Does Python have an ordered set?
Asked Answered
G

16

750

Python has an ordered dictionary. What about an ordered set?

Gladstone answered 31/10, 2009 at 10:12 Comment(13)
what about the converse, a bag of things? (unordered and non-unique)Rosemarierosemary
@Rosemarierosemary collections.Counter is Python's bag.Jamikajamil
What if something gets added twice? What should the position be?Inflammatory
@Inflammatory - if it were to follow the behavior of collections.OrderDict it would still be in the position of the initial additionMilone
Warning: several answers here are outdated. E.g., dict is now insertion-ordered (guaranteed since Python 3.7)Annates
^^+1 See a below answer: https://mcmap.net/q/24209/-does-python-have-an-ordered-set. Dicts preserve order in Python 3.7+. Otherwise, use OrderedDict.Iguana
from sortedcontainers import Sorted*Raimondo
pypi.org/project/ordered-setCuracy
If you specifically want an ordered set in order to deduplicate a list, please see stackoverflow.com/questions/480214.Network
I've contributed to a discussion in the python discussion board in favor of adding OrderedSet to the standard collections library: discuss.python.org/t/add-orderedset-to-stdlib/12730.Kovno
This answer is excellent from a different question: https://mcmap.net/q/24210/-indexable-weak-ordered-set-in-pythonDisastrous
@Inflammatory Mathematical and python sets are by definition "unordered collection[s] with no duplicate elements." If the data structure allowed duplicates then it would no longer be a set; it would be some other data structure. This question is more properly requesting a data structure (in python, more specifically a collection) that is mutable, ordered, and allows no duplicate elements, but it's easier to just phrase that as an ordered set and expect people know what you mean.Brooklynese
@Brooklynese yes, that's exactly my point. What the OP wants is not clear. Sets don't have an order, they want an order, so I think it's appropriate to ask what the order should be in certain cases.Inflammatory
G
253

There is an ordered set (possible new link) recipe for this which is referred to from the Python 2 Documentation. This runs on Py2.6 or later and 3.0 or later without any modifications. The interface is almost exactly the same as a normal set, except that initialisation should be done with a list.

OrderedSet([1, 2, 3])

This is a MutableSet, so the signature for .union doesn't match that of set, but since it includes __or__ something similar can easily be added:

@staticmethod
def union(*sets):
    union = OrderedSet()
    union.union(*sets)
    return union

def union(self, *sets):
    for set in sets:
        self |= set
Gladstone answered 31/10, 2009 at 10:15 Comment(6)
I selected my own answer because the reference from the documentation makes this close to an official answerGladstone
The interface is NOT exactly the same as the normal set object, many essential methods are missing such as update, union, intersection.Fossorial
FYI, I noticed that a slightly modified version of the recipe cited in this answer has been added to PyPi as "ordered-set"Calyptra
I'm pretty sure you're not allowed to have two methods both called union in the same class. The last one will "win" and the first one will fail to exist at runtime. This is because OrderedSet.union (no parens) has to refer to a single object.Adversaria
There is also "orderedset" package which is based on the same recipe but implemented in Cython -- pypi.python.org/pypi/orderedset .Mila
See a below answer: https://mcmap.net/q/24209/-does-python-have-an-ordered-set. Dicts preserve order in Python 3.7+. Otherwise, use OrderedDict.Iguana
G
390

The answer is no, but as of Python 3.7 you can use the simple dict from the Python standard library with just keys (and values as None) for the same purpose.

Here's an example of how to use dict as an ordered set to filter out duplicate items while preserving order, thereby emulating an ordered set. Use the dict class method fromkeys() to create a dict, then simply ask for the keys() back.

