Using Android getIdentifier()
Asked Answered
V

3

65

I've tried this:

r = Resources.getSystem().getIdentifier("ball_red","drawable","com.Juggle2");
Log.i("FindBall","R = "+r);

And this:

r = Resources.getSystem().getIdentifier("com.Juggle2:drawable/ball_red", null, null);

But 'r' always ends up as zero.

I'm calling this line from inside a helper class that's not an Activity and doesn't extend anything, so I can't simply call getResources(), but I can pass it from my SurfaceView.

Eventually, I want to replace "ball_red" with a variable, but first thing's first. This isn't working.

com.Juggle2 is indeed my package name. drawable is the res folder that it's in, and, the name of the file is indeed ball_red.

R.java says:

        public static final int ball_red=0x7f020027;

So I'm not sure why it isn't working.


So I can't use Resources, I must pass a context, and I'm doing that this way: Inside here:

class Collection extends SurfaceView implements SurfaceHolder.Callback {

I'm making a new instance of my class and passing it getContext() as a parameter.

Valleau answered 18/3, 2013 at 22:32 Comment(2)
As per documentation of Resources.getSystem(): "Return a global shared Resources object that provides access to only system resources (no application resources), and is not configured for the current screen (can not use dimension units, does not change based on orientation, etc)." As answered by @Sajmon, you'll need to pass in a Context instance to your (static) helper method to access application-specific resources.Egret
btw the type aspect is case sensitive, e.g. "strings", "drawable" and not "Strings", or "Drawable"Spinal
B
147

Since you are inside of an activity it is enough to write

int resId = YourActivity.this.getResources().getIdentifier(
    "ball_red",
    "drawable",
    YourActivity.this.getPackageName()
);

or if you're not calling it from an inner class

int resourceID = getResources().getIdentifier(
    "ball_red",
    "drawable",
    getPackageName()
);

Note

getIdentifier() Returns 0 if no such resource was found. (0 is not a valid resource ID.)

Check

Check also in your R.java whether there is a drawable with the name ball_red

e.g.:

public static final class drawable {
        public static final int ball_red = 0x7f020000;
 }

EDIT If you're not in any activity then you must pass a context instead of resources as parameter then do this

int resId = context.getResources().getIdentifier(
    "ball_red",
    "drawable",
    context.getPackageName()
);
Bleeder answered 18/3, 2013 at 22:39 Comment(6)
I'm not calling it from an activity, and I don't have access to getResources(), but I can pass Resources in from a SurfaceView class, so I'll try thatValleau
Yep, the drawable is there.Valleau
@OWiz If you're not in any activity then you must passe a context instead of resources as parameter then do this int resId=context.getResources().getIdentifier("ball_red", "drawable", context.getPackageName());Bleeder
Tried that. Context came up null. InvestigatingValleau
@OWiz try then to passe getApplicationContext(). If there is styl null then there is problem with your app. sO far the context is null, you can not access resources tooBleeder
Okay, so I figured out why it was null, and stopped that, so now it works.Valleau
W
6

For Xamarin users I had the issue where I had added an icon with lower and uppercase letters (e.g. iconVaccine.png ) and was referring to the uppercase name iconVaccine.

Xamarin will allow you to do this (even though you shouldn't), but when the app gets compiled the name are flattened to lower case, so you must refer to the lower case variant as follows:

Image Name: iconVaccine.png

Xamarin reference: iconVaccine (as created in Resource.designer.cs, but will fail)

Correct Reference: iconvaccine

Hope that helps!

Willawillabella answered 26/2, 2016 at 10:17 Comment(0)
G
4

Though the answer from Festus Tamakloe is correct I found a quirk in this function.

If you are declaring a string-array in a xml file it must be accessed by calling the base resource type array, using string-array results in anid 0 return.

Groundsel answered 31/5, 2015 at 18:1 Comment(0)

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