As ViewModelProviders.of() is deprecated, how should I create object of ViewModel?
Asked Answered
L

14

97

I have been trying to create an Object of ViewModel in an Activity but ViewModelProviders is deprecated So what's the alternative to create the ViewModel's object.

Lainelainey answered 17/8, 2019 at 8:46 Comment(0)
S
161

Simply replace:

This:

boardViewModel = ViewModelProviders.of(this).get(BoardViewModel::class.java)

With this:

boardViewModel = ViewModelProvider(this).get(BoardViewModel::class.java)
Suppository answered 21/10, 2019 at 4:54 Comment(5)
In Java: "boardViewModel = new ViewModelProvider(this).get(BoardViewModel.class)"Martita
boardViewModel = ViewModelProvider(this).get("model", BoardViewModel::class.java) only compile for me in latest versions.Epanodos
For me .get(UserViewModel::class.java) has red underline that is for some reason saying " Type parameter bound for T in operator fun <T : ViewModel!> get ( modelClass: Class<T!> ) : T is not satisfied: inferred type UserViewModel! is not a subtype of ViewModel! ".Trahan
What does this stand for?Broglie
@Broglie The UI controller (activity or fragment) you want to tie to the viewmodel.Backspin
G
54

This Gradle upgrade created the problem for me.

FROM

implementation 'androidx.core:core:1.1.0'

TO

implementation 'androidx.core:core:1.2.0'

IN MAIN ACTIVITY Java/Kotlin Files

This import statement

import androidx.lifecycle.ViewModelProviders

had to be changed to

import androidx.lifecycle.ViewModelProvider

This KOTLIN viewModel statement

viewModel = ViewModelProviders.of(this).get(MainActivityViewModel::class.java)

had to be changed to

viewModel = ViewModelProvider(this).get(MainActivityViewModel::class.java)

and in JAVA

This line of JAVA code

mViewModel = ViewModelProviders.of(this).get(MainActivityViewModel.class);

had to be changed to

mViewModel = new ViewModelProvider(this).get(MainActivityViewModel.class);

and then it all worked for me.

Based on: An outline of the steps that created the problem for me enter image description here

Grimsby answered 17/2, 2020 at 15:17 Comment(3)
this is. by far the most clear and the best answer.Towpath
yeah man! the best solution was this, it really solved my problem here.Ebb
Hey, what about AndroidViewModel which needs Application as constructor argument?Crifasi
C
35

ViewModelProviders.of() has been deprecated. enter image description here

Use ViewModelProvider constructors directly as they now handle the default ViewModelProvider.Factory role.

Java

 mainActivityViewModel = new ViewModelProvider(this).get(MainActivityViewModel.class);

Kotlin

mainActivityViewModel = ViewModelProvider(this).get(MainActivityViewModel::class.java)
Celindaceline answered 28/12, 2019 at 22:17 Comment(1)
This did the trick in my case. Thanks! It's just nice to mention that I had to change some reded this to getViewLifecycleOwner() to avoid warnings.Weise
G
14

Instead of ViewModelProviders we should now use ViewModelProvider constructors and it has three:

public ViewModelProvider(ViewModelStoreOwner owner)
public ViewModelProvider(ViewModelStoreOwner owner, Factory factory)
public ViewModelProvider(ViewModelStore store, Factory factory)

1. If you are not using a ViewModelProvider.Factory to pass additional arguments to your ViewModel, you can use the first one. so:

viewModel = ViewModelProviders.of(this).get(YourViewModel.class);

can be replaced with:

viewModel = new ViewModelProvider(this).get(YourViewModel.class);

AppCompatActivity and different kinds of Fragments are indirect subclasses of ViewModelStoreOwner (see the complete list of its known subclasses here), so you can use them in this constructor.

2. But if you are using a ViewModelProvider.Factory, you should use the second or the third constructors:

viewModel = ViewModelProviders.of(this, viewModelFactory).get(YourViewModel.class);

can be replaced with:

viewModel = new ViewModelProvider(this, viewModelFactory).get(YouViewModel.class);

OR based on the documentation of ViewModelStore:

Use ViewModelStoreOwner.getViewModelStore() to retrieve a ViewModelStore for activities and fragments.

viewModel = new ViewModelProvider(getViewModelStore(), viewModelFactory).get(YourViewModel.class);
Greenling answered 12/3, 2020 at 10:21 Comment(1)
this is the best ansGuinna
G
10

If you're using Kotlin, instead of:

private lateinit var viewModel: EntityGridViewModel

[...]