>>> keywords = ['foo', 'bar', 'bar', 'foo', 'baz', 'foo']

>>> list(dict.fromkeys(keywords))
['foo', 'bar', 'baz']

For older versions of Python, use the collections.OrderedDict

Gerome answered 6/12, 2018 at 18:21 Comment(8)
Maybe worth mentioning that this also works (faster) with vanilla dict.fromkeys(). But in that case, key order is only preserved in CPython 3.6+ implementations, so OrderedDict is a more portable solution when order matters.Lingo
@AnwarHossain keys = (1,2,3,1,2,1) list(OrderedDict.fromkeys(keys).keys()) -> [1, 2, 3], python-3.7. It works.Charlacharlady
Can we infer that Set in Python 3.7+ preserve order too ?Expect
This answers the actual question instead of jumping right into a work-around.Raillery
@user474491 Unlike dict, set in Python 3.7+ unfortunately does not preserve order.Chaffer
dict is not guaranteed to preserve order. From the link, "The order-preserving aspect of this new implementation is considered an implementation detail and should not be relied upon."Proteiform
@DavidEhrmann Keep reading a little further on the same link: "Update December 2017: dicts retaining insertion order is guaranteed for Python 3.7"Gerome
The linked answer says dict retains insertion order, but it doesn't necessarily retain order after operations on its contents. It also points out several features that OrderedDict has, but dict does not. dict may be sufficient for the specific problem posed in this question, but one shouldn't take dict's support for retaining insertion order to mean that it is a complete replacement for OrderedDict.Moua
G
253

There is an ordered set (possible new link) recipe for this which is referred to from the Python 2 Documentation. This runs on Py2.6 or later and 3.0 or later without any modifications. The interface is almost exactly the same as a normal set, except that initialisation should be done with a list.

OrderedSet([1, 2, 3])

This is a MutableSet, so the signature for .union doesn't match that of set, but since it includes __or__ something similar can easily be added:

@staticmethod
def union(*sets):
    union = OrderedSet()
    union.union(*sets)
    return union

def union(self, *sets):
    for set in sets:
        self |= set
Gladstone answered 31/10, 2009 at 10:15 Comment(6)
I selected my own answer because the reference from the documentation makes this close to an official answerGladstone
The interface is NOT exactly the same as the normal set object, many essential methods are missing such as update, union, intersection.Fossorial
FYI, I noticed that a slightly modified version of the recipe cited in this answer has been added to PyPi as "ordered-set"Calyptra
I'm pretty sure you're not allowed to have two methods both called union in the same class. The last one will "win" and the first one will fail to exist at runtime. This is because OrderedSet.union (no parens) has to refer to a single object.Adversaria
There is also "orderedset" package which is based on the same recipe but implemented in Cython -- pypi.python.org/pypi/orderedset .Mila
See a below answer: https://mcmap.net/q/24209/-does-python-have-an-ordered-set. Dicts preserve order in Python 3.7+. Otherwise, use OrderedDict.Iguana
Q
173

Update: This answer is obsolete as of Python 3.7. See jrc's answer above for a better solution. Will keep this answer here only for historical reasons.


An ordered set is functionally a special case of an ordered dictionary.

The keys of a dictionary are unique. Thus, if one disregards the values in an ordered dictionary (e.g. by assigning them None), then one has essentially an ordered set.

As of Python 3.1 and 2.7 there is collections.OrderedDict. The following is an example implementation of an OrderedSet. (Note that only few methods need to be defined or overridden: collections.OrderedDict and collections.MutableSet do the heavy lifting.)

import collections

class OrderedSet(collections.OrderedDict, collections.MutableSet):

    def update(self, *args, **kwargs):
        if kwargs:
            raise TypeError("update() takes no keyword arguments")

        for s in args:
            for e in s:
                 self.add(e)

    def add(self, elem):
        self[elem] = None

    def discard(self, elem):
        self.pop(elem, None)

    def __le__(self, other):
        return all(e in other for e in self)

    def __lt__(self, other):
        return self <= other and self != other

    def __ge__(self, other):
        return all(e in self for e in other)

    def __gt__(self, other):
        return self >= other and self != other

    def __repr__(self):
        return 'OrderedSet([%s])' % (', '.join(map(repr, self.keys())))

    def __str__(self):
        return '{%s}' % (', '.join(map(repr, self.keys())))
    
