How to select a single child element using jQuery?
Asked Answered
C

6

92

Using jQuery how do I select a single child element? I've looked at the Traversing API and know I can select all the immediate children img elements like this:

$(this).children('img');

And to select the first child img element I could use a subscript like this:

$(this).children('img')[0];

But I guess I'm kind of surprised I can't do this:

$(this).child('img'); // no subscript, returns single element

Or have I missed something?

Curvet answered 24/9, 2009 at 20:52 Comment(0)
T
53

No. Every jQuery function returns a jQuery object, and that is how it works. This is a crucial part of jQuery's magic.

If you want to access the underlying element, you have three options...

  1. Do not use jQuery
  2. Use [0] to reference it
  3. Extend jQuery to do what you want...

    $.fn.child = function(s) {
        return $(this).children(s)[0];
    }
    
Telford answered 24/9, 2009 at 21:2 Comment(3)
Ah ha! That was it. I was expecting the img element (trying to reference its 'src' property) instead of the jQuery object. Now I'll just use 'attr()' to get at the 'src' property.Curvet
Thanks for 3) as well. I might consider doing that. :)Curvet
No. If I use for example find("div")[0] I will not get div as a jQuery object. I will get div as HTMLElement. To get div as jQuery object one has to use .eq(0), as Greg said below.Sailor
C
136

I think what you want to do is this:

$(this).children('img').eq(0);

this will give you a jquery object containing the first img element, whereas

$(this).children('img')[0];

will give you the img element itself.

Cumshaw answered 24/9, 2009 at 20:57 Comment(2)
Note that using find as in the first answer will give you all descendant elements, whereas child will give you only direct children.Cumshaw
From jquery.com: .children() only travels a single level down the DOM tree while .find() can traverse down multiple levels to select descendant elements (grandchildren, etc.) as well.Circumferential
T
53

No. Every jQuery function returns a jQuery object, and that is how it works. This is a crucial part of jQuery's magic.

If you want to access the underlying element, you have three options...

  1. Do not use jQuery
  2. Use [0] to reference it
  3. Extend jQuery to do what you want...

    $.fn.child = function(s) {
        return $(this).children(s)[0];
    }
    
Telford answered 24/9, 2009 at 21:2 Comment(3)
Ah ha! That was it. I was expecting the img element (trying to reference its 'src' property) instead of the jQuery object. Now I'll just use 'attr()' to get at the 'src' property.Curvet
Thanks for 3) as well. I might consider doing that. :)Curvet
No. If I use for example find("div")[0] I will not get div as a jQuery object. I will get div as HTMLElement. To get div as jQuery object one has to use .eq(0), as Greg said below.Sailor
S
8

Maybe in this way?

$('img', this)[0]
Squish answered 24/9, 2009 at 20:58 Comment(1)
This will not necessarily select the direct child and, just as the accepted answer, this will return the element, not the jQuery object.Carmellacarmelle
P
3

You can target the first child element with just using CSS selector with jQuery:

$(this).children('img:nth-child(1)');

If you want to target the second child element just change 1 to 2:

$(this).children('img:nth-child(2)');

and so on..

if you want to target more elements, you can use a for loop:

for (i = 1; i <= $(this).children().length; i++) {
    let childImg =  $(this).children("img:nth-child("+ i +")");
    // Do stuff...
}
Philemon answered 20/11, 2020 at 23:22 Comment(0)
G
1

Not jQuery, as the question asks for, but natively (i.e., no libraries required) I think the better tool for the job is querySelector to get a single instance of a selector:

let el = document.querySelector('img');
console.log(el);

For all matching instances, use document.querySelectorAll(), or for those within another element you can chain as follows:

// Get some wrapper, with class="parentClassName"
let parentEl = document.querySelector('.parentClassName');
// Get all img tags within the parent element by parentEl variable
let childrenEls = parentEl.querySelectorAll('img');

Note the above is equivalent to:

let childrenEls = document.querySelector('.parentClassName').querySelectorAll('img');
Gingili answered 22/2, 2019 at 9:13 Comment(0)
B
0
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Barthol answered 23/8, 2017 at 14:53 Comment(1)
$(function () { $('a').click(function() { $(this).parent().children('.dataContentSectionMessages').slideToggle(); }); }); this query will help to get the child item of a parentBarthol

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