This worked in the first beta of Swift.
var degree = "\u00B0" // degree symbol
Now I'm getting this error and I don't understand what I need to do to correct it in Xcode 6 Beta 5.
Expected hexadecimal code in braces after unicode escape
This worked in the first beta of Swift.
var degree = "\u00B0" // degree symbol
Now I'm getting this error and I don't understand what I need to do to correct it in Xcode 6 Beta 5.
Expected hexadecimal code in braces after unicode escape
The correct code is:
var degree = "\u{00B0}" // degree symbol
From the Xcode 6 beta 4 release notes:
The \x, \u and \U escape sequences in string literals have been consolidated into a single and less error prone \u{123456} syntax. (17279286)
Int
to emojis, hope that helps. –
Communist to use a dynamically generated
extension String {
func hexToDecimal() -> String {
var myValue = self
if self.hasPrefix("0x") || self.hasPrefix("0X") {
let start = self.index(self.startIndex, offsetBy: 2)
myValue = String(self[start...])
}
var sum = 0
for num in myValue.uppercased().utf8 {
sum = sum * 16 + Int(num) - 48
if num >= 65 {
sum -= 7
}
}
return String(sum)
}
}
let unicodeValue = "80" // decimal
// or
let unicodeValue = "0x50".hexToDecimal()
if let uInt8 = UInt8(unicodeValue) {
let scalar = UnicodeScalar(uInt8)
let str = String(scalar)
}
By using these lines of code we can convert hexadecimal text to the according symbol
private func getDecodedUrl(url: String) -> String {
let str: String = url.replacingOccurrences(of: "'\'", with: "\\")
return str
}
let webUrl = NSMutableString( string: self.getDecodedUrl(url: convertedString) )
CFStringTransform( webUrl, nil, "Any-Hex/Java" as NSString, true)
print(webUrl)
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