    difference = property(lambda self: self.__sub__)
    difference_update = property(lambda self: self.__isub__)
    intersection = property(lambda self: self.__and__)
    intersection_update = property(lambda self: self.__iand__)
    issubset = property(lambda self: self.__le__)
    issuperset = property(lambda self: self.__ge__)
    symmetric_difference = property(lambda self: self.__xor__)
    symmetric_difference_update = property(lambda self: self.__ixor__)
    union = property(lambda self: self.__or__)
Quietus answered 31/10, 2009 at 10:17 Comment(14)
@Casebash: yes, one may want to define a class OrderedSet which subclasses OrderedDict and abc.Set and then define __len__, __iter__ and __contains__.Quietus
@Stephan202: Regrettably, the collection ABCs live in collections, but otherwise a good suggestionSinghalese
@kaizer.se: right you are. I now posted an example implementation. Turns out my previous comment was not completely correct, but the posted code should speak for itself.Quietus
This is true, but you do have a lot of wasted space as a result, which leads to suboptimal performance.Bathsheeb
An addition; collections.OrderedDict is also available in python 2.7.Psychophysiology
Doing OrderedSet([1,2,3]) raises a TypeError. How does the constructor even work? Missing usage example.Fossorial
This answer needs to be rewritten to: (1) support initialization using a list of tuple, (2) use dict (since it is now ordered) via composition rather than inheritance, and (3) use collections.abc.MutableSet.Substance
__sub__ etc are not normally defined. Needs to be imported or referenced differently.Jilly
How does this answer have so many upvotes? Did this work in Python 2? As @Jilly wrote, this results in NameError: name '__sub__' is not defined (Python 3.7 and 3.8).Murderous
@Murderous I'm sure it worked back then. I haven't done any serious development in Python for many years now, so can't comment on the current state of this code, sorry.Quietus
@Quietus It still works, there's just some changes since Py2. But this is expected, as this is a bit niche and out of the ordinary development one would do :) Just left a comment to point people in the right direction, don't even remember how I fixed it hehe.Jilly
@Jilly OK, no, this didn’t work, not even in Python 2. Someone recently edited the answer (stackoverflow.com/revisions/1653978/5), which broke the code. I’ve submitted an edit to revert this.Murderous
@Murderous tnx! I approved your edit (minus the dropped empty line; stylistic preference ;) )Quietus
Gotta agree with @Fossorial here, I'm getting a TypeError: 'int' object is not iterable when trying the most basic use-case of OrderedSet([1, 3, 2])Procurator
D
59

Implementations on PyPI

While others have pointed out that there is no built-in implementation of an insertion-order preserving set in Python (yet), I am feeling that this question is missing an answer which states what there is to be found on PyPI.

There are the packages:

Some of these implementations are based on the recipe posted by Raymond Hettinger to ActiveState which is also mentioned in other answers here.

Some differences

  • ordered-set (version 1.1)
  • advantage: O(1) for lookups by index (e.g. my_set[5])
  • oset (version 0.1.3)
  • advantage: O(1) for remove(item)
  • disadvantage: apparently O(n) for lookups by index

Both implementations have O(1) for add(item) and __contains__(item) (item in my_set).

Discontinuance answered 22/4, 2014 at 16:22 Comment(3)
A new contender is collections_extended.setlist. Functions like set.union don't work on it though, even though it inherits collections.abc.Set.Crying
OrderedSet now supports removeOtiliaotina
There is also SortedSet from sortedcontainers 2.3.0 with a bunch of other sorted stuff.Eichelberger
M
53

I can do you one better than an OrderedSet: boltons has a pure-Python, 2/3-compatible IndexedSet type that is not only an ordered set, but also supports indexing (as with lists).

Simply pip install boltons (or copy setutils.py into your codebase), import the IndexedSet and:

>>> from boltons.setutils import IndexedSet
>>> x = IndexedSet(list(range(4)) + list(range(8)))
>>> x
IndexedSet([0, 1, 2, 3, 4, 5, 6, 7])
>>> x - set(range(2))
IndexedSet([2, 3, 4, 5, 6, 7])
>>> x[-1]
7
>>> fcr = IndexedSet('freecreditreport.com')
>>> ''.join(fcr[:fcr.index('.')])
'frecditpo'

Everything is unique and retained in order. Full disclosure: I wrote the IndexedSet, but that also means you can bug me if there are any issues.

Mullin answered 7/2, 2016 at 20:41 Comment(2)
Indexing does not work when negative indexes are supplied. For instance, this s[-4:-1] returns IndexedSet([]) on a very non-empty set.Oneidaoneil
@Oneidaoneil Not sure what version you're on but negative indexes are supported and your supplied case does not reproduce on the issue you opened: github.com/mahmoud/boltons/issues/274Mullin
H
28

If you're using the ordered set to maintain a sorted order, consider using a sorted set implementation from PyPI. The sortedcontainers module provides a SortedSet for just this purpose. Some benefits: pure-Python, fast-as-C implementations, 100% unit test coverage, hours of stress testing.

