Is JPEG lossless when quality is set to 100?
Asked Answered
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4

101

I understand that JPEG is a lossy compression standard, and that the 'quality' factor controls the degree of compression and thus the amount of data loss.

But when the quality number is set to 100, is the resulting jpeg lossless?

Naval answered 2/11, 2011 at 14:56 Comment(0)
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86

As correctly answered above, using a "typical" JPEG encoder at quality 100 does not give you lossless compression. Lossless JPEG encoding exists, but it's different in nature and seldom used.

I'm just posting to say why quality 100 does not mean lossless.

In JPEG compression information is mostly lost during the DCT coefficient quantization step (8-by-8 coefficient blocks are divided by a 8-by-8 quantization table, so they become smaller --> 'more compressible'). When you set JPEG quality to 100, no real quantization takes place (because the quantization table will be all 1s, at least with standard IJG-JPEG tables), so in fact you don't lose information here..

However, there are mainly two factors leading to information loss even when no quantization takes place:

  1. Typically, JPEG compression reduces color information (becase the human visual system is less senstitive to that than to lumimance). Therefore, even at quality 100 you may be carrying out chrominance subsampling (which means, dropping half or more Cb and Cr coefficients). When this happens, information is lost, even when no quantization happens. However, you can tell the encoder to preserve full chromimance (so called 4:4:4 color sampling).
  2. Nevertheless, JPEG encoding implies going to the DCT domain, which causes rounding of coefficients. Rounding discards some information. This will happen regardless of all other options.
Osteophyte answered 2/2, 2018 at 8:43 Comment(0)
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Jpeg is lossy regardless of the setting. At 100, you just get the LEAST loss possible.

It's easy enough to test. Whip up a simple .bmp, compress that to a q=100 jpeg, then re-extract back to a .bmp. Use Gimp/Photoshop to do a "difference" of the two bitmaps, and you'll see the lossiness - it'll be much less noticeable than on a q=50 or q=1 conversion, but still be present.

Malinda answered 2/11, 2011 at 14:58 Comment(3)
As an alternative, JPEG2000 supports a lossless mode.Hooks
@MarcB, How would you "use Gimp/Photoshop to do a "difference" of the two bitmaps"?Ciera
@Pacerier, with gimp, you open the reference image, then "open as a layer" the second one. From the "layer" toolbox, you can choose the "difference" overlay method. And if you flatten the image as this, and stretch the contrast, et voilà !Aragon
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There is a lossless form of JPEG but it is not widely supported and you do not get it by tweaking the quality setting - it's an entirely different process.

Elasticize answered 7/11, 2011 at 16:57 Comment(3)
So why is it called JPEG?Ciera
@Ciera good question. It's because it was developed by the Joint Photographic Experts Group, the same people that made the original JPEG. I have no idea why they tried to piggyback it on the earlier spec instead of creating a new one as they did with JPEG-2000.Elasticize
Aditionally, the name of the image standard we know as JPEG is actually JFIF. Related: https://mcmap.net/q/212462/-are-all-jpeg-files-jfifEst
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According to wikipedia, No.

jpeg 100 has a compression ratio of 2.6:1. The compression method is usually lossy, meaning that some original image information is lost and cannot be restored, possibly affecting image quality.

There is an optional lossless mode defined in the JPEG standard; however, this mode is not widely supported in products.

Mafia answered 2/11, 2011 at 15:4 Comment(3)
Just because it has a compression ratio does not make it lossy. You can compress with out losing quality... PNG/GIF?Bohlen
The compression method is usually lossy, meaning that some original image information is lost and cannot be restored, possibly affecting image quality. There is an optional lossless mode defined in the JPEG standard; however, this mode is not widely supported in products.Mafia
You should add that to your answer. It is a much better explanation as to why it is lossy - rather than just stating it has a compression ratio :)Bohlen

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