C# Iterate through NameValueCollection
Asked Answered
W

8

87

I have a NameValueCollection, and want to iterate through the values. Currently, I’m doing this, but it seems like there should be a neater way to do it:

NameValueCollection nvc = new NameValueCollection();
nvc.Add("Test", "Val1");
nvc.Add("Test2", "Val1");
nvc.Add("Test2", "Val1");
nvc.Add("Test2", "Val2");
nvc.Add("Test3", "Val1");
nvc.Add("Test4", "Val4");

foreach (string s in nvc)
    foreach (string v in nvc.GetValues(s))
        Console.WriteLine("{0} {1}", s, v);

Console.ReadLine();

Is there?

Wry answered 21/2, 2011 at 12:30 Comment(4)
What's wrong with what you have?Arad
There's nothing wrong with it per se - just that I thought I should be able to iterate using a single loop. Looking at the answers so far, this doesn't seem to be possible if there may be duplicate key values.Wry
that's correct, but you can use different collection e.g. Dictionary<string, List<string>>Faceoff
see also #391523Schilt
D
116

You can flatten the collection with Linq, but it's still a foreach loop but now more implicit.

var items = nvc.AllKeys.SelectMany(nvc.GetValues, (k, v) => new {key = k, value = v});
foreach (var item in items)
    Console.WriteLine("{0} {1}", item.key, item.value);

The first line, converts the nested collection to a (non-nested) collection of anonymous objects with the properties key and value.

It's flatten in the way that it's now a mapping key -> value instead of key -> collection of values. The example data:

Before:

Test -> [Val],

Test2 -> [Val1, Val1, Val2],

Test3 -> [Val1],

Test4 -> [Val4]

After:

Test -> Val,

Test2 -> Val1,

Test2 -> Val1,

Test2 -> Val2,

Test3 -> Val1,

Test4 -> Val4

Disuse answered 21/2, 2011 at 13:29 Comment(8)
Tested and using using System.Linq;Disuse
In case someone wants to know the vb.net syntax: Dim items = nvc.AllKeys.SelectMany(AddressOf col.GetValues, Function(k, v) New With {.key = k, .value = v})Whitehorse
@EndyTjahjono slight typo, change "col" to "nvp" so it becomes Dim items = nvc.AllKeys.SelectMany(AddressOf nvp.GetValues, Function(k, v) New With {.key = k, .value = v})Brumbaugh
Wouldn't v simply refer to the index of the current key?Borrell
What if it's a blank value, how do I just get add string.empty instead?Piton
what is a blank value? null?Disuse
Alternatively: nvc.AllKeys.Select(k => $"{k}={nvc[k]}"). Formats as a key and its comma-separated values.Savoy
This way is too inefficient! using AllKeys, SelectMany, GetValues, Creating new anonym/dynamic object.... too much to just enumerate a simple collection!Cobble
N
98

You can use the key for lookup instead of having two loops:

foreach (string key in nvc)
{
    Console.WriteLine("{0} {1}", key, nvc[key]);
}
Nonplus answered 21/2, 2011 at 12:34 Comment(1)
Note that this will behave differently to the OP's code if there are any keys with multiple values. Your code will output "key value1,value2,value3", whereas the OP's code would output "key value1" then "key value2" then "key value3".Basinet
S
4

Nothing new to see here (@Julian's +1'd by me answer is functionally equivalent), y'all move along y'all please.


I have an [overkill for this case but possibly relevant] set of extension methods in an answer to a related question, which would let you do:

foreach ( KeyValuePair<string,string> item in nvc.AsEnumerable().AsKeyValuePairs() )
    Console.WriteLine("{0} {1}", item.key, item.value);
Schilt answered 3/10, 2012 at 13:13 Comment(3)
NameValueCollection does not have AsEnumerable or as keyValuePairsCompressibility
@Luis Tellez. I know. The text says I have a set of extension methods. And it links to it. And the body text is flagging that there is nothing new to see here please. Does this clarify or do I need to re-explain?Schilt
You can make an enumerable as IEnumerable<KeyValuePair<string,string>> e = nvc.AllKeys.Select(k => new KeyValuePair<string, string>(k, nvc[k])). Another stumbling point brought to you by Microsoft.Savoy
D
2

I think this is simpler: VB.NET

For i As Integer = 0 To nvc.Count - 1
   Console.Write("No", "Key", "Value")
   Console.Write(i, nvc.GetKey(i), nvc.Get(i))
Next

C#:

for (int i = 0; i <= nvc.Count - 1; i++)
{
    Console.Write("No", "Key", "Value");
    Console.Write(i, nvc.GetKey(i), nvc.Get(i));
}
Dail answered 17/12, 2017 at 11:27 Comment(2)
This is the worst C# I've ever seen.Biosphere
Sorry, I think in vb.net! UpdatedDail
K
2
var enu = myNameValueCollection.GetEnumerator();
while (enu.MoveNext())
{
    string key = (string)enu.Current;
    string value = myNameValueCollection[key];
}

OR when keys nullable:

for (int i = 0; i < myNameValueCollection.Count; i++)
{
    string key = myNameValueCollection.GetKey(i);
    string value = myNameValueCollection.Get(i);
}
Kentledge answered 3/6, 2019 at 16:15 Comment(0)
F
1

The only way I found to avoid the nested loops is using additional List to store the values:

List<string> arrValues = new List<string>();
for (int i = 0; i < nvc.Count; i++)
    arrValues.AddRange(nvc.GetValues(i));
foreach (string value in arrValues)
    Console.WriteLine(value);

(Requires [only] .NET 2.0 or later)

Faceoff answered 21/2, 2011 at 12:44 Comment(5)
(obviously superseded by using SelectMany like the other answer)Schilt
@Ruben true, but I prefer to leave this one even if just for historical value showing how to do that with old .NET version. :)Faceoff
The thing with SelectMany i came across is if the key has a value that's blank it fails. Any way around it? Thanks.Piton
@Piton what exactly fails? In theory, just throw an if statement and check for null, though if your code is one-liner, it will make it much less readable.Faceoff
Your method works with the null but the LINQ doesn't is what I was stating... sorry for not clear.Piton
I
0
for (int i = 0; i < nvc.Count; i++) {
    System.Console.WriteLine(

        nvc.AllKeys[i] + " = " + nvc[i]

    );
}
Iniquity answered 16/1, 2021 at 21:11 Comment(0)
B
-2
foreach ( string key in nvc.Keys )
   Console.WriteLine("{0} {1}", key, nvc[key]);

This will return you all keys and corresponding values.

Bushhammer answered 21/2, 2011 at 12:34 Comment(2)
No; it won't return duplicate values.Staghound
Isnt this a dup of https://mcmap.net/q/237565/-c-iterate-through-namevaluecollection which is milliseconds earlier (wow!) - personally I'd delete. @Slaks to be pedantic, it will give the duplicate values, just with commas separating them.Schilt

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