking for a regex that I could use to match on a specific date format (like the OP). But I then discovered, as many of the answers and comments have comprehensively highlighted, there are many pitfalls that make constructing an effective pattern very tricky when extracting dates that are mixed-in with poor quality or non-structured source data.

In my exploration of the issues, I have come up with a system that enables you to build a regular expression by arranging together four simpler sub-expressions that match on the delimiter, and valid ranges for the year, month and day fields in the order you require.

These are :-

Delimeters

[^\w\d\r\n:] 

This will match anything that is not a word character, digit character, carriage return, new line or colon. The colon has to be there to prevent matching on times that look like dates (see my test Data)

You can optimise this part of the pattern to speed up matching, but this is a good foundation that detects most valid delimiters.

Note however; It will match a string with mixed delimiters like this 2/12-73 that may not actually be a valid date.

Year Values

(\d{4}|\d{2})

This matches a group of two or 4 digits, in most cases this is acceptable, but if you're dealing with data from the years 0-999 or beyond 9999 you need to decide how to handle that because in most cases a 1, 3 or >4 digit year is garbage.

Month Values

(0?[1-9]|1[0-2])

Matches any number between 1 and 12 with or without a leading zero - note: 0 and 00 is not matched.

Date Values

(0?[1-9]|[12]\d|30|31)

Matches any number between 1 and 31 with or without a leading zero - note: 0 and 00 is not matched.

This expression matches Date, Month, Year formatted dates

(0?[1-9]|[12]\d|30|31)[^\w\d\r\n:](0?[1-9]|1[0-2])[^\w\d\r\n:](\d{4}|\d{2})

But it will also match some of the Year, Month Date ones. It should also be bookended with the boundary operators to ensure the whole date string is selected and prevent valid sub-dates being extracted from data that is not well-formed i.e. without boundary tags 20/12/194 matches as 20/12/19 and 101/12/1974 matches as 01/12/1974

Compare the results of the next expression to the one above with the test data in the nonsense section (below)

\b(0?[1-9]|[12]\d|30|31)[^\w\d\r\n:](0?[1-9]|1[0-2])[^\w\d\r\n:](\d{4}|\d{2})\b

There's no validation in this regex so a well-formed but invalid date such as 31/02/2001 would be matched. That is a data quality issue, and as others have said, your regex shouldn't need to validate the data.

Because you (as a developer) can't guarantee the quality of the source data you do need to perform and handle additional validation in your code, if you try to match and validate the data in the RegEx it gets very messy and becomes difficult to support without very concise documentation.

Garbage in, garbage out.

Having said that, if you do have mixed formats where the date values vary, and you have to extract as much as you can; You can combine a couple of expressions together like so;

This (disastrous) expression matches DMY and YMD dates

(\b(0?[1-9]|[12]\d|30|31)[^\w\d\r\n:](0?[1-9]|1[0-2])[^\w\d\r\n:](\d{4}|\d{2})\b)|(\b(0?[1-9]|1[0-2])[^\w\d\r\n:](0?[1-9]|[12]\d|30|31)[^\w\d\r\n:](\d{4}|\d{2})\b)

BUT you won't be able to tell if dates like 6/9/1973 are the 6th of September or the 9th of June. I'm struggling to think of a scenario where that is not going to cause a problem somewhere down the line, it's bad practice and you shouldn't have to deal with it like that - find the data owner and hit them with the governance hammer.

Finally, if you want to match a YYYYMMDD string with no delimiters you can take some of the uncertainty out and the expression looks like this

\b(\d{4})(0[1-9]|1[0-2])(0[1-9]|[12]\d|30|31)\b

But note again, it will match on well-formed but invalid values like 20010231 (31th Feb!) :)

Test data

In experimenting with the solutions in this thread I ended up with a test data set that includes a variety of valid and non-valid dates and some tricky situations where you may or may not want to match i.e. Times that could match as dates and dates on multiple lines.

I hope this is useful to someone.

Valid Dates in various formats

Day, month, year
2/11/73
02/11/1973
2/1/73
02/01/73
31/1/1973
02/1/1973
31.1.2011
31-1-2001
29/2/1973
29/02/1976 
03/06/2010
12/6/90

month, day, year
02/24/1975 
06/19/66 
03.31.1991
2.29.2003
02-29-55
03-13-55
03-13-1955
12\24\1974
12\30\1974
1\31\1974
03/31/2001
01/21/2001
12/13/2001

Match both DMY and MDY
12/12/1978
6/6/78
06/6/1978
6/06/1978

using whitespace as a delimiter

13 11 2001
11 13 2001
11 13 01 
13 11 01
1 1 01
1 1 2001

Year Month Day order
76/02/02
1976/02/29
1976/2/13
76/09/31

YYYYMMDD sortable format
19741213
19750101

Valid dates before Epoch
12/1/10
12/01/660
12/01/00
12/01/0000

Valid date after 2038

01/01/2039
01/01/39

Valid date beyond the year 9999

01/01/10000

Dates with leading or trailing characters

12/31/21/
31/12/1921AD
31/12/1921.10:55
12/10/2016  8:26:00.39
wfuwdf12/11/74iuhwf
fwefew13/11/1974
01/12/1974vdwdfwe
01/01/99werwer
12321301/01/99

