How to define default value if empty user input in Python?

Question

Here I have to set the default value if the user will enter the value from the keyboard. Here is the code that user can enter value:

input = int(raw_input("Enter the inputs : "))

Here the value will be assigned to a variable input after entering the value and hitting Enter. Is there any method that if we don't enter the value and directly hit the Enter key, the variable will be directly assigned to a default value, say as input = 0.025?

Rooky

... and that will fail if the user just hits Enter – Oecd

input is a built-in function in Python, you might wanna use a different variable name... – Chloras

Related but not a duplicate: How to set a default string for raw_input? – Kiwanis

Answer 1

Python 3:

inp = int(input('Enter the inputs: ').strip() or "42")

Python 2:

inp = int(raw_input('Enter the inputs: ').strip() or "42")

How does it work?

If nothing was entered then input/raw_input returns empty string. Empty string in Python is False, bool("") -> False. Operator or returns first truthy value, which in this case is "42".

This is not sophisticated input validation. It's slightly more robust with the addition of .strip(). That handles the possibility of the user entering spaces or other whitespace, which then would be True.

Ninos

Isn't it bad practise to name the variable as 'input'? – Frisbee

It depends on the context, if the message would say "enter how many apples you have", then yes input would be very bad name. – Ninos

@AnchithAcharya, I would agree it's bad practice as input is a built-in function and you would be replacing that function with the output of the statement. In practice it may not be a big deal, but if you needed to ask for input again later in the function you would find it not working as expected as input would now be an int. – Conti

Answer 2

One way is:

default = 0.025
input = raw_input("Enter the inputs : ")
if not input:
   input = default

Another way can be:

input = raw_input("Number: ") or 0.025

Same applies for Python 3, but using input():

ip = input("Ip Address: ") or "127.0.0.1"

Shue

Answer 3

You can do it like this:

>>> try:
        input= int(raw_input("Enter the inputs : "))
    except ValueError:
        input = 0

Enter the inputs : 
>>> input
0
>>> 

Olatha

There are many reasons not to use exceptions for control flow. – Puebla

Answer 4

You can also use click library for that, which provides lots of useful functionality for command-line interfaces:

import click

number = click.prompt("Enter the number", type=float, default=0.025)
print(number)

Examples of input:

Enter the number [0.025]: 
 3  # Entered some number
3.0

or

Enter the number [0.025]: 
    # Pressed enter wihout any input
0.025

Kiwanis

Answer 5

You could first input a string, then check for zero length and valid number:

input_str = raw_input("Ender the number:")

if len(input_str) == 0:
    input_number = DEFAULT
else:
    try:
        input_number = int(input_str)
    except ValueError:
        # handle input error or assign default for invalid input

Julienne

Answer 6

Most of the above answers are correct but for Python 3.7, here is what you can do to set the default value.

user_input = input("is this ok ? - [default:yes] \n")
if len(user_input) == 0 :
    user_input = "yes"

Harriettharrietta

This is the same idea as in Ber's answer. Also, you might wanna change "Python 3.7" to just "Python 3" because input was there before that as well. – Kiwanis

Answer 7

Here is an example to validate user input to be a number and also set default value if he enters nothing.

while True:
    luckyNo = input("Enter your lucky number - [default:108]: ").strip()
    if luckyNo.isdigit(): # check if user entered a number
        luckyNo = int(luckyNo) # convert entered number to integer
        break
    else:  
        if not luckyNo: # user entered nothing
            print("You entered nothing. Using default value...")
            luckyNo = 108 # set default value
            break
        else: # user entered something other than a number
            print("Wrong input!. Try again.")

print("Your lucky number is " + str(luckyNo))

Psilomelane