Why would PHP-generated Javascript not work in file loaded via AJAX?
Asked Answered
J

2

2

I am loading a .php file via an ExtJS AJAX call like this:

menuItemApplication.header.on('click', function() {             
    Ext.Ajax.request({
        url: 'content/view_application.php',
        success: function(objServerResponse) {
            var responseText = objServerResponse.responseText;
            regionContent.update(responseText);
            var scripts, scriptsFinder=/<script[^>]*>([\s\S]+)<\/script>/gi;
            while(scripts=scriptsFinder.exec(responseText)) {
                eval(scripts[1]);
            }
        }
    });
});

Javascript in the loaded .php file executes fine:

<script type="text/javascript">
     regionContent.update('changed region content from within application view');
</script>

But if the Javascript is being generated via PHP, it is not executed:

<?php
echo "<script type=\"text/javascript\">\n";
echo "regionContent.update('changed region content from within application view')';\n";
echo "</script>\n";
?>

Yes the responses are the same, as seen in the Firebug Net panel, here with Javascript which works:

alt text

And here with PHP-generated Javascript, which does not work:

alt text

How can I get the PHP-generated Javascript to execute?

Jointress answered 2/12, 2010 at 12:48 Comment(0)
C
4

Those responses aren't the same. Check the '; versus ; at the end there.

<?php
echo "<script type=\"text/javascript\">\n";
echo "regionContent.update('changed region content from within application view')';\n";
echo "</script>\n";
?>

Versus

<?php
echo "<script type=\"text/javascript\">\n";
echo "regionContent.update('changed region content from within application view');\n";
echo "</script>\n";
?>
Charpoy answered 2/12, 2010 at 12:52 Comment(1)
Its such an easy mistake to make. I'm surprised the error console didn't let you know what's up.Charpoy
D
2

There's an extra quote in your PHP code, causing the quotes in Javascript to work incorrectly; instead of:

echo "regionContent.update('changed region content from within application view')';\n";

You need:

echo "regionContent.update('changed region content from within application view');\n";
Danielledaniels answered 2/12, 2010 at 12:53 Comment(0)

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