How do you stop UITapGestureRecognizer from catching EVERY tap?

Question

Hello I have an opengl view and on that I have a tab bar. I'm using a tap recognizer to tap different 3d objects on screen. In the tab bar I have a button but it doesn't work because the tap recognizer catches these taps too. How do I stop this? I've already tried this:

- (BOOL) gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldReceiveTouch:(UITouch *)touch
{
  if ([touch.view isKindOfClass:[UIBarButtonItem class]]) return FALSE;
  return TRUE;
}

I think I am somehow comparing wrong classess because when I debug it returns TRUE always.

Mort

your if-statement can never return false - a button is not a view... But you could check via a breakpoint in the debugger which type the view is you get on different tap positions. – Your

Oh..I just noticed that UIBarButtonItem is not an UIView :) Thanks. – Mort

Answer 1

Or you can just do [singleTap setCancelsTouchesInView:NO]. Example:

UITapGestureRecognizer *singleTap = [
    [UITapGestureRecognizer alloc]
    initWithTarget: self
    action: @selector(yourSelector:)
];
[singleTap setCancelsTouchesInView:NO];
[[self view] addGestureRecognizer: singleTap];

Cappello

Also available in the Interface Builder as Canceled in View. Great! – Laurice

Only thing that worked. And like a charm, might I add! no messing with the rest of the code. thks! – Overthrust

Answer 2

  if ([touch.view.superview isKindOfClass:[UIToolbar class]]) return FALSE;

This is how I got it to work. The superview is a UIToolbar, probably UIBarButtonIttem is a view after all.

Mort

This worked where hit testing on the gesture recognizer's view failed. To be clear, I was working within a UITableView and the gesture's location was reported as {0, contentOffset - someConstant}. Checking the touch's view is a good solution. Thanks. – Midwinter