Times that look like dates

12:13:56
13:12:01
1:12:01PM
1:12:01 AM

Dates that runs across two lines

1/12/19
74

01/12/19
74/13/1946

31/12/20
08:13

Invalid, corrupted or nonsense dates

0/1/2001
1/0/2001
00/01/2100
01/0/2001
0101/2001
01/131/2001
31/31/2001
101/12/1974
56/56/56
00/00/0000
0/0/1999
12/01/0
12/10/-100
74/2/29
12/32/45
20/12/194

2/12-73
Purposeless answered 28/10, 2016 at 16:45 Comment(3)
Very nice explanation with examples! May consider adding other month formats like MMM and full month name regex also!Engrossing
Thank you! Does the "disastrous" expression have a bug? I wasn't able to get it to match yyyy-mm-dd-format dates and had to change it to (in Perl): /( (\b(0?[1-9]|[12]\d|30|31)[^\w\d\r\n:](0?[1-9]|1[0-2])[^\w\d\r\n:](\d{4}|\d{2})\b) | (\d{4}|\d{2})[^\w\d\r\n:](\b(0?[1-9]|1[0-2])[^\w\d\r\n:](0?[1-9]|[12]\d|30|31)\b) )/x' --- Tested as : echo 2017-01-28 | perl -ne 'print "$1\n" if /((\b(0?[1-9]|[12]\d|30|31)[^\w\d\r\n:](0?[1-9]|1[0-2])[^\w\d\r\n:](\d{4}|\d{2})\b)|(\d{4}|\d{2})[^\w\d\r\n:](\b(0?[1-9]|1[0-2])[^\w\d\r\n:](0?[1-9]|[12]\d|30|31)\b))/'Navicular
Yes, this is useful to not use regex for validation. KISS (Keep It Simple Stupid!) is another principle that must be follow up in this scenario. Great documentation/description, @Bob!Unsheathe
W
14

Maintainable Perl 5.10 version

/
  (?:
      (?<month> (?&mon_29)) [\/] (?<day>(?&day_29))
    | (?<month> (?&mon_30)) [\/] (?<day>(?&day_30))
    | (?<month> (?&mon_31)) [\/] (?<day>(?&day_31))
  )
  [\/]
  (?<year> [0-9]{4})
  
  (?(DEFINE)
    (?<mon_29> 0?2 )
    (?<mon_30> 0?[469]   | (11) )
    (?<mon_31> 0?[13578] | 1[02] )

    (?<day_29> 0?[1-9] | [1-2]?[0-9] )
    (?<day_30> 0?[1-9] | [1-2]?[0-9] | 30 )
    (?<day_31> 0?[1-9] | [1-2]?[0-9] | 3[01] )
  )
/x

You can retrieve the elements by name in this version.

say "Month=$+{month} Day=$+{day} Year=$+{year}";

( No attempt has been made to restrict the values for the year. )

Whall answered 13/9, 2008 at 21:28 Comment(3)
Wouldn't this match "12/00/0000"?Repulse
@Repulse That is true of most of the others as well, If you need the check that, it should be easy to figure out how to modify this regular expression.Whall
+1 for having a version that is actually maintainable.Cristinecristiona
J
10

To control a date validity under the following format :

YYYY/MM/DD or YYYY-MM-DD

I would recommand you tu use the following regular expression :

(((19|20)([2468][048]|[13579][26]|0[48])|2000)[/-]02[/-]29|((19|20)[0-9]{2}[/-](0[4678]|1[02])[/-](0[1-9]|[12][0-9]|30)|(19|20)[0-9]{2}[/-](0[1359]|11)[/-](0[1-9]|[12][0-9]|3[01])|(19|20)[0-9]{2}[/-]02[/-](0[1-9]|1[0-9]|2[0-8])))

Matches

2016-02-29 | 2012-04-30 | 2019/09/31

Non-Matches

2016-02-30 | 2012-04-31 | 2019/09/35

You can customise it if you wants to allow only '/' or '-' separators. This RegEx strictly controls the validity of the date and verify 28,30 and 31 days months, even leap years with 29/02 month.

Try it, it works very well and prevent your code from lot of bugs !

FYI : I made a variant for the SQL datetime. You'll find it there (look for my name) : Regular Expression to validate a timestamp

Feedback are welcomed :)

June answered 12/4, 2013 at 9:44 Comment(0)
W
4

Sounds like you're overextending regex for this purpose. What I would do is use a regex to match a few date formats and then use a separate function to validate the values of the date fields so extracted.

Wordplay answered 9/9, 2008 at 4:34 Comment(0)
W
3

Perl expanded version

Note use of /x modifier.