Installing from PyPI is easy with pip:

pip install sortedcontainers

Note that if you can't pip install, simply pull down the sortedlist.py and sortedset.py files from the open-source repository.

Once installed you can simply:

from sortedcontainers import SortedSet
help(SortedSet)

The sortedcontainers module also maintains a performance comparison with several alternative implementations.

For the comment that asked about Python's bag data type, there's alternatively a SortedList data type which can be used to efficiently implement a bag.

Hallett answered 23/9, 2014 at 6:52 Comment(6)
Note that the SortedSet class there requires members to be comparable and hashable.Wakashan
@Wakashan The builtins set and frozenset also require elements to be hashable. The comparable constraint is the addition for SortedSet, but it's also an obvious constraint.Emersed
As the name suggests, this does not maintain order. It is nothing but sorted(set([sequence])) which makes better?Teets
@Teets I'm not sure which you're referring to but just to be clear, SortedSet as part of Sorted Containers does maintain sorted order.Hallett
@Hallett - It is the difference between whether it maintains insertion order or sort order. Most of the other answers are regarding insertion order. I think you are already aware of this based on your first sentence, but it's probably what ldmtwo is saying.Cascara
This one is available by default on leetcodeNothing
C
17

As other answers mention, as for python 3.7+, the dict is ordered by definition. Instead of subclassing OrderedDict we can subclass abc.collections.MutableSet or typing.MutableSet using the dict's keys to store our values.

import typing

T = typing.TypeVar("T")


class OrderedSet(typing.MutableSet[T]):
    """A set that preserves insertion order by internally using a dict."""

    def __init__(self, iterable: typing.Iterable[T]):
        self._d = dict.fromkeys(iterable)

    def add(self, x: T) -> None:
        self._d[x] = None

    def discard(self, x: T) -> None:
        self._d.pop(x, None)

    def __contains__(self, x: object) -> bool:
        return self._d.__contains__(x)

    def __len__(self) -> int:
        return self._d.__len__()

    def __iter__(self) -> typing.Iterator[T]:
        return self._d.__iter__()

    def __str__(self):
        return f"{{{', '.join(str(i) for i in self)}}}"

    def __repr__(self):
        return f"<OrderedSet {self}>"

Then just:

x = OrderedSet([1, 2, -1, "bar"])
x.add(0)
assert list(x) == [1, 2, -1, "bar", 0]

I added this code, with some tests, in a small library, so anyone can just pip install it.

Coppage answered 26/5, 2020 at 10:9 Comment(2)
Don't use this as-is. discard should never ever raise a KeyError. Also note that this doesn't provide a sensible __repr__Mystagogue
@JasonForbes You are right —in fact we addressed your comments in the linked repo. So I just brought those fixes in this answer. Thank you for pointing it out! :-)Coppage
E
12

In case you're already using pandas in your code, its Index object behaves pretty like an ordered set, as shown in this article.

Examples from the article:

indA = pd.Index([1, 3, 5, 7, 9])
indB = pd.Index([2, 3, 5, 7, 11])

indA & indB  # intersection
indA | indB  # union
indA - indB  # difference
indA ^ indB  # symmetric difference
Ess answered 25/9, 2015 at 14:13 Comment(3)
Can you include an example in this answer? Links tend to be broken after some time.Traveler
for the difference between sets, you actually need to use indA.difference(indB), the minus sign performs standard subtractionHornsby
It's important to note that pd.Index allows for duplicate elements, which one would not expect from an actual Python set.Busch
F
10

A little late to the game, but I've written a class setlist as part of collections-extended that fully implements both Sequence and Set

>>> from collections_extended import setlist
>>> sl = setlist('abracadabra')
>>> sl
setlist(('a', 'b', 'r', 'c', 'd'))
>>> sl[3]
'c'
>>> sl[-1]
'd'
>>> 'r' in sl  # testing for inclusion is fast
True
>>> sl.index('d')  # so is finding the index of an element
4
>>> sl.insert(1, 'd')  # inserting an element already in raises a ValueError
ValueError
>>> sl.index('d')
4

GitHub: https://github.com/mlenzen/collections-extended

Documentation: http://collections-extended.lenzm.net/en/latest/

PyPI: https://pypi.python.org/pypi/collections-extended

Flanch answered 20/1, 2015 at 18:46 Comment(0)
S
10

There's no OrderedSet in official library. I make an exhaustive cheatsheet of all the data structure for your reference.

