There's only one type of "if" statement there. The other is a conditional expression. As to which will perform better: they could compile to the same bytecode, and I would expect them to behave identically - or so close that you definitely wouldn't want to choose one over the other in terms of performance.
Sometimes an if
statement will be more readable, sometimes the conditional operator will be more readable. In particular, I would recommend using the conditional operator when the two operands are simple and side-effect-free, whereas if the main purpose of the two branches is their side-effects, I'd probably use an if
statement.
Here's a sample program and bytecode:
public class Test {
public static void main(String[] args) {
int x;
if (args.length > 0) {
x = 1;
} else {
x = 2;
}
}
public static void main2(String[] args) {
int x = (args.length > 0) ? 1 : 2;
}
}
Bytecode decompiled with javap -c Test
:
public class Test extends java.lang.Object {
public Test();
Code:
0: aload_0
1: invokespecial #1
4: return
public static void main(java.lang.String[]
Code:
0: aload_0
1: arraylength
2: ifle 10
5: iconst_1
6: istore_1
7: goto 12
10: iconst_2
11: istore_1
12: return
public static void main2(java.lang.String[
Code:
0: aload_0
1: arraylength
2: ifle 9
5: iconst_1
6: goto 10
9: iconst_2
10: istore_1
11: return
}
As you can see, there is a slight difference in bytecode here - whether the istore_1
occurs within the brance or not (unlike my previous hugely-flawed attempt :) but I would be very surprised if the JITter ended up with different native code.
int x=1; if (!expression) x++;
- no, even better, stop microoptimizations. – Exceptionif
is for use in statements.?
is for use in expressions. – Ripplet? :
because it is more readable and less verbose. – Noninterference