/^(
      (
        ( # 31 day months
            (0[13578])
          | ([13578])
          | (1[02])
        )
        [\/]
        (
            ([1-9])
          | ([0-2][0-9])
          | (3[01])
        )
      )
    | (
        ( # 30 day months
            (0[469])
          | ([469])
          | (11)
        )
        [\/]
        (
            ([1-9])
          | ([0-2][0-9])
          | (30)
        )
      )
    | ( # 29 day month (Feb)
        (2|02)
        [\/]
        (
            ([1-9])
          | ([0-2][0-9])
        )
      )
    )
    [\/]
    # year
    \d{4}$
  
  | ^\d{4}$ # year only
/x

Original

^((((0[13578])|([13578])|(1[02]))[\/](([1-9])|([0-2][0-9])|(3[01])))|(((0[469])|([469])|(11))[\/](([1-9])|([0-2][0-9])|(30)))|((2|02)[\/](([1-9])|([0-2][0-9]))))[\/]\d{4}$|^\d{4}$
Whall answered 13/9, 2008 at 20:56 Comment(0)
C
3

if you didn't get those above suggestions working, I use this, as it gets any date I ran this expression through 50 links, and it got all the dates on each page.

^20\d\d-(Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec)-(0[1-9]|[1-2][0-9]|3[01])$ 
Connate answered 21/1, 2012 at 0:3 Comment(0)
A
3

This regex validates dates between 01-01-2000 and 12-31-2099 with matching separators.

^(0[1-9]|1[012])([- /.])(0[1-9]|[12][0-9]|3[01])\2(19|20)\d\d$
Amorphism answered 29/4, 2013 at 17:53 Comment(0)
S
2
    var dtRegex = new RegExp(/[1-9\-]{4}[0-9\-]{2}[0-9\-]{2}/);
    if(dtRegex.test(date) == true){
        var evalDate = date.split('-');
        if(evalDate[0] != '0000' && evalDate[1] != '00' && evalDate[2] != '00'){
            return true;
        }
    }
Soothsayer answered 23/11, 2012 at 18:0 Comment(0)
S
1

Regex was not meant to validate number ranges(this number must be from 1 to 5 when the number preceding it happens to be a 2 and the number preceding that happens to be below 6). Just look for the pattern of placement of numbers in regex. If you need to validate is qualities of a date, put it in a date object js/c#/vb, and interogate the numbers there.

Singletree answered 9/9, 2008 at 4:36 Comment(0)
T
1

I know this does not answer your question, but why don't you use a date handling routine to check if it's a valid date? Even if you modify the regexp with a negative lookahead assertion like (?!31/0?2) (ie, do not match 31/2 or 31/02) you'll still have the problem of accepting 29 02 on non leap years and about a single separator date format.

The problem is not easy if you want to really validate a date, check this forum thread.

For an example or a better way, in C#, check this link

If you are using another platform/language, let us know

Tryma answered 9/9, 2008 at 4:43 Comment(0)
W
1

Perl 6 version

rx{
  ^

  $<month> = (\d ** 1..2)
  { $<month> <= 12 or fail }

  '/'

  $<day> = (\d ** 1..2)
  {
    given( +$<month> ){
      when 1|3|5|7|8|10|12 {
        $<day> <= 31 or fail
      }
      when 4|6|9|11 {
        $<day> <= 30 or fail
      }
      when 2 {
        $<day> <= 29 or fail
      }
      default { fail }
    }
  }

  '/'

  $<year> = (\d ** 4)

  $
}

After you use this to check the input the values are available in $/ or individually as $<month>, $<day>, $<year>. ( those are just syntax for accessing values in $/ )

No attempt has been made to check the year, or that it doesn't match the 29th of Feburary on non leap years.

Whall answered 13/9, 2008 at 21:42 Comment(0)
D
0

If you're going to insist on doing this with a regular expression, I'd recommend something like:

( (0?1|0?3| <...> |10|11|12) / (0?1| <...> |30|31) |
  0?2 / (0?1| <...> |28|29) ) 
/ (19|20)[0-9]{2}

This might make it possible to read and understand.

Depone answered 9/9, 2008 at 4:45 Comment(0)
B
0

/(([1-9]{1}|0[1-9]|1[0-2])\/(0[1-9]|[1-9]{1}|[12]\d|3[01])\/[12]\d{3})/

This would validate for following -

  • Single and 2 digit day with range from 1 to 31. Eg, 1, 01, 11, 31.
  • Single and 2 digit month with range from 1 to 12. Eg. 1, 01, 12.
  • 4 digit year. Eg. 2021, 1980.
Binder answered 11/9, 2021 at 4:50 Comment(0)
D
0

I wanted to remove dates that were formatted like so

<p>8 March</p>

<p>8 February</p>

<p>8 Dec</p>

I was able to use following reg expression

/<([\w]*)\b[^>]*>(\d).*<\/\1>/

e.g. https://regexr.com/7u3sc

Dissolve answered 27/3 at 14:3 Comment(0)
P
-1

A slightly different approach that may or may not be useful for you.

I'm in php.

The project this relates to will never have a date prior to the 1st of January 2008. So, I take the 'date' inputed and use strtotime(). If the answer is >= 1199167200 then I have a date that is useful to me. If something that doesn't look like a date is entered -1 is returned. If null is entered it does return today's date number so you do need a check for a non-null entry first.

Works for my situation, perhaps yours too?

Perinephrium answered 21/10, 2008 at 12:56 Comment(0)

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