I'm working on a OS portable database system. I want our database files to be OS portable so that customers can move their database files to other kinds of OS's at their discretion. Because of this use case I need my data types to be consistent across OS's, and I'm wondering if IEEE float's and double's are guaranteed to be the same byte size on any OS?
C++ says almost nothing about the representation of floating point types.
[basic.fundamental]/8
says (Emphasis mine):
There are three floating point types:
float
,double
, andlong double
. The typedouble
provides at least as much precision asfloat
, and the typelong double
provides at least as much precision as double. The set of values of the typefloat
is a subset of the set of values of the typedouble
; the set of values of the typedouble
is a subset of the set of values of the typelong double
. The value representation of floating-point types is implementation-defined. Integral and floating types are collectively called arithmetic types. Specializations of the standard templatestd::numeric_limits
(18.3) shall specify the maximum and minimum values of each arithmetic type for an implementation.
If you just write C++ code using float
, double
and long double
, you have virtually no guarantees, apart from those given in the documentation for your particular compiler, and those that can be implied from std::numeric_limits
.
On the other hand, IEEE 754 provides exact definitions of the behaviour and binary representation of its floating point types. These definitions are not quite enough to guarantee identical behaviour on all IEEE 754 platforms, since (for example) IEEE 754 sometimes allows multiple operations to be folded together when the result would be more precise than performing the two operations separately. This is likely to be unimportant to your specific case, since you just want the files to be portable, and probably do not care quite as much about identical queries creating identical changes to the files on different platforms as you do about identical files being loaded in identical ways on different platforms.
So the question is: "how do I get a portable IEEE 754 implementation for C++?".
The answer to this question is somewhat tricky. Most C++ compilers for reasonable platforms will provide at least float
and double
that approximately match IEEE 754's binary32
and binary64
specifications (although you will need to read the documentation for each individual compiler to be sure).
Alternatively, you can use a software floating point implementation or wrapper such as FLIP, libgcc's soft-float, SoftFloat, or STREFLOP. These libraries sometimes still make assumptions about the implementation that are not completely portable according to the C++ standard, so use at your own risk.
[expr.add]/3
states "The result of the binary + operator is the sum of the operands.". [numeric.limits]
somewhat constrains the results, but as far as I can see there is nothing stopping 1.1+0.9=28.7
, as long as appropriate values are listed for numeric_limits<double>::round_error()
and numeric_limits<double>::round_style
, beyond the fact that it would most likely be considered a very low quality implementation. –
Drenthe ISO/IEC 10967
(Language Independent Arithmetic) and/or IEEE 754
(IEEE Floating Point), or otherwise have some reasonable behaviour. –
Drenthe --cut-- Nevermind https://mcmap.net/q/25072/-are-ieee-float-and-double-guaranteed-to-be-the-same-size-on-any-os provides a better explanation for the float sizes.
If you're however thinking about storing these floats in binary data files, do make sure you don't mess up the byte order or endianness. If you're dumping raw floats, some systems store the bytes in a different order, so casting the 4 bytes you just read to a double might give some surprising results.
std::numeric_limits<T>::is_iec559
Determines if a given type follows IEC 559, which is another name for IEEE 754.
This serves as further evidence that IEEE is optional, and offers a way for you to check if it is used or not.
C++11 N3337 standard draft 18.3.2.4 numeric_limits members:
static constexpr bool is_iec559;
56 True if and only if the type adheres to IEC 559 standard. (217)
57 Meaningful for all floating point types.
(217) International Electrotechnical Commission standard 559 is the same as IEEE 754.
Sample code:
#include <iostream>
#include <limits>
int main() {
std::cout << std::numeric_limits<float>::is_iec559 << std::endl;
std::cout << std::numeric_limits<double>::is_iec559 << std::endl;
std::cout << std::numeric_limits<long double>::is_iec559 << std::endl;
}
Outputs:
1
1
1
on Ubuntu 16.04 x86-64.
__STDC_IEC_559__
is an analogous macro for C: https://mcmap.net/q/25070/-is-it-safe-to-assume-floating-point-is-represented-using-ieee754-floats-in-c
Rationale
This is an interesting article that describes the rationale behind not fixing sizes, and hot to get around it: http://yosefk.com/blog/consistency-how-to-defeat-the-purpose-of-ieee-floating-point.html
They are. "float" will be 32 bits, "double" will be 64 bits. The byte ordering might be different; it's exactly the same as with 32 bit and 64 bit integers.
If you need extended precision: That may or may not be available as "long double". And extended precision uses 80 bits, but "long double" may have additional padding bits.
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float
anddouble
types are not guaranteed to be IEEE 754binary32
andbinary64
. I assume you're more interested in the latter? – OutcropCHAR_BIT != 8
to your question. Most answers here will probably tell you thatfloat
is guaranteed to be 32-bit long anddouble
is guaranteed to be 64-bit long. But what if, for example,CHAR_BIT
is defined as16
? – Husband