DataStructure = {
    'Collections': {
        'Map': [
            ('dict', 'OrderDict', 'defaultdict'),
            ('chainmap', 'types.MappingProxyType')
        ],
        'Set': [('set', 'frozenset'), {'multiset': 'collection.Counter'}]
    },
    'Sequence': {
        'Basic': ['list', 'tuple', 'iterator']
    },
    'Algorithm': {
        'Priority': ['heapq', 'queue.PriorityQueue'],
        'Queue': ['queue.Queue', 'multiprocessing.Queue'],
        'Stack': ['collection.deque', 'queue.LifeQueue']
        },
    'text_sequence': ['str', 'byte', 'bytearray']
}
Sephira answered 6/12, 2017 at 10:50 Comment(1)
Some odd things in this cheatsheet: according to collections.abc, Sequences are Collections, not a sibling. And iterator does not support indexing, so shouldn't be on the same group as lists and tuples. Also, all text_sequences are also SequenceAttribution
P
5

As others have said, OrderedDict is a superset of an ordered set in terms of functionality, but if you need a set for interacting with an API and don't need it to be mutable, OrderedDict.keys() is actually an implementation abc.collections.Set:

import random
from collections import OrderedDict, abc

a = list(range(0, 100))
random.shuffle(a)

# True
a == list(OrderedDict((i, 0) for i in a).keys())

# True
isinstance(OrderedDict().keys(), abc.Set)   

The caveats are immutability and having to build up the set like a dict, but it's simple and only uses built-ins.

Proteiform answered 2/9, 2020 at 2:33 Comment(0)
P
2

The ParallelRegression package provides a setList( ) ordered set class that is more method-complete than the options based on the ActiveState recipe. It supports all methods available for lists and most if not all methods available for sets.

Prolific answered 21/1, 2017 at 22:45 Comment(0)
L
0

There is a pip library that does this:

pip install ordered-set

Then you can use it:

from ordered_set import OrderedSet
Lucullus answered 4/4, 2022 at 20:4 Comment(0)
C
0

Just use pd.unique from pandas - does exactly what you need!

>>> import pandas as pd
>>> pd.unique([3, 1, 4, 5, 2, 2])
array([3, 1, 4, 5, 2])
Chorus answered 20/6, 2023 at 16:5 Comment(0)
W
-2

This answer is for completeness sake. If the length of your set is small, and your code is single-threaded, a list could work just fine as it's implicitly ordered.

if not new_item in my_list:
    my_list.append(new_item)

If using this approach:

  • To append or remove an item, first check for presence as in the code above.
  • To compare equality, use set(my_list).

Checking for presence in a list of course has an O(n) complexity, but this could be acceptable for a small list, especially if high performance isn't required.

Wilber answered 16/7, 2018 at 2:40 Comment(2)
The main issue with this approach is that adding runs in O(n). Meaning it gets slower with big lists. Python's built-in sets are very good at making adding elements faster. But for simple use-cases, it certainly does work!Lulalulea
This answer should not be deleted because this approach works acceptably for small lists where the best performance isn't required.Substance
L
-6

For many purposes simply calling sorted will suffice. For example

>>> s = set([0, 1, 2, 99, 4, 40, 3, 20, 24, 100, 60])
>>> sorted(s)
[0, 1, 2, 3, 4, 20, 24, 40, 60, 99, 100]

If you are going to use this repeatedly, there will be overhead incurred by calling the sorted function so you might want to save the resulting list, as long as you're done changing the set. If you need to maintain unique elements and sorted, I agree with the suggestion of using OrderedDict from collections with an arbitrary value such as None.

Luciano answered 20/2, 2013 at 22:52 Comment(1)
The purpose for OrderedSet is to be able to get the items in the order which they where added to the set. You example could maybe called SortedSet...Hube

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