// Deprecated
viewModel = ViewModelProviders.of(this).get(EntityGridViewModel::class.java)

You can use the nicer:

private val viewModel: EntityGridViewModel by viewModels()
Gap answered 23/8, 2019 at 16:54 Comment(2)
The question is about alternative to what you've proposedSumerlin
how can i pass a factory to the 'viewModels()' delegate ???Erogenous
D
9

ViewModelProviders.of() has been deprecated. You can pass a Fragment or FragmentActivity to the new ViewModelProvider(ViewModelStoreOwner) constructor to achieve the same functionality. (aosp/1009889)

Please click here to see the solution

Deedradeeds answered 19/8, 2019 at 11:13 Comment(0)
T
9

For java:

Simply replace this:

viewModel = ViewModelProviders.of(this).get(YOUR_VIEW_MODEL::class.java)

With this:

viewModel = ViewModelProvider(this).get(YOUR_VIEW_MODEL::class.java)

if you are having your own factory then,

viewModel = 
ViewModelProvider(this,YOUR_FACTORY).get(YOUR_VIEW_MODEL::class.java)

For kotlin: There is a nicer way to do this. you can add the below dependencies in app build.gradle:

//for activity
implementation "androidx.activity:activity-ktx:1.3.0-alpha06"
//for fragment
implementation "androidx.fragment:fragment-ktx:1.3.2"

and then access the viewmodel like below:

private val viewmodel: YOUR_VIEW_MODEL by viewModels()

If you have your own view model factory then,

  private val viewmodel: YOUR_VIEW_MODEL by viewModels { YOUR_VIEW_MODEL_FACTORY }
Toehold answered 9/4, 2021 at 6:7 Comment(0)
S
7

The simple option for the next several months is to stick with stable or beta versions. ViewModelProviders is only deprecated starting with 2.2.0, presently in an alpha03 release.

For when you do move to 2.2.0 or higher of the lifecycle dependencies, your options depend on your language:

  • If you are using Java, use the ViewModelProvider() constructor, passing in your activity or fragment

  • If you are using Kotlin, there is supposed to be a by viewModels() property delegate, though I am not finding it in the source code...

Sexagesimal answered 17/8, 2019 at 11:29 Comment(4)
to use by viewModels() you need to add this dependency implementation 'androidx.fragment:fragment-ktx:1.2.0'Pincus
@Sexagesimal I guess we should use below dependencies to instantiate view model For Fragments implementation 'androidx.fragment:fragment-ktx:x.x.x' For Activities implementation "androidx.activity:activity-ktx:x.x.x"Quack
@VikashKumarTiwari: Yes, I believe that by viewModels() and by activityViewModels() are defined in the fragment-ktx and activity-ktx artifacts.Sexagesimal
@Sexagesimal As per latest release Version 1.2.0 January 22, 2020 by viewModels() and by activityViewModels() are present in below dependency implementation 'androidx.fragment:fragment-ktx:1.2.0' Also, by viewModels() is to be used for viewmodel initialization in both activity and fragment. But by activityViewModels() can only be used in fragment to get parent activity's viewmodel. Moreover, while using implementation "androidx.activity:activity-ktx:x.x.x" We can access by viewModels() only in activity and it will not be accessed in fragment.Quack
C
5

This code works for me

private lateinit var viewModel: MainViewModel
viewModel = ViewModelProvider(this, ViewModelProvider.NewInstanceFactory()).get(MainViewModel::class.java)
Chacma answered 27/7, 2020 at 7:28 Comment(0)
I
4

lifecycle-extensions 2.2.0 version:

implementation "androidx.lifecycle:lifecycle-extensions:2.2.0"

ViewModelProvider with constructor uses

 // With ViewModelFactory   
 val viewModel = ViewModelProvider(this, YourViewModelFactory).get(YourViewModel::class.java)


//Without ViewModelFactory
val viewModel = ViewModelProvider(this).get(YourViewModel::class.java)
Inefficacy answered 17/9, 2022 at 9:56 Comment(0)
U
2

This class is deprecated. Use the constructors for ViewModelProvider directly. here

So instead of using this

ViewModelProviders.of(this).get(MyViewModel.class); - deprecated

Use this one

new ViewModelProvider(this).get(MyViewModel.class); - correct
Urita answered 1/3, 2020 at 8:13 Comment(0)
U
2

As ViewModelProviders got deprecated. You can now use the ViewModelProvider constructor directly. For more details how to use it, check here.

Unprincipled answered 29/4, 2020 at 17:29 Comment(0)
J
0

you can add the below dependencies in app build.gradle:

//for activity
implementation "androidx.activity:activity-ktx:1.2.2"
//for fragment
implementation "androidx.fragment:fragment-ktx:1.3.2"

and then use like below:

private val viewmodel: YOUR_VIEW_MODEL_CLASS_NAME by viewModels()

If you have your own view model factory then,

  private val viewmodel: YOUR_VIEW_MODEL_CLASS_NAME by viewModels { YOUR_VIEW_MODEL_FACTORY }
Jinks answered 9/4, 2021 at 4:12 Comment(0)
I
0
private lateinit var vm: SRViewModel
private lateinit var adapter: StudentRecordsAdapter

Deprecated

vm = ViewModelProviders.of(this)[SRViewModel::class.java]

Use this line of code

vm=  ViewModelProvider(this)[SRViewModel::class.java]
Infeasible answered 13/6, 2022 at 4:53 Comment(0)

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